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Canonical Variables in Dirac Spinor Field Theory

In S.Weinberg [QFT V1][1] section 7.1, in eq (7.1.15) and (7.1.16), he states that in order to be consistent with the previous-derived anti-commutator relation, we should take $\psi_{\text{n}}$ and $\...
Ting-Kai Hsu's user avatar
1 vote
0 answers
61 views

(Anti) Commutation relation of derivative of the fermionic operator

While deriving Semiconductor Bloch equation, I stumbled upon a commutation relation that I have never seen before. It looks like, $$[\alpha_k^{\dagger}\alpha_k, \alpha_{k'}^{\dagger}(\nabla_{k'}\...
sslucifer's user avatar
  • 1,007
2 votes
1 answer
74 views

Product of spinors in Dirac field anticommutators

I am reading a "A modern introduction to quantum field theory" by Maggiore and on page 88 it shows the anticommutators of the Dirac field: $$ \{\psi_a(\vec{x},t),\psi_{b}^{\dagger}(\vec{y},t)...
Andrea's user avatar
  • 613
-1 votes
1 answer
100 views

Confusion about whether a fermion field and its conjugate as an Grassmann number

I'm confused about what "a Grassmann-odd number" really means and how does it apply to fermions. In some text, it says that "if $\varepsilon \eta+\eta \varepsilon =0 $, then $\...
Errorbar's user avatar
  • 368
3 votes
2 answers
456 views

Geometry of anticommutation relations

I am asking this question as a mathematician trying to understand quantum theory, so please forgive my naivety. Systems satisfying the canonical commutation relations are naturally modeled with ...
Cole Comfort's user avatar
3 votes
2 answers
212 views

Why does $[Q,P]=i\hbar$ work for fermion? Shouldn't fermion satisfy anticommuting relation?

For hydrogen, we use $[Q,P]=i\hbar$ for electron, which is a fermion. Does it have a deeper reason such as that we're really considering the proton + electron system, which might be of bosonic nature?
Bababeluma's user avatar
4 votes
1 answer
215 views

Why is commutation bracket used instead of anti-commutation bracket on page 61 of Peskin QFT?

Peskin&Schroeder was performing a trick where they used $$J_za^{s\dagger}_0|0\rangle=[J_z,a^{s\dagger}_0]|0\rangle\tag{p.61}$$ and claimed that the only non-zero term in this commutator would be ...
Rescy_'s user avatar
  • 838
0 votes
1 answer
88 views

Help with commutator algebra with fermionic operators

I am struggling to understand how the following is true for the fermionic creation/annihilation operators $a^\dagger, a$: $$[a^\dagger a, a]=-a$$ If someone could walk me through the math derivation ...
photonica's user avatar
  • 101
0 votes
0 answers
49 views

The renormalized fermionic operators do not anti-commute?

Let's say we have fermionic operators $a$ and $b$ (which anti-commute). In the context of a renormalization scheme (I am thinking specifically of Wilson's NRG, but it could be DMRG) I have a matrix $P$...
Qwertuy's user avatar
  • 1,262
4 votes
1 answer
145 views

Anticommutation relations for Dirac field at non-equal times

I'm reading this paper by Alfredo Iorio and I have a doubt concerning the anticommutation relations he uses for the Dirac field. Around eq. (2.25), he wants to find the unitary operator $U$ that ...
AFG's user avatar
  • 2,284
0 votes
1 answer
125 views

Why do we only consider commutators and anticommutators in QFT?

While studying canonical quantization in QFT, I observed that we quantize fields either by a commutation or an anticommutation relation \begin{equation} [\phi(x), \phi(y)]_\pm := \phi(x) \phi(y) \pm \...
Ishan Deo's user avatar
  • 1,588
1 vote
1 answer
66 views

Anticommutator Relation of Quantized Fermionic Field and Fermi–Dirac statistics: How are these related?

I'm reading the Wikipedia article about Fermionic field and have some troubles to understand the meaning following phrase: We impose an anticommutator relation (as opposed to a commutation relation ...
user267839's user avatar
  • 1,395
3 votes
1 answer
98 views

Contour integral for commutator of fermionic fields

Suppose we have primary fields $A$ and $B$ which have the OPE, $$A(z) B(w) = \frac{1}{z-w} = -B(z)A(w), \quad |z| > |w|,\tag{1}$$ so they have fermionic statistics. Now I was curious how this would ...
user2062542's user avatar
3 votes
1 answer
128 views

Can Hadamard's formula be used for fermionic operators?

Can I use this special case of Hadamard's formula $$e^\hat B \hat A e^{-\hat B}= A + [B,A]+\frac{1}{2!}[B, [B,A]] + \dots$$ for fermionic operators? Suppose I have fermionic operators that obey ...
C-Roux's user avatar
  • 179
1 vote
0 answers
18 views

Adding a surface term to Dirac action modifies the canonical anticommutation relations [duplicate]

I'm dealing with the following issue: when describing a fermionic field, one can use the typical Dirac Lagrangian $$\mathcal{L}=\bar\psi(i\gamma^\mu\partial_\mu-m)\psi,\tag{1}$$ or the more symmetric ...
TopoLynch's user avatar
  • 503

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