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2 votes
1 answer
56 views

Show that if $x=-1$ is a solution of $x^{3}-2bx^{2}-a^{2}x+b^{2}=0$, then $1-\sqrt{2}\le b\le1+\sqrt{2}$

$$x^{3}-2bx^{2}-a^{2}x+b^{2}=0$$ Show that if $x=-1$ is a solution, then $1-\sqrt{2}\le b\le1+\sqrt{2}$ I subbed in the solution $x=-1$, completed the square, and now I'm left with the equation $\...
LÜHECCHEgon's user avatar
0 votes
1 answer
43 views

Prove a relation between the coefficients of a depressed cubic.

The equation $x^{3}+px^{2}+q=0$ where p and q are non-zero constants, has three real roots $\alpha$, $\beta$ and $\gamma$. Given that the interval between $\alpha$ and $\beta$ is p and that the ...
druidmind's user avatar
1 vote
1 answer
45 views

Proof of conditions for polynomials

Find the conditions for the roots $\alpha, \beta, \gamma$ of the equation $x^3-ax^2+bx-c=0$ to be in: $(i)$A.P.; $(ii)$G.P. If the roots are not in A.P. and if $\alpha+\lambda,\ \beta+\lambda,\ \...
J_dash's user avatar
  • 87
0 votes
0 answers
125 views

Can I use this algorithm for solving cubic equations?

I am trying to find the root solutions for a cubic equation including the eigenvalues of each root. I tried to put the equation into my calcualtor but the calculator doesn't show solutions that has ...
Ryan's user avatar
  • 1
3 votes
6 answers
406 views

Find all real numbers $a$ for equation $x^3 + ax^2 + 51x + 2023=0$, has two equal roots.

Problem: Find all real numbers $a$ for which the equation, $x^3 + ax^2 + 51x + 2023=0$, has two equal roots. This problem is from an algebra round of a local high school math competition that has ...
JHumpdos's user avatar
  • 167
3 votes
2 answers
222 views

Finding root of a cubic equation.

I was solving a physics statistical mechanics problem of an interacting system. In that question, I have to find the eigenvalues of a matrix P whose elements are given by $$P= \begin{bmatrix} e^{x} &...
Sumit Gupta's user avatar
6 votes
2 answers
176 views

Why do equilateral triangles relate to cubics

I found this question talking about the relation between an equilateral triangle and cubics with three distinct real roots. Here's an image from the original post with an example: What this post says ...
thereisnoname's user avatar
6 votes
5 answers
183 views

If the roots of $x^3 − 6x^2 + 10x + 1$ are denoted as a, b, c, then find the value of $(a^2 + b^2 )(a^2 + c^2 )(b^2 + c^2 )$.

If the roots of $x^3 − 6x^2 + 10x + 1$ are denoted as a, b, c, then find the value of $(a^2 + b^2 )(a^2 + c^2 )(b^2 + c^2 )$. I have tried factoring $x^3 − 6x^2 + 10x + 1$ but didn't get anything. ...
silent_fable0087's user avatar
5 votes
1 answer
127 views

Find the value of: $\sqrt[3]{a+b}+\sqrt[3]{b+c}+\sqrt[3]{a+c}$

Let $a,b,c$ be roots of the cubic $$x^3-x^2-2x+1=0$$ Then, find the value of: $$\sqrt[3]{a+b}+\sqrt[3]{b+c}+\sqrt[3]{a+c}$$ My attempt. I used the substitutions $$a+b=x^3, b+c=y^3, a+c=z^3$$ $$x^3+y^...
user1094359's user avatar
0 votes
0 answers
105 views

When we say the odd degree polynomial has odd number of real roots, is there any condition on the coefficients?

I read that if the degree of a polynomial equation is odd then the number of real roots will also be odd. I took the example of a cubic equation. If it has imaginary roots then that will occur in pair....
aarbee's user avatar
  • 8,338
0 votes
3 answers
1k views

Solve the equation $x^3-11x^2+38x-40=0$, given that the ratio of two of its roots is $2:1$.

Solve the equation $x^3-11x^2+38x-40=0$, given that the ratio of two of its roots is $2:1$. By hit and try, I can see that $x=2$ is a root. Dividing the given cubic by $x-2$, I get a quadratic whose ...
aarbee's user avatar
  • 8,338
3 votes
3 answers
214 views

Find the total number of roots of $(x^2+x+1)^2+2=(x^2+x+1)(x^2-2x-6)$, belonging to $(-2,4)$.

Find the total number of roots of $(x^2+x+1)^2+2=(x^2+x+1)(x^2-2x-6)$, belonging to $(-2,4)$. My Attempt: On rearranging, I get, $(x^2+x+1)(3x+7)+2=0$ Or, $3x^3+10x^2+10x+9=0$ Derivative of the cubic ...
aarbee's user avatar
  • 8,338
7 votes
3 answers
400 views

Reducing $ax^6-x^5+x^4+x^3-2x^2+1=0$ to a cubic equation using algebraic substitutions

Use algebraic substitutions and reduce the sextic equation to the cubic equation, where $a$ is a real number: $$ax^6-x^5+x^4+x^3-2x^2+1=0$$ My attempts. First, I tried to use the Rational root ...
user1094359's user avatar
3 votes
1 answer
107 views

Real solutions to the depressed cubic equation [closed]

How can I find the allowed domain to this depressed cubic inequality $$x^3 - 3 x + 2 \cos(\frac{3 \sqrt{3} n}{2}) \geq 0$$ where $n$ is a real non-negative number. Using Cardano's method, I can obtain ...
Sid's user avatar
  • 403
0 votes
3 answers
96 views

Finding all possible roots of the equation

Find all possible solutions to the equation $$(x^3-x)+(y^3-y)=z^3-z$$ where $(x,y,z)\gt1$ and $\in\mathbb{Z}$ and not all three of them are equal. The original question didn't have the last condition ...
abcdefu's user avatar
  • 860

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