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Questions tagged [ordinals]

In the ZF set theory ordinals are transitive sets which are well-ordered by $\in$. They are canonical representatives for well-orderings under order-isomorphism. In addition to the intriguing ordinal arithmetics, ordinals give a sturdy backbone to models of ZF and operate as a direct extension of the positive integers for *transfinite* inductions.

2 votes
2 answers
87 views

If I have a sequence $a_0, a_1, a_2, \cdots$ , then is expressing the limit of this sequence as $a_\omega$ sensible?

If I have a sequence created by some rule which comes to a limit , then I can express it as $a_0, a_1,a_2,\cdots$. If I said $\lim_{n \to \infty} a_n = a_{\omega} $ , is that a sensible thing to do ? ...
Q the Platypus's user avatar
1 vote
1 answer
30 views

Showing that $\bigcap A$ is the least element for the set $A$ where $A$ is a set of ordinals.

The notes I am reading define a set $x$ to be an ordinal provided $x$ is transitive and every element in $x$ is transitive. Let $A$ be a set of ordinals. I have shown that $\bigcap A$ is an ordinal. I ...
3j iwiojr3's user avatar
1 vote
0 answers
71 views

What is the largest known "computational" ordinal

I am interested in the computational implementation of ordinals. What I mean by that, is a data structure T and a function/algorithm "compare" that takes two arguments of type "T" ...
Ivan's user avatar
  • 11
2 votes
1 answer
80 views

Can $\sf{ST}$ construct an infinite class wellordered ordered by $\in$?

Assume the axioms of Extensionality, Empty Set, and Adjunction (meaning that $S\cup\{x\}$ forms a set for any $S,x$). Notice that we do not have Specification as an axiom, which makes this theory very ...
Jade Vanadium's user avatar
1 vote
0 answers
29 views

A sequence of continuum hypotheses

The continuum hypothesis asserts that $\aleph_{1}=\beth_{1}$. Both it and its negation can be consistent with ZFC, if ZFC is consistent itself. The generalised continuum hypothesis asserts that $\...
Darmani V's user avatar
  • 290
1 vote
1 answer
82 views

Can cardinality $\kappa$ exist where $\forall n\in\mathbb{N} \beth_n<\kappa$,$\kappa<|\bigcup_{n\in\mathbb{N}}\mathbb{S}_n|$,$|\mathbb{S}_n|=\beth_n$

The Wikipedia article on Beth numbers defines $\beth_\alpha$ such that $\beth_{\alpha} =\begin{cases} |\mathbb{N}| & \text{if } \alpha=0 \\ 2^{\beth_{\alpha-1}} & \text{if } \alpha \text{ is a ...
SarcasticSully's user avatar
0 votes
0 answers
63 views

Can the class of ordinals be extended even further? [duplicate]

Is it possible for anything to come after all ordinals? I don't see why not. For example, one can take a non-ordinal set $S$, and then add in all the ordered pairs $(\alpha, S)$ to $ON$, where $\alpha$...
user107952's user avatar
  • 21.3k
0 votes
0 answers
17 views

Ordinal addition with limit ordinals, as in Kunen.

This definition of ordinal adddition is taken from Kenneth Kunens "Set Theory: An Introduction to Independence Proofs": $\alpha + \beta = \text{type}(\alpha \times \{0\} \cup \beta \times \{...
Ben123's user avatar
  • 1,222
2 votes
1 answer
127 views

Is the first-order theory of the class of well-ordered sets the same as the first-order theory of the class of ordinals?

Consider the class $K$ of well-ordered sets $(W,\leq)$. Although that class is not first-order axiomatizable, it has an associated first-order theory $Th(K)$. Now consider the class of ordinals $On$, ...
user107952's user avatar
  • 21.3k
2 votes
0 answers
73 views

Set of ordinals isomorphic to subsets of total orders

Background. Given a poset $(S,<)$ we'll indicate with $\tau(S,<)$ the set of all the ordinals which are isomorphic to a well ordered subset of $(S,<)$. We're in $\mathsf{ZFC}$. Questions. ...
lelouch_l8r4's user avatar
3 votes
1 answer
73 views

Constructible subsets of an ordinal - an alternate definition?

Work over ZFC. Recall the standard definition of $\mathrm{Def}(X)$, the set of constructible subsets of the set $X$. This can be considered as taking all those subsets of $X$ that satisfy some first-...
theHigherGeometer's user avatar
5 votes
1 answer
467 views

Does every ordinal have a well-defined "next" limit ordinal?

I would like to know whether every ordinal $\alpha$ has a well-defined "next limit ordinal", i.e. a least limit ordinal $\beta$ such that $\beta > \alpha$. I understand from this ...
blk's user avatar
  • 181
1 vote
0 answers
46 views

Ordinals multiplication: Does $a^2 b^2=b^2a^2$ imply $ab=ba$? [duplicate]

I found this question in one of set theory past exam: If $\alpha$ and $\beta$ are two ordinals such that $\alpha^2\beta^2=\beta^2\alpha^2$, does it necessarily imply $\alpha\beta=\beta\alpha$? Clearly ...
Ankiiatsy's user avatar
1 vote
1 answer
93 views

Intuition of Ordinal Number

I am learning the concept of ordinal numbers. In the book of Set Theory and Metric Spaces by I. Kaplansky (Sec. 3.2, pg. 55), the author states We attach to every well-ordered set an ordinal number; ...
Mingzhou Liu's user avatar
2 votes
0 answers
28 views

References that give the cofinality of ordinal addition, multiplication and exponentiation

$\newcommand{\cf}{\operatorname{cf}}$ Let $\alpha$, $\beta$ be ordinals. I believe that we have \begin{align*} \cf(\alpha+\beta)=\cf(\beta),\quad\beta\neq 0;\quad\cf(\alpha\cdot\beta)=\begin{cases}\cf(...
Jianing Song's user avatar
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