Skip to main content

All Questions

Tagged with
5 votes
1 answer
242 views

Is there an easy way to tell whether a cubic or quartic polynomial is factorable over the integers?

For a quadratic, it is easy to tell whether it is factorable. If the discriminant is a perfect square, the quadratic is factorable. Otherwise, the quadratic is not factorable. Is there anything ...
Catherine's user avatar
0 votes
2 answers
192 views

Factoring $x^3-6x^2+11x-6$ without using Rational Roots Theorem

To factor $P(x)=x^3-6x^2+11x-6$ one way is using Rational Roots Theorem and recognizing that $x=1$ makes $P(x)$ zero. But I want to factor without using it. I tried, $$x^3-6x^2+11x-6=x^2(x-6)+11(x-6)+...
Amirali's user avatar
  • 1,159
2 votes
0 answers
64 views

Irreducibility testing for integral cubic polynomials

I am interested in an algorithm (or irreducibility criterion) for testing whether a cubic polynomial $f \in \mathbb{Q}[x]$ is reducible or not. By Gauss's Lemma, we can work with cubics in $\mathbb{Z}[...
Pranav Bisht's user avatar
0 votes
1 answer
68 views

Factoring into a product with three term

I want to solve the following equation: $$144s^3-408s^2+349s-85 = 0$$ I know that the solution is: $$(s-1)(12s-17)(12s-5)=0$$ which implies gives, $s=1$ or $s=\dfrac{17}{12} $ or $s=\dfrac{5}{12}$. ...
Sara 's user avatar
-1 votes
1 answer
64 views

If $a\neq 2$ and $a^3+a^2-a-10 = 0$, then evaluate $a+\frac{5}{a}$ [closed]

If $a\neq 2$ and $a^{3}+a^{2}-a-10 = 0$, then what is the value of $a+\dfrac{5}{a}$? I have plugged equation on WolframAlpha and get the complex values of $a$ but you supposed to do this problem ...
Bilal Ergüç's user avatar
0 votes
1 answer
423 views

Factor simple cubic polynomial $ax^3 + cx + d = 0$

I'm working on a self-made problem where I have a cubic equation I need to factor. I have some flexibility in choosing my own coefficients for the polynomial, so I am strategically trying to choose my ...
John_Krampf's user avatar
-1 votes
1 answer
54 views

Factorizing $12x^3 - 8x^2 - 3x + 2$ [closed]

How should I factorize this cubic expression? $$12x^3 - 8x^2 - 3x + 2$$
mfsg's user avatar
  • 49
0 votes
3 answers
174 views

Foolproof method for simplifying polynomials with four terms?

When simplifying quadratic equations you have two options: factoring (which may or may not work) or the quadratic formula (which will always find the answer) For quadrinomials what is the go to ...
RudyGoburt's user avatar
5 votes
7 answers
260 views

Solve $\frac{x^3-4x^2-4x+16}{\sqrt{x^2-5x+4}}=0$

Solve $$\dfrac{x^3-4x^2-4x+16}{\sqrt{x^2-5x+4}}=0.$$ We have $D_x:\begin{cases}x^2-5x+4\ge0\\x^2-5x+4\ne0\end{cases}\iff x^2-5x+4>0\iff x\in(-\infty;1)\cup(4;+\infty).$ Now I am trying to solve the ...
Math Student's user avatar
  • 5,352
1 vote
2 answers
137 views

Find the zeros of $f(x)=x^3−4x^2+x−4$

I am to find the zeros and multiplicities of $f(x)=x^3−4x^2+x−4$. The solution provided in the answers section of my book is 4 with multiplicity 1. I arrived at $2\pm\sqrt(8)$. My working: $$x^3-4x^2+...
Doug Fir's user avatar
  • 2,266
0 votes
1 answer
82 views

about the complex number

Let $a+ ib$ be the complex root of $f(x)=x^3+2x+1$. I want to find $a$. My Try: $f(a+ib)=0$. It follow that $$(a^3-3ab^2+2a+1)=(-b^3+3a^2b+2b)=0$$
Little girl's user avatar
1 vote
3 answers
89 views

A series of multiplication leads to $\frac{1}{2} = 2$

I'm presented with the equation $\frac{a+b}{a} = \frac{b}{a+b}$ Performing cross multiplication yields $a^2+2ab+b^2 = ab$ Subtracting $ab$ from both sides, we get $a^2+ab+b^2 = 0$ Multiplying both ...
Saif Taher's user avatar
0 votes
2 answers
348 views

Calculating eigenvalues for a $3 \times 3$ matrix without solving a cubic

I am trying to find the eigenvalue for question (h), however I am unable to factor out and find the eigenvalues(roots) after I take the determinant of the characteristic equation. Let $x$ be an ...
mathsisfake's user avatar
2 votes
2 answers
148 views

Solving degree 3 equations

Solve for $x$, \begin{cases}4x^3+3x^2y+y^3=8\\ 2x^3-2x^2y+xy^2=1\end{cases} I tried substitution of $x$, but it got very complex. Is there a simpler way to do this?
user avatar
1 vote
3 answers
374 views

Finding a cubic formula for roots of cubic equations

Solve for $x$, $$27x^3+21x+8=0$$ I would like to know if there exists an formula for cubic equations just like quadratic formula for quadratic equations.
user avatar

15 30 50 per page
1
2 3 4 5