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2 votes
1 answer
105 views

Taking the limit beyond infinity, with the ordinals

Imagine a function $f:X\to X$ and $x\in X$ (keeping $f$ and $X$ vague on purpose) and let's define $u_1 = f (x)$ $u_2=f^2(x)=f(f(x))$ $u_n=f^n(x)$ Let's also assume that $\forall n, u_{n-1} \neq u_n $ ...
KiwiKiwi's user avatar
  • 169
5 votes
1 answer
157 views

Is the Stone Cech compactification $\beta\omega$ of $\omega$ radial?

$\beta\omega$ is sequentially discrete, that is, every convergent sequence is eventually constant. Thus, since the space is not discrete, the space is not sequential, that is, it's untrue that every ...
Steven Clontz's user avatar
0 votes
0 answers
64 views

The range of any continuous function from $[0, \omega_1] \times [0, \omega_1] \rightarrow \mathbb{R}$ is countable

I came across this question: “Prove that the range of any continuous function from $[0, \omega_1] \times [0, \omega_1] \rightarrow \mathbb{R}$ is countable” I’m quite new to ordinals and I’m having a ...
obitobi_tobias's user avatar
0 votes
1 answer
146 views

Classification of compact Hausdorff spaces $X$ of cardinality $2^{\aleph_0}>|X|\geq \aleph_1$?

On my own time, I've been curious/investigating some properties of compact Hausdorff spaces of cardinality $\aleph_{\alpha}$, for $\alpha \geq 0$ a particular ordinal. I am aware of the following ...
Rivers McForge's user avatar
0 votes
1 answer
70 views

Cantor-Bendixson rank of ordinal number

I need prove that: There is a single limit point of type (o Cantor-Bendixson rank) $\alpha$ in $\omega^\alpha + 1$. I try this: Since $\omega^\alpha + 1 = \omega^\alpha \cup \{ \omega^\alpha \}$, ...
James R.'s user avatar
  • 133
1 vote
1 answer
51 views

Order topology in $\omega^\alpha + 1$ and dynamical systems

Let $f \colon \omega^\alpha + 1 \to \omega^\alpha + 1$, where $\alpha \geq 1$ a continous funciton such that, exists $w \in \omega^\alpha + 1$ with $\mathcal{O}_f(w)$ dense in $\omega^\alpha + 1$. The ...
James R.'s user avatar
  • 133
1 vote
0 answers
38 views

Easier proof of homeomorphism classes of ordinals

I found a very interesting paper by V. Kieftenbeld and B. Löwe, "A classification of ordinal topologies" which discusses how to classify ordinals according to homeomorphism when they are ...
PatrickR's user avatar
  • 4,500
4 votes
0 answers
103 views

Prove that any continuous function $f:S_\Omega \rightarrow \mathbb{R}$ is eventually constant.

Let $\Omega$ be the first non-numerable ordinal number ( $\aleph_1$ is the first cardinal number greater than $\aleph_0$ when treated as an ordinal number is denoted by $\Omega$ ) and let $[0,\Omega)$ ...
Marco Roys's user avatar
0 votes
0 answers
169 views

Cantor-Bendixson derivative sets

I try to show that a compact subset $A\subset \mathbb{C}$ is at most countable if and only if there exists a countable ordinal number $\alpha$ (i.e $\alpha <\omega_{1},$ where $\omega_{1}$ is ...
pospos's user avatar
  • 51
0 votes
0 answers
31 views

Dense Compact subset of $X = ((\beta(D) \times (\mathfrak{c}^+ + 1)) \setminus (\beta(D) \setminus D) \times \{\mathfrak{c}^+\})$

Let $D$ be a discrete space of cardinality $\mathfrak{c}$ and $\beta(D)$ is the Stone Cech compactification of $D$. Let $$ X = ((\beta(D) \times (\mathfrak{c}^+ + 1)) \setminus (\beta(D) \setminus D) \...
Sumit Mittal's user avatar
3 votes
2 answers
153 views

$\omega_1$ is not Lindelof

I am looking to prove that $\omega_1$ is not Lindelof. Here is my proof so far: I am attempting to reveal a contradiction. Consider the collection $\mathscr{U} = \{(a,b]: a,b \in \omega_1$, $a<b$, $...
Grigor Hakobyan's user avatar
1 vote
0 answers
48 views

$ \mathbb{X}=\left(\left[0,\omega_{1}\right]\times\left[0,\omega\right]\right)\setminus\left\{ \left(\omega_{1},\omega\right)\right\} $ is not T4

I need to show that the subspace $\mathbb{X}=\left(\left[0,\omega_{1}\right]\times\left[0,\omega\right]\right)\setminus\left\{ \left(\omega_{1},\omega\right)\right\} $ of $\left[0,\omega_{1}\right]\...
Topologon's user avatar
0 votes
0 answers
124 views

Show that omega_1 is normal?

I've already proven the following statement. If $A$ and $B$ are disjoint closed subsets of $\omega_1$, then at least one of them must be bounded. This proof is supposed to be used to prove that $\...
Nicole's user avatar
  • 11
0 votes
1 answer
443 views

Questions about $\omega_1$ as a space (The Set of All Countable Ordinals)

The Set of All Countable Ordinals, $\omega_1$ I'm trying to understand several things regarding $\omega_1$ and trying to get a better intuition. I have four questions regarding this space (in bold), ...
Tereza Tizkova's user avatar
1 vote
1 answer
108 views

Prove: If $A$ and $B$ are closed subsets of $[0,\Omega]$ then at least $A$ or $B$ is bounded

As usual, I am self studying topology and my knowledge of ordinals is meagre. Have done some research on it. Theorem 5.1 Any countable subset of $[0,\Omega)$ is bounded above. (This exercise requires ...
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