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Questions tagged [cubics]

This tag is for questions relating to cubic equations, these are polynomials with $~3^{rd}~$ power terms as the highest order terms.

3 votes
4 answers
256 views

Prove irreducible cubic polynomial over $\mathbb{Q}$ with a cyclic galois group has real roots

I want to prove the following: Let $f\in \mathbb{Q}[x]$ be an irreducible cubic polynomial, whose Galois group is cyclic. Prove that all of the roots of $f$ are real. I know that the Galois group $G$...
Ariel Yael's user avatar
0 votes
0 answers
24 views

Let a, b, c, d be complex numbers satisfying $a+b+c+d=a^3+b^3+c^3+d^3=0$. Prove that a pair of the a, b, c, d must add up to 0 [duplicate]

When doing this I tried using the identity $x^3+y^3+z^3=3xyz$ if $x+y+z=0$ I take $x=a$, $y=b$, and $z=c+d$ So $a+b+(c+d)=0$ $a^3+b^3+(c+d)^3=3ab(c+d)$ $a^3+b^3+c^3+d^3+3cd(c+d)=3ab(c+d)$ $(a^3+b^3+c^...
Namura's user avatar
  • 123
0 votes
0 answers
125 views

Can I use this algorithm for solving cubic equations?

I am trying to find the root solutions for a cubic equation including the eigenvalues of each root. I tried to put the equation into my calcualtor but the calculator doesn't show solutions that has ...
Ryan's user avatar
  • 1
2 votes
2 answers
100 views

Convert an expression with radicals into simpler form

It was pointed out in a mathologer video on the cubic formula that $\sqrt[3]{20 + \sqrt{392}} + \sqrt[3]{20 - \sqrt{392}}$ is actually equal to $4$. Is there a series of transformations that can be ...
Neeraj's user avatar
  • 23
1 vote
1 answer
108 views

Solving a cubic using triple angle for cos (i.e $\cos(3A)$)

a) Show that $x=2\sqrt{2}\cos(A)$ satisfies the cubic equation $x^3 - 6x = -2$ provided that $\cos(3A)$ = $\frac{-1}{2\sqrt{2}}$ I did not have a difficulty with this question, I have provided it for ...
Mikhael's user avatar
  • 15
1 vote
1 answer
203 views

How do I find a cubic equation given only one root?

Given the root of a cubic equation $Z = \sqrt[3]{Y + \sqrt{Y^2 - \frac{X^6}{27}}} + \sqrt[3]{Y - \sqrt{Y^2 - \frac{X^6}{27}}} - X$ and the assumption that both $X$ and $Y$ are greater than zero, is ...
Lawton's user avatar
  • 1,861
1 vote
1 answer
76 views

Best way to solve $\frac{x^3+3}{x^2+1}>\frac{x^3-3}{x^2-1}$

I was wondering what the best way to solve questions like these are? $$\frac{x^3+3}{x^2+1}>\frac{x^3-3}{x^2-1}$$ I can get the answer, which is $(-\infty,-1)\cup(1,3)$. But I'm not sure if I have ...
basket_case's user avatar
3 votes
3 answers
165 views

Is there any faster way to factor $x^3-3x+2$?

$$x^3-3x+2$$ $$x^3-3x+x^2+2-x^2$$ $$x^2-3x+2+x^3-x^2$$ $$(x-2)(x-1)+x^2(x-1)$$ $$(x-1)[x^2+x-2]$$ $$(x-1)(x+2)(x-1)$$ Is there a better, faster way to factor this cubic trinomial?
SirMrpirateroberts's user avatar
2 votes
1 answer
79 views

Classification of curves passing through 7 points. (Hartshorne III ex 10.7)

This is the exercise III 10.7 in Hartshorne's Algebraic Geometry I am not sure if I misunderstood the question. The seven points of the projective plane over $\mathbb{F}_2$, I think, means $\{[x_0,...
Xiong Jiangnan's user avatar
2 votes
1 answer
69 views

Prove $\lim_{n\to\infty}\int_0^{a} \left(\sqrt{2n/\pi-x^2}-\sqrt{2n/\pi-a^2}\right)dx=1/6$ where $a$ is the largest real root of $4x^6+x^2=2n/\pi$.

I've never seen anything like this before: an unsolvable cubic, within a definite integral, within a limit (which applies to the cubic and the integral), resulting in a simple closed form. Prove $\...
Dan's user avatar
  • 25.7k
2 votes
2 answers
134 views

Condition for the existence of positive solution to cubic equation

In a physics textbook I have encountered a cubic equation of the form: $$Ax^3-Bx+C=0$$ The book states that there exists a positive solution $x>0$ to this equation if and only if the following ...
Wild Feather's user avatar
1 vote
2 answers
569 views

Find sum of all integral values of $r$ such that all roots of the equation $x^3-(r-1)x^2-11x+4r=0$ are also integers

Find sum of all integral values of $r$ such that all roots of the equation $$x^3-(r-1)x^2-11x+4r=0$$ are also integers. What I could do was $$r=\frac{x^3+x^2-11x}{x^2-4}=x+1+\frac{4-7x}{x^2-4}$$ Since ...
Maverick's user avatar
  • 9,599
3 votes
6 answers
406 views

Find all real numbers $a$ for equation $x^3 + ax^2 + 51x + 2023=0$, has two equal roots.

Problem: Find all real numbers $a$ for which the equation, $x^3 + ax^2 + 51x + 2023=0$, has two equal roots. This problem is from an algebra round of a local high school math competition that has ...
JHumpdos's user avatar
  • 167
4 votes
1 answer
259 views

Why doesn't simultaneous equations work to find co-efficients of a cubic that passes through four points?

I'm trying to find the equation of a cubic that passes through three specific points (technically it's four but that point is y-intercept). The equation would look something like this:$f(x)=ax^3+bx^2+...
sirOrange17's user avatar
1 vote
0 answers
50 views

Order $3$ linear transforms invariating a binary cubic form

Consider $P(x,y)$ a homogenous polynomial of degree $3$ in two variables (a binary cubic). To it we associate first the $2\times 2$ matrix $$\frac{1}{2}\operatorname{Hess}(P) = \frac{1}{2}\cdot\left( ...
orangeskid's user avatar

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