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12 votes
7 answers
5k views

Why do cubic equations always have at least one real root, and why was it needed to introduce complex numbers?

I am studying the history of complex numbers, and I don't understand the part on the screenshots. In particular, I don't understand why a cubic always has at least one real root. I don't see why the ...
Tereza Tizkova's user avatar
3 votes
1 answer
109 views

Simplifying Coefficients of a Cubic Polynomial with Complex Roots

I am currently encountering difficulties while trying to solve the following question, and I would greatly appreciate any assistance you can provide. Let $a,b,c$ be complex numbers. The roots of $z^{3}...
MyLight's user avatar
  • 327
2 votes
2 answers
220 views

Determine whether the roots of a cubic equation have positive real part

Consider the cubic equation $a x^3 + b x^2 + cx + d =0 $, where all coefficients depend on three parameters $$a=a(i, j, k), b=b(i, j, k),\cdots$$ and $a, b, c \in \mathbb{R}$ for all $(i, j, k)$. The ...
Emma Anderson's user avatar
2 votes
1 answer
76 views

Spivak, Ch, 25, 2(v): Is there some specific technique to factorize $x^3-x^2-x-2$ or must one guess that 2 is root?

The following problem appears in Ch. 25, "Complex Numbers" of Spivak's Calculus 2 (v) Solve the equation $x^3-x^2-x-2=0$. Is there some specific technique to factorize this? Must one ...
xoux's user avatar
  • 5,021
0 votes
0 answers
105 views

When we say the odd degree polynomial has odd number of real roots, is there any condition on the coefficients?

I read that if the degree of a polynomial equation is odd then the number of real roots will also be odd. I took the example of a cubic equation. If it has imaginary roots then that will occur in pair....
aarbee's user avatar
  • 8,338
3 votes
3 answers
214 views

Find the total number of roots of $(x^2+x+1)^2+2=(x^2+x+1)(x^2-2x-6)$, belonging to $(-2,4)$.

Find the total number of roots of $(x^2+x+1)^2+2=(x^2+x+1)(x^2-2x-6)$, belonging to $(-2,4)$. My Attempt: On rearranging, I get, $(x^2+x+1)(3x+7)+2=0$ Or, $3x^3+10x^2+10x+9=0$ Derivative of the cubic ...
aarbee's user avatar
  • 8,338
2 votes
1 answer
233 views

Collinearity of the three roots of a cubic equation in the complex plane

The three roots of the equation $x^3+bx+c=0\;(b,c\in\Bbb C,c\ne0)$ in the complex plane are collinear iff$$k\in\Bbb R\land k\le-\frac{27}4$$where $k=\frac{b^3}{c^2}$. Original post on Math ...
hbghlyj's user avatar
  • 3,047
1 vote
2 answers
101 views

Missing solutions from complex cubic root

From Cardano's work in the 1600s, we have this famous example of a cubic polynomial equation: $$x^3-15x-4=0.$$ Plugging the coefficients into the Cardano-Tartaglia formula, we get an expression for ...
Steeven's user avatar
  • 769
2 votes
3 answers
473 views

How does one show this complex expression equals a natural number?

We have: $$\left(\frac{10 }{3^{3/2}}i-3\right)^{1/3}+ \frac{7}{3 \left(\frac{10}{3^{3/2}}i-3\right)^{1/3}}=2$$ This comes from solving the cubic equation of $x^3-7x+6=0$ which factors as $(x-2)(x-1)(x+...
zooby's user avatar
  • 4,425
0 votes
1 answer
78 views

Polynomial and Complex Roots Problem

Suppose that there exist nonzero complex numbers $a,$ $b,$ $c,$ and $d$ such that $k$ is a root of both the equations $ax^3 + bx^2 + cx + d = 0$ and $bx^3 + cx^2 + dx + a = 0.$ find all possible ...
user avatar
4 votes
0 answers
104 views

A cute way to solve the quadratic. How to extend it to the cubic?

Playing around with complex numbers, I found a cute way of solving the quadratic equation. Let's start with the (monic) equation \begin{equation} z^2+pz+q = 0 \end{equation} where $z$ and the ...
marco trevi's user avatar
  • 3,386
0 votes
3 answers
395 views

Find the roots of $z^3 +3z^2 +3z +3=0$

Hello I have this problem: Find all $z \in C$ $z^3 +3z^2 +3z +3=0.$ With Mathematica I get 3 roots $z_1 = -1 -\sqrt[3]{2}$ $z_2 = -1 + (1 + i \sqrt{3})/2^{(2/3)}$ $z_3 = -1 + (1 - i \sqrt{3})/2^{(2/3)}...
Ramil Sunday's user avatar
0 votes
2 answers
48 views

How to factor $z^3-3\sqrt{3}iz^2-9z+3\sqrt{3}i$ strictly via the method of grouping

I really don't have much of my own attempt to show for this question. All I managed to get to was: $$z^2(z-3\sqrt{3}i)-3(3z-3\sqrt{3}i)$$ By simply factorising. It is asked in the question to be ...
Swiss Gnome's user avatar
2 votes
3 answers
94 views

Stuck on simplifying expressions involving trig and inverse trig functions

TL; DR Using Mathcad and Wolfram I can see that $$\sqrt{7}\cos\frac{\tan^{-1}\left(\frac{9\sqrt{3}}{10}\right)}{3}=2.5$$ The decimal value seems to be exact because Mathcad displays it like that with ...
Rokas's user avatar
  • 173
-1 votes
1 answer
150 views

Solving Non-Homogenous Recurrence Relation

I was interested in Solution of this Non-Homogenous Recurrence Relation $f(n)=f(n-1) + f(n-3) + 1$ The Base conditions are: $f(0)=1$ $f(1)=2$ $f(2)=3$ Kindly help me in solving this Recurrence ...
Rohit Singh's user avatar
  • 1,143

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