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0 votes
1 answer
180 views

Why does isospin symmetry survive chiral symmetry breaking?

In QCD there is a breaking of chiral symmetry such that, for the lightest quarks only, we have $$\langle \overline{u} u \rangle = \langle \overline{d} d \rangle = \mathrm{const.}$$ where the constant ...
Kris's user avatar
  • 841
0 votes
1 answer
70 views

Do we have an analytic calculation to derive $\frac{F^2}{4}\,\text{Tr}\left\{\partial_\mu U\partial^\mu U^{\dagger}\right\}$ from the QCD Lagrangian?

I have studied the quark condensate and chiral perturbation theory. However, I am not sure where the "kinetic term" of the pion $$\frac{F^2}{4}\operatorname{Tr}\left\{\partial_\mu U\partial^...
StupiXPerson's user avatar
3 votes
2 answers
161 views

How do we known that $\langle \bar{\psi}_i \psi_j\rangle=(250 MeV)^3\delta_{ij}$?

I have started to read the phenomenology of QCD in low energy regime. I understand that, from the QCD renormalization group equation, the QCD becomes nonperturbative theory when energy scale is below $...
StupiXPerson's user avatar
9 votes
2 answers
796 views

How is the pion related to spontaneous symmetry breaking in QCD?

In chapter 19 of An Introduction to Quantum Field Theory by Peskin & Schroeder, they discuss spontaneous symmetry breaking (SSB) at low energies in massless (or nearly massless) QCD, given by $$\...
Flynn Linton's user avatar
2 votes
0 answers
69 views

Goldstone bosons in 2 and 3 quark flavor symmetries [closed]

In my (undergraduate) advanced elementary particles class last semester, we learnt that for a 2 quark (u/d) model the symmetry of the Lagrangian is (and breaks as) $$ U(2)_L \otimes U(2)_R = SU(2)_L \...
Yaezir's user avatar
  • 23
4 votes
1 answer
302 views

Global symmetries QCD goldstone bosons

Beside the local $SU(3)$-Color-symmetrie The QCD Lagrangian also has global symmetries: $$L_{QCD}=\sum_{f,c}\bar{q_{fc}}(i\gamma^\mu D_\mu - m ) q_{fc} - \frac{1}{4}F^a_{\mu \nu} F^{a \mu \nu} $$ $SU(...
taxus1's user avatar
  • 63
0 votes
1 answer
185 views

How does the Nambu-Goldstone mode explain the absence of parity doubling?

I've been doing some reading about chiral symmetry breaking since it was not touched in my particle physics course I found these slides As explained in the above link, if we take $|\psi \rangle$ as ...
Monopole's user avatar
  • 3,464
3 votes
0 answers
267 views

Why is the chiral condensate a negative quantity?

The chiral condensate serves as an order parameter for the chiral phase transition. Thus, it is a finite quantity in one phase and vanishes in the other phase. It is given as a vacuum expectation ...
Bernd's user avatar
  • 457
3 votes
0 answers
69 views

Restoration of symmetry explicitly broken by anomaly

What is the meaning of the restoration at finite temperature of a symmetry that is "broken" by the presence of an anomaly. If the symmetry is not there why is it restored at finite ...
Kvothe's user avatar
  • 861
0 votes
0 answers
76 views

Are the arrangements of quarks in hadron ground-state wavefunctions rotationally symmetric?

The Hamiltonian of quantum chromodynamics (like the rest of the Standard Model) is rotationally symmetric. My question is whether these space symmetries are spontaneously broken in the ground state of ...
tparker's user avatar
  • 48.4k
3 votes
1 answer
170 views

$U(1)_A$ effects on the baryons?

We know that the axial $U(1)_A$ is anomalous thus not a global symmetry. Therefore there is no direct associated pseudo goldstone boson for $U(1)_A$. This makes the $\eta'$ much more massive than the ...
ann marie cœur's user avatar
1 vote
1 answer
327 views

Quark condensate and spontaneous symmetry breaking?

It is known the quark condensate $<\bar{\psi}^{i}_L\psi^j_R>=\sigma \delta^{ij}$($i,j$ are flavour indices ) breaks the symmetry group $SU(N_f)_L\times SU(N_f)_R$. Because it is only invariant ...
Sven2009's user avatar
  • 995
0 votes
1 answer
181 views

Chiral symmetry in massless QCD

The QCD Lagrangian for two flavors is: $-\frac{1}{4} G\tilde{G}+i\bar{u}\displaystyle{\not} D u+i\bar{d} \displaystyle{\not} D d-m_u\bar{u} u-m_d\bar{d}d$ or alternaively $-\frac{1}{4} G\tilde{G}+i\...
user avatar
2 votes
1 answer
531 views

Peskin's treatment of Pions as Goldstone Bosons

After restoring the mass terms in the Lagrangian \begin{align} \mathcal{L}=\bar{u} i \not D u+\bar{d i} \not D d-m_{u} \bar{u} u-m_{d} \bar{d} d, \end{align} one obtains equations of motion for the ...
user4580791's user avatar
3 votes
0 answers
360 views

