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-1 votes
1 answer
24 views

Deriving the equal time anti-commutator of the Dirac fields [closed]

I am trying to solve an exercise on deriving the equal-time anti-commutator of the Dirac fields. But I got stuck somewhere and couldn't get the desired result. I would like to show that $$ \{\psi(x), \...
user174967's user avatar
1 vote
0 answers
61 views

(Anti) Commutation relation of derivative of the fermionic operator

While deriving Semiconductor Bloch equation, I stumbled upon a commutation relation that I have never seen before. It looks like, $$[\alpha_k^{\dagger}\alpha_k, \alpha_{k'}^{\dagger}(\nabla_{k'}\...
sslucifer's user avatar
  • 1,007
0 votes
1 answer
88 views

Help with commutator algebra with fermionic operators

I am struggling to understand how the following is true for the fermionic creation/annihilation operators $a^\dagger, a$: $$[a^\dagger a, a]=-a$$ If someone could walk me through the math derivation ...
photonica's user avatar
  • 101
2 votes
1 answer
357 views

Proof involving exponential of anticommuting operators

Problem: On page 23 of the book "Quarks, gluons and lattices" by Creutz, he defines a state $$\langle\psi|=\langle 0|e^{bFc}e^{\lambda b^\dagger G c^\dagger}$$ where $\lambda$ is a number, $...
TheQuantumMan's user avatar
0 votes
1 answer
260 views

How to express the anti-commutator in the form of a density operator?

$ \newcommand{\ket}[1]{|{#1}\rangle} \newcommand{\bra}[1]{\langle{#1}|} \newcommand{\braket}[2]{\langle{#1}|{#2}\rangle} \newcommand{\acomm}[2]{\left\{#1,#2\right\}} $Let $\{ \ket{1} \ket{1} \ket{2} .....
Consideration's user avatar
0 votes
1 answer
607 views

Creation and annihilation operators for fermions from anticommutator

In a question, I was given that $a^{\dagger}a + a a^{\dagger} =1$ and asked to show what $a|n\rangle$ and $a^{\dagger}|n\rangle$ would be, given that $H|n\rangle=(a^{\dagger}a + 1/2)$. I am getting ...
anon.jpg's user avatar
  • 182
1 vote
1 answer
128 views

Chiral Symmetry and Charge Algebra

I'm following Section 5.1 in Cheng and Li's Particle Physics book and I am having trouble reproducing some of the commutation relations. The axial current is given by $$ (J_A^a)^\mu = \bar{\psi}_\...
MarcosMFlores's user avatar
0 votes
1 answer
110 views

Dirac spinor and field quantization

Can we simplify $$ Σ_s Σ_r [b_p^s u^s(p)\mathrm e^{ipx} (b_q^r)^†(u^r)^†(q)\mathrm e^{-iqy} + (b_q^r)^†(u^r)^†(q)\mathrm e^{-iqy} b_p^s u^s(p)\mathrm e^{ipx}]\tag{1}$$ as $$Σ_sΣ_r[ \{b_p^s, (b_q^r)^†...
Sakh10's user avatar
  • 369
0 votes
1 answer
143 views

How to prove the following identity of fermion creation and annihilation operators [closed]

Define $$M_{\theta} \equiv \exp\left[\theta \sum_s \left(d^{\dagger}(\vec{p},s)b(\vec{p},s) -b^{\dagger}(\vec{p},s)d(\vec{p},s)\right)\right],$$ where $\theta$ is a continuous real parameter. Show via ...
lol's user avatar
  • 503
0 votes
1 answer
532 views

Proving identity $\mathrm{Tr}[\gamma^{\mu}\gamma^{\nu}] = 4 \eta^{\mu\nu}$

In the lecture notes accompanying a course I'm following, it is stated that $$\DeclareMathOperator{\Tr}{Tr} \Tr\left[\gamma^{\mu}\gamma^{\nu}\right] = 4 \eta^{\mu\nu} $$ Yet when I try to prove this,...
Spurious Eigenstate's user avatar
0 votes
0 answers
223 views

Anticommutation relation for the exponential field of the bosonic field

In 1+1 dimensions, the massless KG equation has the general solution $$\phi(x,t)=\int_{-\infty}^{\infty}dp/(4\pi E_p)[a_pe^{i(px-E_pt)}+a^{\dagger}_pe^{-i(px-E_pt)}]$$ where $E_p^2=p^2$. The operator ...
Keith's user avatar
  • 1,669
-1 votes
1 answer
181 views

Anti-commutative Hermitian operators in an infinite dimensional Hilbert space

An example of a pair of anti-commutative Hermitian operators in a finite Hilbert space is $\sigma_x$ with $\sigma_z.$ Indeed $\sigma_z\sigma_x=i\sigma_y$, whereas $\sigma_x\sigma_z=-i\sigma_y$. My ...
Henry's user avatar
  • 13
5 votes
2 answers
37k views

Properties of anticommutators [closed]

Do anticommutators of operators has simple relations like commutators. For example: $$[AB,C]=A[B,C]-[C,A]B.$$ But I don't find any properties on anticommutators. Do same kind of relations exists ...
StarBucK's user avatar
  • 1,450
4 votes
1 answer
7k views

Confusion about slash notation

I am confused about the slash notation and especially taking the square of a slashed operator. Defining $\displaystyle{\not} a \, = \, \gamma^\mu a_\mu$ we have $\,\,$ $\displaystyle{\not} a \...
RenatoRenatoRenato's user avatar
0 votes
1 answer
932 views

Fermion anti-commutation relations

The fermion anti-commutation relations are given as $$\{\psi_{\alpha}({\bf x},t),\psi_{\beta}^{\dagger}{(\bf x'},t)\} = \delta_{\alpha,\beta} \, \delta({\bf x} - {\bf x'}).$$ I am interested in ...
jim's user avatar
  • 3,856

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