Skip to main content

All Questions

Tagged with
-4 votes
1 answer
79 views

Practical example of differences between associativity and alternativity (and the in-between Bol loop)? [closed]

Associativity is: $$(a * b) * c = a * (b * c)$$ Alternativity is: $$a * (a * b) = (a * a) * b$$ $$(a * b) * b = a * (b * b)$$ Bol loop is: $${\displaystyle a(b(ac))=(a(ba))c}$$ $${\displaystyle ((ca)b)...
Lance's user avatar
  • 3,773
3 votes
0 answers
213 views

Does the percentage of associative operations on a finite set decrease monotonically towards zero?

In this answer, André Nicolas proves that it is rare for a binary operation on a finite set to be associative, in the following sense: if $A_n$ denotes the number of semigroups that can be defined on ...
Joe's user avatar
  • 20.8k
7 votes
2 answers
466 views

If not associative, then what?

Consider a binary operation $*$ acting from a set $X$ to itself. It's useful and standard to work with operations which are associative, such that $(a*b)*c = a*(b*c)$. What about operations which are ...
Jojo's user avatar
  • 1,324
1 vote
1 answer
81 views

Are all alternative magmas flexible?

A magma is alternative if for all elements $x$ and $y$, we have $(xx)y = x(xy)$ and $y(xx) = (yx)x$. A magma is flexible if for all elements $x$ and $y$ we have $x(yx) = (xy)x$. Both of these are ...
Tim Goodman's user avatar
1 vote
1 answer
168 views

Magma $(\mathbb R,*)$ with a binary operation $\;a*b=a+b-2a^2b^2$

Let $(\mathbb R, *)$ be a magma with a binary operation: $$a*b=a+b-2a^2b^2$$ Prove $(a)$ the binary operation is commutative, but not associative, $(b)$ $0$ is a neutral element for that ...
PinkyWay's user avatar
  • 4,670
0 votes
2 answers
41 views

Valid reason to prove the dis-associativity of ($\mathbb R, -)$.

Is this a valid proof? Let $a,b,c$ $\in$ $(\mathbb R, -)$. We want to prove that $(\mathbb R, -)$ does not have an associative property. Assume that it is associative such that: $a-(b-c) = (a-b)-c$. $...
Minuet's user avatar
  • 52
1 vote
0 answers
90 views

Why is a "double-cancellative" operation so weird?

Let $A = \{ \{0\}, \{0,1\} \}$. Let $\bar{A}$ be the family of sets generated by the Cartesian product on $A$. This is a magma $(\bar{A}, \times)$ that has what I am calling a "double cancellative" ...
Jonathan Hebert's user avatar
3 votes
1 answer
145 views

Is power-associativity an equational property?

A magma $M$ is said to be power-associative if the subalgebra generated by any element is associative. This can be written simply as $x^mx^n=x^{m+n}$ for all $m,n$ positive integers and $x\in M$, ...
Mario Carneiro's user avatar
2 votes
0 answers
46 views

Does the following property of the composition of a magma have a name?

If $M$ is a magma and $$+:M\times M\to M$$ is its law of composition, does the property $$(x+y)+z=x+(y+z)\qquad\forall\ x,y,z\in M :\quad y\neq x,z$$ have a name? It resembles the associativity of ...
Giorgio Comitini's user avatar
2 votes
1 answer
1k views

Associativity in category theory [closed]

In Category Theory, the composition of morphisms must be associative. What would happen if we give up this associative law? For example Lie algebras are vector spaces with non-associative binary ...
bill's user avatar
  • 69
16 votes
6 answers
1k views

Just How Strong is Associativity?

A friend of mine is using a lot of algebra that is not associative for an advanced Chemistry project. We were discussing it recently and I found it rather amusing how often she said things like "...
Shaun's user avatar
  • 45.8k
5 votes
2 answers
185 views

Existence of an operation $\cdot$ such that $(a*(b*c))=(a\cdot b)*c$

When we can define a binary operation $\cdot:M\times M\rightarrow M$ on an algebraic structure $(M,*)$ such that $$a*(b*c)=(a\cdot b)*c$$ If $*$ is associative then $\cdot=*$ even if I'm not sure ...
MphLee's user avatar
  • 2,512
0 votes
1 answer
412 views

Discuss whether or not the following binary operations are commutative, associative, ...

Discuss whether or not the following binary operations are commutative, associtive, have neutral elements and for which elements there are inverse elements. In between are what I have said, but if it ...
tedg's user avatar
  • 111
13 votes
6 answers
2k views

Associativity test for a magma

Say I have the operation table for a magma. I want to know whether or not the operation is associative. However, associativity is defined for an operation on 3 elements, and the operation table deals ...
Matthew Matic's user avatar
62 votes
7 answers
20k views

Is there an easy way to see associativity or non-associativity from an operation's table?

Most properties of a single binary operation can be easily read of from the operation's table. For example, given $$\begin{array}{c|ccccc} \cdot & a & b & c & d & e\\\hline a &...
celtschk's user avatar
  • 43.7k