Pion mass in theta vacuum

Does the mass of the charged pion depend on the QCD vacuum angle? I've seen it said---e.g., in these TASI lectures---that when the quark mass matrix is real and there is a nonzero QCD vacuum angle $\...
plusplusplus's user avatar
1 vote
2 answers
240 views

Sufficient and Necessary Conditions for Chiral Symmetry Breaking

In their 2005 paper, the authors write (just below eq. 3.19) we see that a non-zero value of $F_0$ is a necessary and sufficient criterion for spontaneous chiral symmetry breaking. On the other ...
ersbygre1's user avatar
  • 2,648
2 votes
1 answer
260 views

Why is the approximate $\rm U(2)\times U(2)$ global symmetry of QCD that has a special importance?

I was looking at Peskin and Schroeder (Section 19.3, page $667-668$). They talk about $\rm U(2)\times U(2)$ symmetry for the QCD Lagrangian in the limit of massless $u$ and $d$ quarks. However, this ...
SRS's user avatar
  • 26.8k
1 vote
1 answer
279 views

Group structure of QCD‘s chiral symmetry (breaking)

With $3$ flavors of massless quarks, the QCD Lagrangian is invariant under flavor transformations$$SU(3)_V\ \otimes\ SU(3)_A\ \otimes\ U(1)_V\ \otimes\ U(1)_A.$$ Now, this is equivalent to $$SU(3)_R\ \...
ersbygre1's user avatar
  • 2,648
1 vote
2 answers
379 views

Derivation of Casher-Banks relation

Consider two-point function $\langle \bar{\psi}\psi\rangle$ in a model with massive fermions $\psi$ and gauge field: $$ \langle \bar{\psi}\psi\rangle =\frac{1}{V}\sum_{n} \frac{1}{\lambda_{n} +im}, $$...
Name YYY's user avatar
  • 8,901
4 votes
1 answer
248 views

Simple explanation of the QCD VEV in terms of instantons

I've heard that instantons in QCD generate quark bilinear condensate $\langle \bar{q}_{L}q_{R}\rangle$ which is responsible for spontaneous symmetry breaking. Is there any clear and simple way to ...
Name YYY's user avatar
  • 8,901
2 votes
0 answers
86 views

No global monopoles in QCD

If a global symmetry gets both spontaneously and explicitly broken, the explicit symmetry breaking pattern is crucial for understanding the formation of topological defects. For example, in the axion ...
Thomas's user avatar
  • 1,783
1 vote
0 answers
46 views

Do hierarchical condensates yield instantaneous or sequential symmetry breaking?

I am wondering whether the formation of a hierarchical vacuum condensate yields an instantaneous or sequential symmetry breaking in a cosmological phase transition. Let me illustrate this question ...
Thomas's user avatar
  • 1,783
1 vote
2 answers
1k views

Breaking of $SU(3)$ symmetry by bi-fundamental representation

Are there any general theorems which fix the possible symmetry breaking patterns of Lie groups (such as $SU(3)$) by vacuum expectation values of fields in specific representations (such as the quark ...
Thomas's user avatar
  • 1,783
2 votes
1 answer
141 views

gauge-invariant 6-quark order parameter

In this Review paper in p.1462, bottom left: Rev.Mod.Phys.80:1455-1515,2008 -- Color superconductivity in dense quark matter It says that "There is an associated gauge-invariant 6-quark order ...
ann marie cœur's user avatar
0 votes
1 answer
147 views

chiral symmetry condensate and 2SC, CFL breaking C, P and T symmetry?

Because we know that chiral symmetry condensate causes the chiral symmetry breaking, and it produces Goldstone modes of pseudo-scalars, so I believe that chiral symmetry breaking also breaks the T ...
ann marie cœur's user avatar
8 votes
1 answer
2k views

Peccei-Quinn-symmetry and effective Lagrangian for the Axion field

To solve the strong CP-problem Peccei and Quinn suggested the use of a new $U(1)$-symmetry called the PQ-symmetry. For this symmetry they constructed an effective Lagrangian involving the Nambu-...
Alpha001's user avatar
  • 1,114
3 votes
1 answer
403 views

Scalar pseudo-Goldstones from hypothetical $SU(3)_V$ symmetry breaking in QCD

The eight light pseudoscalar mesons of QCD are the pseudo-Goldstone bosons of the spontaneously broken chiral (axial) $SU(3)_A$ quark flavor symmetry. If we consider the hypothetical case of also ...
Thomas's user avatar
  • 1,783
1 vote
0 answers
195 views

Why does the $U(2n)$ flavor symmetry break down to a $U(1)$ group and an $SU(2n)$ group?

I am studying quantum field theory using Srednicki's textbook. Problem 83.1 is: Suppose that the color group is $G_C=SO(3)$ rather than $SU(3)$, and that each quark flavor is represented by a Dirac ...
Shen's user avatar
  • 1,653
9 votes
1 answer
739 views

Why do we have a non-zero quark vacuum condensate even though the QCD coupling goes to zero in the deep infrared?

