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Questions tagged [anticommutator]

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Canonical Variables in Dirac Spinor Field Theory

In S.Weinberg [QFT V1][1] section 7.1, in eq (7.1.15) and (7.1.16), he states that in order to be consistent with the previous-derived anti-commutator relation, we should take $\psi_{\text{n}}$ and $\...
Ting-Kai Hsu's user avatar
-1 votes
1 answer
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Deriving the equal time anti-commutator of the Dirac fields [closed]

I am trying to solve an exercise on deriving the equal-time anti-commutator of the Dirac fields. But I got stuck somewhere and couldn't get the desired result. I would like to show that $$ \{\psi(x), \...
user174967's user avatar
1 vote
1 answer
42 views

$C$-number ignored in charge conjugation

In Weinberg’s QFT V1, under equation 5.5.58, he says that an anticommutator ($c$-number) can be ignored when we exchange spinors, $\psi$ and $\bar{\psi}$. I cannot fully appreciate why we can ignore ...
Ting-Kai Hsu's user avatar
1 vote
0 answers
61 views

(Anti) Commutation relation of derivative of the fermionic operator

While deriving Semiconductor Bloch equation, I stumbled upon a commutation relation that I have never seen before. It looks like, $$[\alpha_k^{\dagger}\alpha_k, \alpha_{k'}^{\dagger}(\nabla_{k'}\...
sslucifer's user avatar
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1 vote
1 answer
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Does the anticommutator of two spinors affect the transpose of their product?

My lecture notes claim that for an anticommutation relation $$[ \psi_{\mu}(\bf{x},t),{\psi_{{\nu}}^{*}}(\bf{y},t)] = \delta_{\mu \nu} \delta^3(\bf{x}-\bf{y})$$ between two spinors, the transpose of ...
pll04's user avatar
  • 337
2 votes
1 answer
74 views

Product of spinors in Dirac field anticommutators

I am reading a "A modern introduction to quantum field theory" by Maggiore and on page 88 it shows the anticommutators of the Dirac field: $$ \{\psi_a(\vec{x},t),\psi_{b}^{\dagger}(\vec{y},t)...
Andrea's user avatar
  • 613
-1 votes
1 answer
100 views

Confusion about whether a fermion field and its conjugate as an Grassmann number

I'm confused about what "a Grassmann-odd number" really means and how does it apply to fermions. In some text, it says that "if $\varepsilon \eta+\eta \varepsilon =0 $, then $\...
Errorbar's user avatar
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0 answers
56 views

How to generalize the (anti)commutation for spacelike separation to more than $2$ field operators?

Let $\phi_1$ and $\phi_2$ be quantum field operators of certain spin on $\mathbb{R}^4$. Then, the principle of locality dictates that if $x$ and $y$ are space-like separated, we have \begin{equation} \...
Keith's user avatar
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3 votes
2 answers
456 views

Geometry of anticommutation relations

I am asking this question as a mathematician trying to understand quantum theory, so please forgive my naivety. Systems satisfying the canonical commutation relations are naturally modeled with ...
Cole Comfort's user avatar
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1 answer
111 views

Quantization of an Interacting Field Theory

The procedure to quantize free field theories is imposing a commutation/anticommutation relation with the field and its conjugate momentum, as $$\mathcal L = i\bar\psi\gamma^\mu\partial_\mu\psi\...
vfigueira's user avatar
3 votes
2 answers
212 views

Why does $[Q,P]=i\hbar$ work for fermion? Shouldn't fermion satisfy anticommuting relation?

For hydrogen, we use $[Q,P]=i\hbar$ for electron, which is a fermion. Does it have a deeper reason such as that we're really considering the proton + electron system, which might be of bosonic nature?
Bababeluma's user avatar
4 votes
1 answer
215 views

Why is commutation bracket used instead of anti-commutation bracket on page 61 of Peskin QFT?

Peskin&Schroeder was performing a trick where they used $$J_za^{s\dagger}_0|0\rangle=[J_z,a^{s\dagger}_0]|0\rangle\tag{p.61}$$ and claimed that the only non-zero term in this commutator would be ...
Rescy_'s user avatar
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1 answer
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Help with commutator algebra with fermionic operators

I am struggling to understand how the following is true for the fermionic creation/annihilation operators $a^\dagger, a$: $$[a^\dagger a, a]=-a$$ If someone could walk me through the math derivation ...
photonica's user avatar
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The renormalized fermionic operators do not anti-commute?

Let's say we have fermionic operators $a$ and $b$ (which anti-commute). In the context of a renormalization scheme (I am thinking specifically of Wilson's NRG, but it could be DMRG) I have a matrix $P$...
Qwertuy's user avatar
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4 votes
1 answer
145 views

Anticommutation relations for Dirac field at non-equal times

I'm reading this paper by Alfredo Iorio and I have a doubt concerning the anticommutation relations he uses for the Dirac field. Around eq. (2.25), he wants to find the unitary operator $U$ that ...
AFG's user avatar
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1 answer
125 views

Why do we only consider commutators and anticommutators in QFT?

