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Questions tagged [magma]

A magma is a set together with a binary operation on this set. (For questions about the computer algebra system named Magma, use the [magma-cas] tag instead.)

5 votes
1 answer
401 views

Are there interesting examples of medial non-commutative semigroups?

There exist semigroups $S$ (written additively) such that $S$ is medial, meaning $(a+b)+(a'+b') = (a+a')+(b+b')$. $S$ is not commutative. Example. The left (and right) zero semigroups are all medial,...
goblin GONE's user avatar
  • 68.1k
4 votes
1 answer
140 views

A question on certain "magma" structures

Let $S$ be a non-empty set and $*$ be a binary operation on $S$ such that the following axioms hold: for every $x,y,z∈S$ , $x*(y*z)=(x*z)*y$; $(S,*)$ has a right identity i.e. there exists $e∈S$ such ...
Souvik Dey's user avatar
  • 8,387
5 votes
2 answers
165 views

Is there a name for magmas with $[x+y]+[x'+y'] \equiv [x+x']+[y+y']$?

Is there a name for magmas (written additively) satsisfying the following identity? The square brackets have no particular signifance, but will hopefully promote readability in what follows. $$[x+y]+[...
goblin GONE's user avatar
  • 68.1k
1 vote
0 answers
63 views

Proper term for a monotonic magma

Let $M$ be the multiplication table for a finite magma. Entries are labeled $0,\ldots,n-1$. M has the property that $M(i,j)\ge i, M(i,j) \ge j$. What is the proper term for this kind of magma and ...
Chad Brewbaker's user avatar
17 votes
2 answers
457 views

What is this algebraic object called?

I was playing around with the following object: Let $Q$ be a set with a binary operator $\cdot$ obeying the axioms: $a \cdot a = a$ (idempotence) $a \cdot (b \cdot c) = (a \cdot b) \cdot (a \cdot c)$ ...
Malper's user avatar
  • 1,397
0 votes
1 answer
412 views

Discuss whether or not the following binary operations are commutative, associative, ...

Discuss whether or not the following binary operations are commutative, associtive, have neutral elements and for which elements there are inverse elements. In between are what I have said, but if it ...
tedg's user avatar
  • 111
1 vote
2 answers
1k views

prove no identity element in the given Cayley Table of three elements

Prove that the operation in the following Cayley table has no identity element: $$ \begin{array}{c|ccc} \hline * & u & v & w \\ \hline u & u & w & w \\ v & v & v & ...
user60887's user avatar
  • 2,935
3 votes
3 answers
125 views

How are the powers being changed

I have a semigroup $S$ including a generator, say $d$, such that $$d^4=d$$ I am trying to guess the general rule of $d$'s powers such that when I want to calculate $d^n, n\in\mathbb N$; I can simplify ...
Mikasa's user avatar
  • 67.5k
6 votes
5 answers
3k views

Inverse elements in the absence of identities/associativity.

Lets view groups as consisting of a binary operation, a distinguished element $e$, and unary operation $x \mapsto x^{-1}$. Then the group axioms can be stated as follows. $(xy)z=x(yz).$ $xe=ex=x.$ $...
goblin GONE's user avatar
  • 68.1k
8 votes
3 answers
450 views

Which properties are inherited by the Cartesian product of two sets equipped with a binary operation?

Let $G$ and $H$ denote sets equipped with a binary operation (aka magmas). We can form the Cartesian product magma $G \times H$ in the obvious way. I'm interested in which properties of $G$ and $H$ ...
goblin GONE's user avatar
  • 68.1k
4 votes
0 answers
84 views

Left continuous magmas with no fixed points

Let $X$ be a compact Hausdorff topological space, and $*: X^2\rightarrow X$ an associative map (so that $(X, *)$ is a semigroup) which is left continuous (for all $s\in X$, the map $t\mapsto ts$ is ...
Noah Schweber's user avatar
13 votes
6 answers
2k views

Associativity test for a magma

Say I have the operation table for a magma. I want to know whether or not the operation is associative. However, associativity is defined for an operation on 3 elements, and the operation table deals ...
Matthew Matic's user avatar
5 votes
2 answers
168 views

Prove this magma commutativity

Given magma $(X, *)$ and that $(x*y)*y = x$ and $y*(y*x) = x$ $\forall x, y \in X$ prove that $x*y = y*x$. Should be rather simple but I've been trying to prove that for several hours now with no ...
Nikita's user avatar
  • 53
30 votes
5 answers
12k views

A finite, cancellative semigroup is a group

Let $G$ be a finite, nonempty set with an operation $*$ such that $G$ is closed under $*$ and $*$ is associative Given $a,b,c \in G$ with $a*b=a*c$, then $b=c$. Given $a,b,c \in G$ with $b*a=c*a$, ...
user avatar
62 votes
7 answers
20k views

Is there an easy way to see associativity or non-associativity from an operation's table?

Most properties of a single binary operation can be easily read of from the operation's table. For example, given $$\begin{array}{c|ccccc} \cdot & a & b & c & d & e\\\hline a &...
celtschk's user avatar
  • 43.7k

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