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3 votes
1 answer
139 views

Solving a depressed cubic polynomial in modulus. [closed]

Is there a general technique for solving depressed cubic modulus polynomial? For instance, how would you solve the equation $a^3 + a + 21 = 0 \pmod{43}$?. My attempts eventually ended up with solving $...
Sin Keong Tong's user avatar
4 votes
2 answers
492 views

Understanding Cardano's Formula

In deriving his formula, Cardano arrives at the equation $y^3+py+q=0$. By substituting $y=\sqrt[3]{u}+\sqrt[3]{v}$, he gets the equation $(u+v+q)+(\sqrt[3]{u}\sqrt[3]{v})(3\sqrt[3]{u} \sqrt[3]{v} +p)=...
Dick Grayson's user avatar
  • 1,467
5 votes
0 answers
109 views

Counterexample to the Hasse principle of the form $x^3 + y^3 + z^3 + nt^3$

Selmer's cubic is a counterexample to the Hasse principle for ternary cubic forms. We also know that the Hasse principle does not hold for quaternary cubic forms, as $$ 5x^3 + 12y^3 + 9z^3 + 10t^3 $$ ...
Heinrich Wagner's user avatar
5 votes
0 answers
714 views

Elementary approach to solving cubic equations over finite fields

I am interested in studying cubic equations over finite fields. For example, when does $$ ax^3 + bx^2 + cx + d = 0 $$ have a solution in $\mathbb{F}_q$ for $a,b,c,d\in \mathbb{F}_q$ (finite field of ...
John Doe's user avatar
  • 3,309
2 votes
1 answer
182 views

Proving the sums of three cubes conjecture by the Hasse principle

In his Cours d'arithmétique Serre applies the Hasse-Minkowski theorem to quadratic forms of the form: $$ x^2 + y^2 + z^2 = n $$ for $n \in \mathbb{N}$ to prove that a natural number $n$ is a square if ...
Heinrich Wagner's user avatar
0 votes
3 answers
2k views

Solution of cubic equations in terms of quadratic equations

Is there a general way in which a cubic equation of $3$rd degree can be represented by a quadratic equation of $2$nd degree such that $2$ solutions of a cubic equation is equal to $2$ solutions of ...
Suryanshu koli's user avatar
0 votes
1 answer
65 views

How to get rid of such radicals?

I would like to know if there is any way I can get rid of these cubic radicals bellow (1). I am allowing both complex and real values. $$ \sqrt[3]{ -\frac{q}{2} + \sqrt{\frac{q^2}{4} + \frac{p^3}{27} }...
Mr. N's user avatar
  • 516
5 votes
3 answers
154 views

Using partial information to factor $x^6+3x^5+5x^4+10x^3+13x^2+4x+1.$

I wish to find exact expressions for all roots of $p(x)=x^6+3x^5+5x^4+10x^3+13x^2+4x+1.$ By observing that for the roots $x_0 \pm iy_0, x_0 \approx -0.15883609808599033632, y_0 \approx 0....
Display name's user avatar
  • 5,230
1 vote
1 answer
174 views

Solving the sextic equation with 14th root of unity

I am solving the sextic equation $t^6-t^5+t^4-t^3+t^2-t+1=0$ satisfied by the 14th root of unity (a problem from Ian Stewart's book). I was able to get up to the point where you have the polynomial $u^...
Killaspe's user avatar
  • 338
2 votes
3 answers
1k views

Prove $2\cos\frac{2\pi}{7}$ is root of $x^3 + x^2 - 2x -1$

To prove that a regular septagon cannot be constructed by a straightedge and compass, it suffices to prove that $2\cos(\frac{2\pi}{7})$ is not constructible. Several other answers to this question ...
kt046172's user avatar
  • 535
1 vote
2 answers
64 views

how one can prove that real roots, which look non-real when using Cardano's formula.

how one can prove that real roots, which look non-real when using Cardano's formula, can be shown to be real.
Emo Gma's user avatar
  • 11
1 vote
2 answers
131 views

Writing Cubic Equation in terms of discriminant (with possible shifts and translations)

So I noticed this fact for the following fact for quadratic equations. I need one notation that if one equation can be gotten from another through a shift or scaling of variable then I will denote ...
HumbleStudent's user avatar
5 votes
1 answer
337 views

For $c\in\mathbb{F}_p^*$, the cubic $t^3-3ct^2-3t+c$ has exactly one root $r\in\mathbb{F}_p$. Express $r$ in terms of $c$ without cubic roots.

For some $c \in \mathbb{F}_p^*$ consider the polynomial $$ f(t) = t^3 - 3ct^2 - 3t + c $$ for $p \equiv 1$ (mod $3$) and $p \equiv 3$ (mod $4$). In this case $3$ is a quadratic non-residue modulo $p$ ...
Dimitri Koshelev's user avatar
1 vote
0 answers
39 views

Solutions of Cubic equation over $k$ with $char(k)=0$

I was working on the irreducibility of cubic equations over a non specific field (at first) and came up with this question: Given a cubic polynomial $d(t)=t^3+at^2+bt+c$ in $k[x]$ where $char(k)=0$, ...
Cristian Baeza's user avatar
-2 votes
1 answer
77 views

How to find $\operatorname{Gal}(S/\mathbb{Q})$ [closed]

Please help me to answer the following problem: Let $f(x)=x^3-3x-5\in\mathbb{Q}[x]$ Thanks
siwar's user avatar
  • 291

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