While studying canonical quantization in QFT, I observed that we quantize fields either by a commutation or an anticommutation relation \begin{equation} [\phi(x), \phi(y)]_\pm := \phi(x) \phi(y) \pm \...
Ishan Deo's user avatar
  • 1,588
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0 answers
86 views

Relationship between anti-commutators and correlation

Ballentine (in his solution at the back of the book to his Problem 8.10) writes that $$[Tr(\rho \{A,B\}/2)]^2$$ is related to the correlation between the observables represented by $A,B$, but gives no ...
EE18's user avatar
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1 vote
1 answer
66 views

Anticommutator Relation of Quantized Fermionic Field and Fermi–Dirac statistics: How are these related?

I'm reading the Wikipedia article about Fermionic field and have some troubles to understand the meaning following phrase: We impose an anticommutator relation (as opposed to a commutation relation ...
user267839's user avatar
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2 votes
0 answers
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Can Exceptional Jordan Quantum mechanics model field theory?

Exceptional Jordan Quantum mechanics is an interesting case in which observables are modelled with $3\times3$ Hermitian octonion matrices $\mathbb{J}_3(\mathbb{O})$. There is the Jordan product $A\...
user avatar
0 votes
1 answer
79 views

What is the motivation for the Self-Dual Canonical Anticommutation Relation (CAR) algebra?

What exactly is the motivation for the use of the Self-Dual Canonical Anticommutation Relation (CAR) algebra in the context of infinite lattice systems? Why not remain with the CAR algebra, as both ...
TheDawg's user avatar
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2 votes
1 answer
70 views

Why can the commutator of a general expression be replaced by the anti-commutator in the $bc$ CFT theory?

Polchinski states in his equation 2.6.14 (in his book String Theory Vol. 1, Introduction to the Bosonic String) that for charges $Q_1$ and $Q_2$ the following equation holds, where $j_i$ is the ...
kalle's user avatar
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1 vote
0 answers
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Commutation of kinetic energy operator with Hamiltonian

I am basically trying to calculate current energy operator $\hat{\mathbf{J}}_E(\mathbf{r})$ by using Heisenberg equation of motion as $$ -\nabla\cdot \hat{\mathbf{J}}_E(\mathbf{r})=\frac{i}{\hbar}[H,\...
Sana Ullah's user avatar
1 vote
1 answer
312 views

Anti-commutator of angular momentum operators for arbitrary spin

I know the commutator of angular momentum operators are $$ [J_i,J_j]=\mathrm i\hbar \varepsilon_{ijk}J_k. $$ For spin-1/2 particles, $J_i=\frac\hbar2\sigma_i$ where $\sigma_i$ are Pauli matrices, and ...
Luessiaw's user avatar
  • 695
3 votes
1 answer
98 views

Contour integral for commutator of fermionic fields

Suppose we have primary fields $A$ and $B$ which have the OPE, $$A(z) B(w) = \frac{1}{z-w} = -B(z)A(w), \quad |z| > |w|,\tag{1}$$ so they have fermionic statistics. Now I was curious how this would ...
user2062542's user avatar
2 votes
0 answers
123 views

About the Hilbert space that carries the representation of $\{\psi (x), \bar{\psi (y) }\}=i\delta (x-y) $?

What is this Hilbert space? Is it the complex Hilbert space of wavefunctionals spanned by using the spinor-field configurations as the basis vectors? I know that the wavefunctional space carries a ...
Ryder Rude's user avatar
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Dirac spinor field anti-commutation

I am thinking the anti-commutation property of Dirac field! First, note that the equal time anti-commutation relation (from P&S's QFT): $$\{ \psi_a(\mathbf{x}),\psi_b^{\dagger}(\mathbf{y}) \}=\...
Daren's user avatar
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3 votes
1 answer
128 views

Can Hadamard's formula be used for fermionic operators?

Can I use this special case of Hadamard's formula $$e^\hat B \hat A e^{-\hat B}= A + [B,A]+\frac{1}{2!}[B, [B,A]] + \dots$$ for fermionic operators? Suppose I have fermionic operators that obey ...
C-Roux's user avatar
  • 179
1 vote
0 answers
18 views

Adding a surface term to Dirac action modifies the canonical anticommutation relations [duplicate]

I'm dealing with the following issue: when describing a fermionic field, one can use the typical Dirac Lagrangian $$\mathcal{L}=\bar\psi(i\gamma^\mu\partial_\mu-m)\psi,\tag{1}$$ or the more symmetric ...
TopoLynch's user avatar
  • 503
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0 answers
63 views

Why do fermions anti-commute in Ising model?

In my course fermions are given like a product of spin and (dual to spin) disorder parameter in 2D Ising square lattice. Then, using the properties of disorder parameter I can prove that fermions ...
Aslan Monahov's user avatar
1 vote
0 answers
72 views

Where do arbitrary phases of wavefunctions go under second-quantization?

As far as I understand, a second-quantized operator in QFT or condensed matter represents a many-body wavefunction (symmetrized for bosons or antisymmetrized for fermions). But every wavefunction is ...
boojumAndSnark's user avatar

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