Skip to main content

Questions tagged [anticommutator]

The tag has no usage guidance.

2 votes
1 answer
207 views

Are there any 3 or more Hermitian solutions to the problem: $\alpha_i^2=1$, $\{\alpha_i, \alpha_j \}=2$

I’m trying to generate some matrices which are similar to Pauli’s but with the following anti-commutation relation $$\{\alpha_i, \alpha_j\}=\alpha_i \alpha_j + \alpha_j \alpha_i = 2 \tag{1}$$ And $$\...
J. Manuel's user avatar
  • 2,241
0 votes
0 answers
168 views

Commuting but not anti-commuting operators

Two Hermitian operators $\hat{A}$ and $\hat{B}$ are such that they commute but don't anti-commute. In this case, even they commute their uncertainty product will not be zero, is it right?
Snpr_Physics's user avatar
3 votes
0 answers
93 views

Derivation of anti-commutation relations of massive supermultiplet generators [closed]

In almost all intro to supersymmetry notes the commutation relations are given between the generators and their conjugates however, I can not find any proofs of them anywhere and am struggling to ...
Barnsandmaths's user avatar
4 votes
0 answers
270 views

Defining particles by their commutation/anti-commutation relations

In my studies of many-body physics, I have encountered three types of particles, which can be defined based on their commutation/anti-commutation relations. Fermions, defined by raising/lowering ...
Solarflare0's user avatar
2 votes
1 answer
585 views

Right derivative of Grassmann number and associated anti-commutation relation

I am reading chapter 3 of Anomalies in quantum field theory by Reinhold Bertlmann and I found one statement that I don't know how to prove. First of all he defined the right derivative on the ...
ocf001497's user avatar
  • 766
0 votes
1 answer
241 views

On the normal ordering of Fermi fields

From my understanding, the normal ordering of Klein-Gordon fields in QFT is valid because of the ambiguity that comes with quantizing a classical theory, in the sense that the conmutator of fields is ...
Sasha's user avatar
  • 11
4 votes
1 answer
337 views

Pauli Exclusion Princple for a fermion and antifermion

I understand that the Pauli Exclusion Principle applies only for identical particles, so that a fermion and an anti-fermion should be allowed to be in the same state. However, when I look at the ...
Nick Ormrod's user avatar
0 votes
1 answer
373 views

Anti-commutator of Dirac matrices

Consider $$ \beta = \begin{pmatrix} \mathbf{1} & 0 \\ 0 & -\mathbf{1} \end{pmatrix},\quad \alpha_i = \begin{pmatrix} 0 & \mathbf{\sigma}_i \\ \mathbf{\sigma}_i&0 \end{pmatrix}.$$ The ...
Zachary's user avatar
  • 265
0 votes
1 answer
274 views

(Anti)commutation of creation and annhilation operators for different fermion fields

The Fourier expansion of the fermion field operator is such that $$ \hat\psi=\int\!d^3p\,\left[ f_b(p)\hat b(p) +f_d(p)\hat d^\dagger\!(p) \right] ~~, $$ for some sufficiently complicated $f_b$ and $...
hodop smith's user avatar
1 vote
1 answer
139 views

Measurements, QFT and Wightman's axiom 3

I think I might have misconceptions about the conceptual core of QFT. Let me explain where I am puzzled. In QM, the measurement process is accounted by the postulate of collapse of the wave function: ...
Plop's user avatar
  • 507
0 votes
0 answers
197 views

Show $[\gamma^\mu,\eta^{\nu\lambda}I]=0$ for Dirac matrices

I am trying to show the following commutation relation for the Dirac matrices $\gamma^\mu$ and the metric $\eta^{\nu\lambda}$: $$2[\gamma^\mu,\eta^{\nu\lambda}I]=0$$ where $I$ is the 4x4 identity ...
TaeNyFan's user avatar
  • 4,235
2 votes
1 answer
525 views

What is a fermionic field theory?

Let $\mathscr{H}$ be a Hilbert space and $\mathscr{H}^{n}$ be the associated $n$-fold tensor product of this Hilbert space. I'll skip the mathematical details in what follows, but my approach follows ...
JustWannaKnow's user avatar
3 votes
1 answer
534 views

Why is the anti-commutation relation $\lbrace \psi_a(x), \bar{\psi}_b(y) \rbrace = 0$ enough to ensure causality?

In quantum field theory, it is crutial that two experiments can not effect each other at space-like seperation. Thus $[\mathcal{O}_1(x), \mathcal{O}_2(y)] = 0 $ if $(x-y)^2 < 0$. For the Klein-...
tomtom1-4's user avatar
  • 1,219
3 votes
1 answer
279 views

Why is the anticommutator of the uncertainty principle omitted if it serves to increase the accuracy of our "knowledge" of a quantum state?

The generalized uncertainty principle can be derived and shown to be this which is fine and rigorous. $\langle ( \Delta A )^{2} \rangle \langle ( \Delta B )^{2} \rangle \geq \dfrac{1}{4} \vert \langle ...
cheekylittleduck's user avatar
0 votes
1 answer
260 views

How to express the anti-commutator in the form of a density operator?

$ \newcommand{\ket}[1]{|{#1}\rangle} \newcommand{\bra}[1]{\langle{#1}|} \newcommand{\braket}[2]{\langle{#1}|{#2}\rangle} \newcommand{\acomm}[2]{\left\{#1,#2\right\}} $Let $\{ \ket{1} \ket{1} \ket{2} .....
Consideration's user avatar

15 30 50 per page
1 2 3
4
5
12