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0 votes
1 answer
79 views

What is the motivation for the Self-Dual Canonical Anticommutation Relation (CAR) algebra?

What exactly is the motivation for the use of the Self-Dual Canonical Anticommutation Relation (CAR) algebra in the context of infinite lattice systems? Why not remain with the CAR algebra, as both ...
TheDawg's user avatar
  • 71
1 vote
1 answer
78 views

Finding chiral-symmetric degenerate states numerically

I am dealing with a Chiral-symmetric Hamiltonian such that $$ 𝑆𝐻𝑆^{βˆ’1}=βˆ’π». $$ Two of its eigenstates have zero eigenvalue and fulfill $π‘†βˆ£πœ“_{\alpha}⟩=𝑒^{π‘–πœ™_{\alpha}}βˆ£πœ“_{\alpha}⟩$, while the ...
Carlos Ortega Taberner's user avatar
6 votes
2 answers
2k views

Why must the Bogoliubov transform preserve anticommutation relations?

$\mathbf{Background}$: In my research I am studying the Ising model, expressed in terms of Jordan-Wigner fermions: $$ H = \sum_{j=1}^n(c_j - c_j^\dagger)(c_{j+1} + c_{j+1}^\dagger) + \lambda c_jc_j^\...
Zxv's user avatar
  • 101
10 votes
2 answers
2k views

Why do we use the anticommutation relation for particle-hole and chiral symmetries?

In physics we say that a quantity is conserved, if its operator commutes with Hamiltonian. For example, in condensed matter systems, when the momentum $k$ commutes with the Hamiltonian $H$ as $[H,k]=...
079's user avatar
  • 343
4 votes
2 answers
2k views

Anticommutatorrelation in Bogoliubov-de Gennes Hamiltonian

I almost solved the problem Equivalence of Bogoliubov-de Gennes Hamiltonian for nanowire. In the next steps I used the notation by arXiv:0707.1692: $$ \Psi^{\dagger} = \left(\left(\psi_{\uparrow}^{\...
user avatar
5 votes
2 answers
2k views

Imposing anti-commutation relations on fermionic quasi-particles

In many theories of CMT, we assume the nature of quasi-particles (without giving proper justifications). For example, we assume nature of quasi-particles to be fermionic in case of a interacting ...
cleanplay's user avatar
  • 1,475