Skip to main content

All Questions

1 vote
0 answers
61 views

(Anti) Commutation relation of derivative of the fermionic operator

While deriving Semiconductor Bloch equation, I stumbled upon a commutation relation that I have never seen before. It looks like, $$[\alpha_k^{\dagger}\alpha_k, \alpha_{k'}^{\dagger}(\nabla_{k'}\...
sslucifer's user avatar
  • 1,007
3 votes
2 answers
212 views

Why does $[Q,P]=i\hbar$ work for fermion? Shouldn't fermion satisfy anticommuting relation?

For hydrogen, we use $[Q,P]=i\hbar$ for electron, which is a fermion. Does it have a deeper reason such as that we're really considering the proton + electron system, which might be of bosonic nature?
Bababeluma's user avatar
0 votes
1 answer
88 views

Help with commutator algebra with fermionic operators

I am struggling to understand how the following is true for the fermionic creation/annihilation operators $a^\dagger, a$: $$[a^\dagger a, a]=-a$$ If someone could walk me through the math derivation ...
photonica's user avatar
  • 101
0 votes
0 answers
86 views

Relationship between anti-commutators and correlation

Ballentine (in his solution at the back of the book to his Problem 8.10) writes that $$[Tr(\rho \{A,B\}/2)]^2$$ is related to the correlation between the observables represented by $A,B$, but gives no ...
EE18's user avatar
  • 1,095
2 votes
0 answers
68 views

Can Exceptional Jordan Quantum mechanics model field theory?

Exceptional Jordan Quantum mechanics is an interesting case in which observables are modelled with $3\times3$ Hermitian octonion matrices $\mathbb{J}_3(\mathbb{O})$. There is the Jordan product $A\...
user avatar
1 vote
0 answers
238 views

Commutation of kinetic energy operator with Hamiltonian

I am basically trying to calculate current energy operator $\hat{\mathbf{J}}_E(\mathbf{r})$ by using Heisenberg equation of motion as $$ -\nabla\cdot \hat{\mathbf{J}}_E(\mathbf{r})=\frac{i}{\hbar}[H,\...
Sana Ullah's user avatar
3 votes
1 answer
128 views

Can Hadamard's formula be used for fermionic operators?

Can I use this special case of Hadamard's formula $$e^\hat B \hat A e^{-\hat B}= A + [B,A]+\frac{1}{2!}[B, [B,A]] + \dots$$ for fermionic operators? Suppose I have fermionic operators that obey ...
C-Roux's user avatar
  • 179
0 votes
1 answer
76 views

Anticommutation and Bogoliubove transformation

I am given the following transformation: \begin{equation} \begin{bmatrix} ...
user17004502's user avatar
0 votes
0 answers
35 views

What is the physical meaning of the anticommutator of two observables? [duplicate]

It is quite clear to me that when two operators commute it implies that two different observables associated with the respective operators can be measured simultaneously with the exact accuracy. But ...
Mital katariya's user avatar
1 vote
0 answers
57 views

From Fermions to CAR

I do not understand why Fermions statistic is equivalent to the CAR. In other words, suppose we have $\{a_i\}_i$ set of Fermionic operators acting on an Hilbert space, they satisfy the Canonical ...
Ehub's user avatar
  • 43
2 votes
1 answer
207 views

Are there any 3 or more Hermitian solutions to the problem: $\alpha_i^2=1$, $\{\alpha_i, \alpha_j \}=2$

I’m trying to generate some matrices which are similar to Pauli’s but with the following anti-commutation relation $$\{\alpha_i, \alpha_j\}=\alpha_i \alpha_j + \alpha_j \alpha_i = 2 \tag{1}$$ And $$\...
J. Manuel's user avatar
  • 2,241
0 votes
0 answers
168 views

Commuting but not anti-commuting operators

Two Hermitian operators $\hat{A}$ and $\hat{B}$ are such that they commute but don't anti-commute. In this case, even they commute their uncertainty product will not be zero, is it right?
Snpr_Physics's user avatar
4 votes
0 answers
270 views

Defining particles by their commutation/anti-commutation relations

In my studies of many-body physics, I have encountered three types of particles, which can be defined based on their commutation/anti-commutation relations. Fermions, defined by raising/lowering ...
Solarflare0's user avatar
3 votes
1 answer
279 views

Why is the anticommutator of the uncertainty principle omitted if it serves to increase the accuracy of our "knowledge" of a quantum state?

The generalized uncertainty principle can be derived and shown to be this which is fine and rigorous. $\langle ( \Delta A )^{2} \rangle \langle ( \Delta B )^{2} \rangle \geq \dfrac{1}{4} \vert \langle ...
cheekylittleduck's user avatar
0 votes
1 answer
607 views

Creation and annihilation operators for fermions from anticommutator

In a question, I was given that $a^{\dagger}a + a a^{\dagger} =1$ and asked to show what $a|n\rangle$ and $a^{\dagger}|n\rangle$ would be, given that $H|n\rangle=(a^{\dagger}a + 1/2)$. I am getting ...
anon.jpg's user avatar
  • 182

15 30 50 per page