Skip to main content

All Questions

Tagged with
0 votes
0 answers
55 views

Is every strict ordering by inclusion a well-ordering?

Given a set $s$ which is transitive and completely ordered by inclusion, that is, such that $z \in s \rightarrow z \subset s$ and $\left( x \in s \wedge y \in s \wedge x \neq y \right) \rightarrow \...
Mark Fischler's user avatar
5 votes
3 answers
488 views

Motivation of inventing concept of well-ordered set?

I've started studying set theory for a while. I understand what is an ordered sets but i still fail to see what motivated mathematicians to invent these concept. Could you please enlightment me ? ...
InTheSearchForKnowledge's user avatar
1 vote
1 answer
72 views

Is there something missing in Jech's proof of Zermelo's Well-Ordering Theorem?

Here is the proof from p. 48 of the Millennium Edition, corrected 4th printing 2006: My question: how do we know that there is any ordinal $\theta$ such that $A=\{a_\xi\,\colon\xi<\alpha\}$? ...
Nat Kuhn's user avatar
  • 307
3 votes
2 answers
98 views

Proving the shortlex ordering is a well-ordering

Let $(A,<)$ be a nonempty linearly ordered set, and let $\operatorname{Seq}(A)$ denote the set of finite sequences of elements of $A$. That is, $f\in\operatorname{Seq}(A)$ is a function $f:n\to A$, ...
John's user avatar
  • 4,442
2 votes
0 answers
106 views

How does one prove without the axiom of choice that the product of a collection of nonempty well-ordered sets is nonempty?

Suppose $\{X_{\alpha}\}_{\alpha\in\mathcal A}$ is an indexed family of nonempty well-ordered sets, where $X_{\alpha}=(E_{\alpha},\le_{\alpha})$ for each $\alpha$. It seems intuitively obvious that we ...
Joe's user avatar
  • 20.8k
0 votes
1 answer
64 views

Partial order on sets and application of Zorn's Lemma to construct well-ordered subset

I would appreciate help with the following question: Let $(A,<)$ a linear ordered set. a. Let $F\subseteq P(A)$. Prove that the following relation is a partial order in $F$: $X\lhd Y$ for $X,Y\in F$...
eitan.sh21's user avatar
1 vote
1 answer
81 views

Any subset of a well-ordered set is isomorphic to an initial segment of this well-ordered set.

I wanted to prove the fact for which I have a sketch of proof: Let $(W,\leq )$ be a well-ordered set and $U$ be a subset of $W$. Then considering the restriction of $\leq $ to $U\times U$, we have ...
boyler's user avatar
  • 375
2 votes
1 answer
42 views

Are these two notions of weak well-foundedness equivalent?

Background (optional): I have a state transition system $Q$ with two "kinds" of transitions: progress-making ($\delta_P : Q \times \Sigma \rightarrow Q$) and non-progress making ($\delta_N : ...
soktinpk's user avatar
  • 685
1 vote
1 answer
121 views

Partition of $\mathbb R$ in convex subsets/badly ordered sets

Background: These questions come from two different exercises, but since the first is much shorter and of the same kind of one of the others, I preferred to put everything in only one thread. (We work ...
lelouch_l8r4's user avatar
6 votes
0 answers
149 views

Existence of uncountable set of functions on natural numbers

For $f,g:\mathbb{N}\rightarrow \mathbb{N}$ we write $f\leq g$ iff $f(n)\leq g(n)$ for all $n\in \mathbb{N}$. Let $\mathcal{S}\subseteq \{f\vert f:\mathbb{N}\rightarrow \mathbb{N}\}$ be a set of ...
L. R.'s user avatar
  • 113
2 votes
0 answers
75 views

Law of Trichotomy for Well-Orderings

Often in beginning set-theory courses, and in particular in Jech's book Set Theory, it is proved from scratch that given any two well-orderings, they are isomorphic or one is isomorphic to an initial ...
rea_burn42's user avatar
2 votes
1 answer
85 views

Given two well-orders $\langle A,R \rangle$ and $\langle B,S \rangle$, one of the following holds.

Let $\langle A,R \rangle$ and $\langle B,S \rangle$ be two well-orders, and let $\text{pred}(A,x,R) := \{y \in A \;|\; yRx\}$ and similarly for $\text{pred}(B,z,S)$. It is claimed that one of the ...
Ben123's user avatar
  • 1,307
3 votes
1 answer
73 views

Is it consistent with ZC that a well-order of type $\omega_\omega$ does not exist?

Working in Zermelo's set theory (with choice for simplicity) - the construction in Hartogs' theorem shows that starting with a set $X$, there is a set $X'$ in at most $\mathcal{P}^4(X)$ (where $\...
Chad K's user avatar
  • 4,963
1 vote
3 answers
1k views

Shouldn't the Well Ordering Principle apply only to sets with at least two elements?

From what I've been taught in school, the well-ordering principle states that every non-empty set must have a least element. To me, the least element of some set $X$ is an element $a$ such that, for ...
Mailbox's user avatar
  • 927
3 votes
1 answer
80 views

Hessenberg sum/natural sum of ordinals definition

I was given the following definition of Hessenberg sum: Definition. Given $\alpha,\beta \in \text{Ord}$ their Hessenberg sum $\alpha \oplus \beta$ is defined as the least ordinal greater than all ...
lelouch_l8r4's user avatar

15 30 50 per page
1
2 3 4 5
13