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Questions tagged [well-orders]

For questions about well-orderings and well-ordered sets. Depending on the question, consider adding also some of the tags (elementary-set-theory), (set-theory), (order-theory), (ordinals).

6 votes
0 answers
149 views

Existence of uncountable set of functions on natural numbers

For $f,g:\mathbb{N}\rightarrow \mathbb{N}$ we write $f\leq g$ iff $f(n)\leq g(n)$ for all $n\in \mathbb{N}$. Let $\mathcal{S}\subseteq \{f\vert f:\mathbb{N}\rightarrow \mathbb{N}\}$ be a set of ...
L. R.'s user avatar
  • 113
0 votes
1 answer
56 views

Reordering algorithm to fragment consecutive sequences of ones as much as possible

Recently, I came across the following problem: Let $s_1, s_2, ..., s_k$ be non-empty strings in $\{0,1\}^*$. We define $S_{s_1,s_2,...,s_k}$ as the concatenation of $s_1, s_2, \dots, s_k$. We call a &...
Thedby's user avatar
  • 1
0 votes
1 answer
41 views

Prove $\sum_{i=0}^n 2^i=2^{n+1}-1$ using WOP

So I defined my predicate $P(n)$ according to the theorem, and then I said there there exists an integer $n\ge0$ such that $P(n)$ is false. And I let $C$ be the set of all such $n$. And by WOP, there ...
Maddie VePrice's user avatar
0 votes
0 answers
46 views

Prove that an infinite well ordered set X has equal cardinality to the set X∪{a}, where 'a' does not belong to X.

Found this question in a book of analysis as a corollary. Before the question is introduced (as an exercise), the book introduced Theorem of Recursion on Wosets and Comparability Theorem. For ...
Arbbor1's user avatar
-1 votes
1 answer
52 views

Is this set uncountable? $A = \{A_n \colon n \in \mathbb{N}\}$ where $A_n$ is the set $\mathbb{N}$ with the number $n$ removed from it

The set in the title is presented in this answer as an example of a similar set to the $P(\mathbb{N})$ (in the context of explaining the necessity of the axiom of choice in the existence of a well ...
lucas's user avatar
  • 39
2 votes
0 answers
75 views

Law of Trichotomy for Well-Orderings

Often in beginning set-theory courses, and in particular in Jech's book Set Theory, it is proved from scratch that given any two well-orderings, they are isomorphic or one is isomorphic to an initial ...
rea_burn42's user avatar
2 votes
1 answer
85 views

Given two well-orders $\langle A,R \rangle$ and $\langle B,S \rangle$, one of the following holds.

Let $\langle A,R \rangle$ and $\langle B,S \rangle$ be two well-orders, and let $\text{pred}(A,x,R) := \{y \in A \;|\; yRx\}$ and similarly for $\text{pred}(B,z,S)$. It is claimed that one of the ...
Ben123's user avatar
  • 1,307
3 votes
1 answer
73 views

Is it consistent with ZC that a well-order of type $\omega_\omega$ does not exist?

Working in Zermelo's set theory (with choice for simplicity) - the construction in Hartogs' theorem shows that starting with a set $X$, there is a set $X'$ in at most $\mathcal{P}^4(X)$ (where $\...
Chad K's user avatar
  • 4,963
0 votes
1 answer
51 views

Detemine whether the interval [4,8] is well-ordered. Explain.

I don't think this interval is well-ordered because the subset (4,8) would not have a smallest value. I'm stuck on how to show (4,8) has no smallest value.
Abigail Webb's user avatar
3 votes
1 answer
95 views

Order type of N and Q

Studying linear orderings, I learned two theorems. Suppose two linearly ordered sets A and B satisfy the following: (1) countably infinite, (2) dense, i.e. if x<z then there exists y such that x&...
Lim do's user avatar
  • 53
0 votes
0 answers
37 views

The arithmetic of first uncountable ordinal number

I think, I know the proof of 1+ω0 = ω0. (ω0 is countable ordinal s.t ω0=[N]). To prove this, I can define a function f: {-1,0,1,2,...}->{0,1,2,...} by f(x)=x+1. But if ω1 is first uncountable ...
Mathforest's user avatar
1 vote
3 answers
1k views

Shouldn't the Well Ordering Principle apply only to sets with at least two elements?

From what I've been taught in school, the well-ordering principle states that every non-empty set must have a least element. To me, the least element of some set $X$ is an element $a$ such that, for ...
Mailbox's user avatar
  • 927
3 votes
1 answer
80 views

Hessenberg sum/natural sum of ordinals definition

I was given the following definition of Hessenberg sum: Definition. Given $\alpha,\beta \in \text{Ord}$ their Hessenberg sum $\alpha \oplus \beta$ is defined as the least ordinal greater than all ...
lelouch_l8r4's user avatar
5 votes
1 answer
75 views

Exercise 7.1.6 Introduction to Set Theory by Hrbacek and Jech

This is exercise 7.1.6 of the book Introduction to Set Theory 3rd ed. by Hrbacek and Jech. Let $h^{*}(A)$ be the least ordinal $\alpha$ such that there exists no function with domain $A$ and range $\...
Alphie's user avatar
  • 4,827
0 votes
1 answer
106 views

Prove that $\mathbb N \times \mathbb N$ is well ordered under $\le$

We define an ordering $\mathbb N \times \mathbb N$, $\le$ as follows: $(a, b) \le (c, d)$ iff $a \le c$ and $b \le d$. I tried to prove that $\mathbb N \times \mathbb N$ is well ordered under this ...
Vector's user avatar
  • 377

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