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Questions tagged [axiom-of-choice]

An important and fundamental axiom in set theory sometimes called Zermelo's axiom of choice. It was formulated by Zermelo in 1904 and states that, given any set of mutually disjoint nonempty sets, there exists at least one set that contains exactly one element in common with each of the nonempty sets. The axiom of choice is related to the first of Hilbert's problems.

14 votes
1 answer
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Are Berkeley cardinals easier to refute in ZFC than Reinhardt cardinals?

Kunen showed that Reinhardt cardinals are inconsistent in ZFC. But his proof is a bit technical for a non-set-theorist to follow. Berkeley cardinals are stronger than Reinhardt cardinals. You can ...
Tim Campion's user avatar
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3 votes
0 answers
144 views

Can well-ordering of the universe due to global choice survive extensive failure of Extensionality?

That axiom of global choice leads to the well-ordering of the universe given the other axioms of Zermelo set theory is a famous result. Now, if we weaken the power set axiom to the axiom stating that ...
Zuhair Al-Johar's user avatar
12 votes
2 answers
411 views

Trading Choice for Comprehension (or Replacement)

This question is basically a request for clarification about a remark made by Sam Sanders in a comment to another question: IIUC what he's saying, there are statements that can be proved either with a ...
Gro-Tsen's user avatar
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9 votes
3 answers
416 views

Exponentiation of Dedekind cardinals

Question: Let $\mathfrak n$ be an infinite cardinal. In ZF (set theory without the axiom of choice) can either of the implications $$\mathfrak n=\mathfrak n+1\implies2^\mathfrak n=2^{\mathfrak n+1}\...
bof's user avatar
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6 votes
1 answer
277 views

The Parity Principle and $\mathbf{C}_2$ (choice for $2$-sets)

The Parity Principle states that if $X\neq \emptyset$ is a set, then there is $\mathcal B\subseteq \mathcal P(X)$ such that whenever $a,b\in \mathcal P(X)$ with $a\mathbin\Delta b = \{x\}$ for some $...
Dominic van der Zypen's user avatar
15 votes
1 answer
1k views

Parity and the Axiom of Choice

Motivation. The three-dimensional cube can be formalized by $\mathcal P(\{0,1,2\})$ where vertices $x,y\in\mathcal P(\{0,1,2\})$ are connected by an edge if and only if their symmetric difference $x\...
Dominic van der Zypen's user avatar
6 votes
0 answers
279 views

Models of ZF (without Inaccessible cardinals) where only the full Axiom of Choice fails, but the Axiom of Countable Choice remains true?

Solovay's model (which assumes $I$ = "existence of inaccessible cardinal") will be a well-known construction to produce a model of ZF where only the full Axiom of Choice ($AC$) fails, but ...
Yauhen Yakimovich's user avatar
3 votes
1 answer
279 views

What are some "easy" violations of $\mathsf{SVC}$?

By $\mathsf{SVC}$, I mean "small violations of choice", which is the statement $$(\exists S)(\forall X)(\exists f)``f\colon S\times\text{Ord}\to X\text{ is a surjection}".$$ Such an $S$ is ...
Calliope Ryan-Smith's user avatar
40 votes
3 answers
5k views

How much of mathematical General Relativity depends on the Axiom of Choice?

One of the cornerstones of the mathematical formulation of General Relativity (GR) is the result (due to Choquet-Bruhat and others) that the initial value problem for the Einstein field equations is ...
Pelota's user avatar
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21 votes
4 answers
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How much of the axiom of choice do you need in mathematics?

Say we have DC-λ where λ is some inaccessible cardinal. Is that enough to develop all of ordinary mathematics? If not, is there a strengthening that is but that nevertheless does not assume full ...
Someone211's user avatar
4 votes
0 answers
146 views

The monochromatic principle and the axiom of choice

For any set $A\neq\emptyset$, denote by $[A]^A$ the collection of sets $B\subseteq A$ such that there is a bijection $\varphi:B\to A$. If ${\cal S}\subseteq [A]^A$, we say that $B\in[A]^A$ is ...
Dominic van der Zypen's user avatar
7 votes
0 answers
165 views

"Minimal-ish" Dedekind-finite cardinalities of models

Throughout, we work in $\mathsf{ZF}+$ "There is an infinite Dedekind-finite set." Say that a Dedekind-finite cardinality $\kappa$ is $\Sigma^1_1$-isolated iff there is some first-order ...
Noah Schweber's user avatar
3 votes
2 answers
203 views

Posets such that the collection of principal down-sets does not have property ${\bf B}$

We say that a hypergraph $H=(V,E)$ has property ${\bf B}$ if there is $S\subseteq V$ such that for all $e\in E$ with $|e|>1$ we have $S\cap e \neq \emptyset \neq e \setminus S$. Let $(P,\leq)$ be a ...
Dominic van der Zypen's user avatar
5 votes
1 answer
132 views

References for the axiom of surjective comparability

The axiom $W_\kappa$, for $\kappa$ a cardinal, is the statement that for all sets $X$, either $|X|\leq\kappa$ (that is, there is an injection $X\to\kappa$) or $\kappa\leq|X|$. Is there literature on ...
Calliope Ryan-Smith's user avatar
3 votes
0 answers
172 views

Do the difficulties in generalising Henstock-Kurzweil still exist if every subset of $\mathbb R^n$ is Lebesgue measurable?

There are apparently some difficulties generalising the Henstock-Kurzweil integral from functions of signature $\mathbb R\to\mathbb R$ to functions of signature $\mathbb R^n \to \mathbb R$. One ...
wlad's user avatar
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