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2 votes
1 answer
127 views

Is the first-order theory of the class of well-ordered sets the same as the first-order theory of the class of ordinals?

Consider the class $K$ of well-ordered sets $(W,\leq)$. Although that class is not first-order axiomatizable, it has an associated first-order theory $Th(K)$. Now consider the class of ordinals $On$, ...
user107952's user avatar
  • 21.5k
3 votes
1 answer
80 views

Hessenberg sum/natural sum of ordinals definition

I was given the following definition of Hessenberg sum: Definition. Given $\alpha,\beta \in \text{Ord}$ their Hessenberg sum $\alpha \oplus \beta$ is defined as the least ordinal greater than all ...
lelouch_l8r4's user avatar
5 votes
1 answer
75 views

Exercise 7.1.6 Introduction to Set Theory by Hrbacek and Jech

This is exercise 7.1.6 of the book Introduction to Set Theory 3rd ed. by Hrbacek and Jech. Let $h^{*}(A)$ be the least ordinal $\alpha$ such that there exists no function with domain $A$ and range $\...
Alphie's user avatar
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2 votes
1 answer
42 views

If $X_1$,$X_2$ are wosets isomorphic to ordinals $\alpha_1,\alpha_2$ then $X_1\times X_2$ is isomorphic to $\alpha_2\cdot \alpha_1$

I want to prove the following: Let $X_1$,$X_2$ be wosets, isomorphic to ordinals $\alpha_1,\alpha_2$ respectively. Then $X_1\times X_2$, with the lexicographic order, is isomorphic to $\alpha_2\cdot\...
Alphie's user avatar
  • 4,827
4 votes
0 answers
105 views

Why does proof of Zorn's lemma need to use the fact about ordinals being too large to be a set?

I'm not understanding why its necessary to invoke the knowledge about ordinals in order to prove Zorn's lemma. The Hypothesis in Zorn's lemma is Every chain in the set Z has an upper bound in Z Then ...
Pecan Lim's user avatar
8 votes
1 answer
109 views

What does the cardinality alone of a totally ordered set say about the ordinals that can be mapped strictly monotonically to it?

For any cardinal $\kappa$ and any totally ordered set $(S,\le)$ such that $|S| > 2^\kappa$, does $S$ necessarily have at least one subset $T$ such that either $\le$ or its opposite order $\ge$ well-...
Transfinite Pyramid Scheme's user avatar
1 vote
0 answers
46 views

Limit Countable Ordinal - is it a limit of a intuitive sequence of ordinals?

I am studying set theory, ordinal part. Set theory is new to me. I know that commutativity of addition and multiplication can be false in infinite ordinal world. $ \omega $ = limit of sequence $\, 1,2,...
imida k's user avatar
  • 295
1 vote
1 answer
126 views

a proof idea: Every well-ordered set has an order-preserving bijection to exactly one ordinal.

I have seen a proof of the statement, and its usually by transfinite induction. And I'm trying to find out why my proof doesn't work, it seems too simple: Let $X$ be a well-ordered set. Define $X^{<...
hteica's user avatar
  • 438
0 votes
1 answer
67 views

A couple of well ordering proofs.

I'm having trouble understanding a couple of things when studying well orderings and ordinals. I know that given a well ordering $(A,<)$ there is no $a\in A$ s.t. $(A,<)\cong (A_a,<)$ where $...
cento18's user avatar
  • 391
1 vote
1 answer
95 views

What are the order types of computable pseudo-ordinals with no c.e. descending chains?

The notion of a “computable pseudo-ordinal”, i.e. a computable linearly ordered set with no hyperarithmetical descending chains, is an old one going back to Stephen Kleene. Joe Harrison wrote the ...
Keshav Srinivasan's user avatar
13 votes
1 answer
670 views

Why do we need "canonical" well-orders?

(I asked this question on MO, https://mathoverflow.net/questions/443117/why-do-we-need-canonical-well-orders) Von-Neumann ordinals can be thought of "canonical" well-orders, Indeed every ...
Vivaan Daga's user avatar
  • 5,704
2 votes
2 answers
145 views

What is the meaning of "induction up to a given ordinal"?

Given an ordinal $\alpha$, what does it mean: "induction up to $\alpha$"? When $\alpha=\omega$, is this is ordinary mathematical induction? Also, Goodstein's Theorem is equivalent to "...
John's user avatar
  • 4,432
1 vote
1 answer
137 views

Question about a proof that any well-ordered set is isomorphic to a unique ordinal

I am studying a proof that every well-ordered set is isomorphic to a unique ordinal. However, I don't understand why $A = pred(\omega)$ (see yellow). One direction is clear: Let $x \in pred(\omega)$, ...
DerivativesGuy's user avatar
0 votes
0 answers
169 views

Cantor-Bendixson derivative sets

I try to show that a compact subset $A\subset \mathbb{C}$ is at most countable if and only if there exists a countable ordinal number $\alpha$ (i.e $\alpha <\omega_{1},$ where $\omega_{1}$ is ...
pospos's user avatar
  • 51
0 votes
1 answer
100 views

Description of largest possible countable set / number

I am looking for an elegant / standard (if any) description of the largest countable set. A first naive approach would be to construct this set, X, by taking the integers (0 to, but not including, ω_0,...
Daniel Miedema's user avatar

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