Skip to main content

All Questions

Tagged with
2 votes
1 answer
121 views

Three real roots of a cubic

Question: If the equation $z^3-mz^2+lz-k=0$ has three real roots, then necessary condition must be _______ $l=1$ $ l \neq 1$ $ m = 1$ $ m \neq 1$ I know there is a question here on stack about ...
Darshit Sharma's user avatar
2 votes
1 answer
76 views

Spivak, Ch, 25, 2(v): Is there some specific technique to factorize $x^3-x^2-x-2$ or must one guess that 2 is root?

The following problem appears in Ch. 25, "Complex Numbers" of Spivak's Calculus 2 (v) Solve the equation $x^3-x^2-x-2=0$. Is there some specific technique to factorize this? Must one ...
xoux's user avatar
  • 5,021
2 votes
1 answer
135 views

Stationary points of a cubic function

If t is a positive constant, find the local maximum and minimum values of the function $f(x) = (3x^2 - 4)\left(x - t + \frac{1}{t}\right)$ and show that the difference between them is $\frac{4}{9}(t + ...
Gill Dixon's user avatar
3 votes
0 answers
92 views

About extreme values of $\{f(x)-x\}^2$ when $f(x)$ is a cubic function.

$t \ge 6$, $t \in \mathbb{R}$ $f(x) = \frac{1}{t}\left( \frac{1}{8}x^3 + \frac{t^2}{8}x+2\right)$ $\{f(x)-x\}^2$ has an extreme value on $x = k$ Sum of such $k = g(t)$ $g(p) = -1$ for some $p \in \...
SinonOW's user avatar
  • 343
6 votes
2 answers
248 views

Integration formula for cubic polynomial $\int_a^bq(x)dx=\frac{b-a}{2}(q(b)+q(a))-\frac{(b-a)^2}{12}(q'(b)-q'(a))$

Show that $\forall a,b\in \mathbb{R}$, with $a<b$, we have$$\int \limits _a^bq(x)\,dx=\frac{b-a}{2}(q(b)+q(a))-\frac{(b-a)^2}{12}(q'(b)-q'(a)),$$ where $q\in \mathcal{P}_3$ is a cubic polynomial. I'...
Jonas Hardt's user avatar
1 vote
3 answers
84 views

Assume that $a=b$. If the function $f(x)$ is monotonously increasing, then (answer 1) $0<a<1$ (answer b).

The given function is $f(x)=x^3-3ax^2+3bx-2$. I am aware that monotonously increasing means to continuously increase, so I tried getting this function's derivative and then setting it to zero, but to ...
TizzleRizzle's user avatar
15 votes
1 answer
354 views

Does the limit of the cubic formula approach the quadratic one as the cubic coefficient goes to $0$?

The formula for solving a cubic equation of the form $ax^3+bx^2+cx+d=0$ does not seem to yield the quadratic formula for the limit $\lim _{a \rightarrow 0} \text{(cubic formula)}$. But, if one tries ...
Joel's user avatar
  • 297
3 votes
2 answers
80 views

Minimum value of M such that the cubic modulus value is always less than M for x in between -1 and 1 both included

Minimum value of $M$ such that $\exists a, b, c \in \mathbb{R}$ and $$ \left|4 x^{3}+a x^{2}+b x+c\right| \leq M ,\quad \forall|x| \leq 1 $$ What i considered was that putting x= 0, 1 and -1 we get ...
Orion_Pax's user avatar
  • 431
0 votes
0 answers
116 views

Finding the roots of an absolute value natural log function, regarding the usage of Newton-Raphson

This is an exercise I saw in my last test, I've been practicing it but I'm currently a bit lost when finding the roots, here's the exercise: Given $f:f(x)=-x^2+2x+3$, be F/F(x) is a primitive of f ...
Hareka's user avatar
  • 31
2 votes
1 answer
304 views

What do the inflection points of complex functions look like when plotted?

The inflection points of real continuous functions have a relatively clear visual interpretation - they are the points when the function's graph moves from convex to concave, or vice-versa. Conversely,...
Oscar Heath's user avatar
0 votes
1 answer
76 views

Applying general cubic formula to example

I'm trying to understand the general cubic formula so let's try applying it to an example: Let's take: $$(x-1)(x-2)(x-3) = 0$$ $$\implies x^3 - 6x^2 +11x -6 = 0$$ So the general cubic formula should ...
Andrew Tomazos's user avatar
0 votes
0 answers
63 views

Understanding the general cubic formula? ("Changing the choice of a cubic root"?)

Paraphrasing Wikipedia > Cubic Equation > General cubic formula, and ignoring special cases and caveats, it says: The cubic equation: $$ax^3 + bx^2 + cx + d = 0$$ can be solved as follows: Let: $...
Andrew Tomazos's user avatar
1 vote
1 answer
769 views

The roots of a cubic auxiliary equation are $𝑚_1 = 4$ and $𝑚_2 = 𝑚_3 = 5$. What is the corresponding homogeneous linear differential equation?

Is your solution unique? My try: $m-4=0, m-5=0 \text { and } m-5=0$ $(m-4)(m-5)^{2}=0$ $(m-4)(m^{2}-10m+25)=0$ $m^{3}-10m^{2}+25m-4m^{2}+40m-100=0$ $m^{3}-14m^{2}+65m-100=0$ $d^{3}y/dx^{3}-14d^{2}y/dx^...
Waseem F-Name  Ali Nawaz's user avatar
-1 votes
2 answers
198 views

Cubic's derivative

For a cubic $ax^3+bx^2+cx+d$, the radicand of the derivative is $b^2-3ac$ and I was wondering if there's a word for this term. I know that the nature of it being positive, zero, or negative will ...
user avatar
1 vote
1 answer
79 views

Is there a simple reason for why the two stationary points in a cubic polynomial has its second derivative equal in magnitude but opposite in sign.

Given a polynomial $f(x) = x^3 + ax^2 + bx + c$, then $$f'(x) = 3x^2 + 2ax + b$$ $$f''(x) = 6x + 2a$$ The stationary points in the curve will have $x = \frac{-a \pm \sqrt{a^2 - 3b}}{6}$, but then the ...
Y.T.'s user avatar
  • 1,447

15 30 50 per page
1
2 3 4 5