It is well-known that QCD has a Landau pole at $\Lambda_{\rm QCD}\sim 200$ MeV, which means that the perturbative QCD coupling becomes strong at this scale. Conventionally, this is claimed to be the ...
Thomas's user avatar
  • 1,783
4 votes
1 answer
2k views

Question about the linear sigma-model

Suppose the linear sigma-model lagrangian: $$ L = \bar{N}(i\gamma_{\mu}\partial^{\mu}-g_A \phi)N + |\partial_{\mu}\phi|^{2} - V(|\phi|) - c\sigma , $$ where $$ N = \begin{pmatrix} p \\ n\end{pmatrix}, ...
Name YYY's user avatar
  • 8,901
1 vote
0 answers
410 views

How to find the explicit value of the fermion vacuum expectation value?

In the derivation for Goldstone modes, a pdf I found online (scipp.ucsc.edu/~dine/ph222/goldstone_lecture.pdf) says it's believed the above-mentioned expectation value $\langle \bar{ \psi} \psi \...
pyroscepter's user avatar
3 votes
1 answer
483 views

Relevance of the condensate $\langle 0 | \bar q q | 0 \rangle$ to SSB of chiral QCD symmetry

The QCD lagrangian with two massless flavours of quarks takes the form $$\mathcal L = \sum_{i=u,d} i \bar q_i \gamma_{\mu} D^{\mu} q_i.$$ Defining operators to project out the left and right handed ...
CAF's user avatar
  • 3,569
14 votes
1 answer
3k views

Physical meaning of the chiral condensate in QCD

Considering the QCD Lagrangian in the chiral limit, where all the quarks masses are set to zero. Then the Lagrangian has the following chiral symmetry: $$ SU(L)_{V} \times SU(L)_{A} \times U(1)_{V} \...
ottavio 's user avatar
2 votes
1 answer
239 views

Chiral current VEV below the QCD scale

Let's have pure QCD. I know that after spontaneous symmetry breaking quark bilinear form are replaced by their averaged values: $$ \bar{q}_{i}q_{j} \to \langle \bar{q}_{i}q_{j}\rangle \approx \Lambda_{...
Name YYY's user avatar
  • 8,901
9 votes
1 answer
807 views

Spontaneous symmetry breaking of anomalous global abelian symmetries and $U(1)$ of QCD

Let me restate the $U(1)$ problem of QCD: Let us forget about the $s$ quark, and consider the $u$ and $d$ massless. This is a good approximation since $m_{u,d} \ll \Lambda_{QCD}$. Then $\mathscr{...
EEEB's user avatar
  • 498
7 votes
1 answer
479 views

Massive Gauge Bosons without Higgs fields

In a possible theory like our Standard model but without a Higgs i.e.: $$ \mathcal{L}=i\bar{\Psi}_f\gamma_\mu D^\mu\Psi_f-\text{Tr}[G^b_{\mu\nu}G^{b\,\mu\nu}] $$ where $b,f$ run over the typical ...
Nontriviality's user avatar
1 vote
1 answer
149 views

Interpretation of vector mesons in QCD

It is well-known that scalar mesons are interpreted as pseudogoldstone bosons which is connected with spontaneous broken $SU(3) \times SU(3)$ symmetry to $SU(3) \times SU(3) / SU(3)_{chiral}$. Is ...
Andrew McAddams's user avatar
11 votes
1 answer
528 views

From which dimensionful constants does proton mass arise?

It is well known that the most of the proton (or any other hadron with light quarks) mass is not made up from quark masses, but it is dynamically generated by QCD mess inside. I've also heard that, ...
Varin Esan's user avatar
5 votes
2 answers
1k views

Origin of quark masses

Does all the mass of the quarks in the standard model come from the Higgs sector or is there also a contribution to quark masses due to QCD chiral symmetry breaking?
SRS's user avatar
  • 26.8k
3 votes
1 answer
1k views

Dilaton field and Scale symmetry breaking

I have read at some places that a dilaton field is associated with the spontaneous breaking of scale symmetry in a theory. (While others would be difficult to trace right now, the most easily ...
User Anonymous's user avatar
8 votes
1 answer
361 views

Intuitive explanation of how hadron mass emerges from the strong force

I'm not familiar with QCD, but I'm looking for intuitive explanation of this phenomenon (it could be that easy explanation does not exist). What I've read is that large part of hadron masses arises ...
krzysztoft's user avatar
11 votes
1 answer
470 views

What's the heuristic reasoning for Chiral Symmetry breaking

In Peskin and Schroeder (page 669), and other references, the heuristic reasoning for why one would expect chiral symmetry breaking at low energies is that quark masses are small and hence it's not ...
user26866's user avatar
  • 3,492
2 votes
3 answers
886 views

The status of $SU(3)_C$ symmetry in the Standard Model

In the Standard Model of Particle physics the $SU(2)_{EW}$ symmetry and the $SU(2)$ isospin symmetry are broken. What about $SU(3)_C$? Is it broken too? if YES, what breaks the symmetry? If NO, what ...
Murod Abdukhakimov's user avatar