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90 questions with no upvoted or accepted answers
9 votes
0 answers
299 views

Set $S$ of integers $\ge0$ such that $\{1,2,\cdots,n\}$ partitions into $A, B$ with $\sum_\limits{a\in A}a^k=\sum_\limits{b\in B}b^k$ for all $k\in S$

Let $s_n$ be the largest size of a set $S$ of integers $\ge0$ st there exist two subsets $A,B\subseteq \{1,2,...,n\}$ that satisfy the conditions (1) $A\cap B=\emptyset$, (2) $A\cup B=\{1,2,...,n\}$, (...
moray eel's user avatar
  • 184
6 votes
1 answer
143 views

Equality of Floors of some Partial Sums

Let $S_n=\frac{1}{0!}+\frac{1}{1!}+\frac{1}{2!}+\cdots+\frac{1}{n!}$ denote the $(n+1)^{st}$ partial sum in the series expansion for $e=\sum_{k\ge 0}\frac{1}{k!}$. I want to prove that $\lfloor n\cdot(...
hradaeck's user avatar
4 votes
0 answers
306 views

Closed form for Sum of Tangents with Angles in Arithmetic Progression

The formulae that can be used to evaluate series of sines and cosines of angles in arithmetic progressions are well known: $$\sum_{k=0}^{n-1}\cos (a+k d) =\frac{\sin( \frac{nd}{2})}{\sin ( \frac{d}{2} ...
A-Level Student's user avatar
4 votes
2 answers
78 views

Is $\left(\sum_{n=1}^N\frac{a_n}{N}\right)^N\left(\sum_{n=N+1}^{2N}\frac{a_n}{N}\right)^N≠\left(\sum_{n=1}^{2N}\frac{a_n}{2N}\right)^{2N}$?

Let $$G_N= \prod_{n=1}^Na_n$$ and $$A_N=\left(\frac{\sum_{n=1}^Na_n}{N}\right)$$ So $$G_{2N}= \prod_{n=1}^{2N}a_n \\ =\left(\prod_{n=1}^{N}a_n\right)\left(\prod_{n=N+1}^{2N}a_n\right) \\ ≤_{IH}\left(\...
DSL's user avatar
  • 1,359
4 votes
0 answers
54 views

Is there any error in my solution : If $\sum^n_{r=1} r^4=I(n), $ then $\sum^n_{r=1}(2r-1)^4$ is equal to ..

Problem : If $\sum^n_{r=1} r^4=I(n), $ then $\sum^n_{r=1}(2r-1)^4$ is equal to (a) $I(2n)-16I(n)$ (b) $I(3n)-2I(n)$ (c) $I(2n)-I(n)$ (d) $I(2n)+I(n)$ Please suggest if there is some error ...
Sachin's user avatar
  • 10k
3 votes
2 answers
117 views

$1\binom{20}1+2\binom{20}2+3\binom{20}3+\dots+19\binom{20}{19}+20\binom{20}{20}$

$$1\binom{20}1+2\binom{20}2+3\binom{20}3+\dots+19\binom{20}{19}+20\binom{20}{20}$$ I solved it by letting the sum be $S$, then adding the sum to itself but taking the terms from last to first and then ...
AltercatingCurrent's user avatar
3 votes
0 answers
100 views

Simplifying a subindex equation

Consider the following equation $$ \frac{e^{\sum_i \alpha_i x_i}}{\sum_i x_i}=\sum_k\frac{e^{\sum_i \alpha_i y_{i, k}}}{\sum_i y_{i, k}} $$ Is it possible to write $x_i$ as a function of the terms $y_{...
sam wolfe's user avatar
  • 3,435
3 votes
1 answer
46 views

Rewriting a system of two equations found in The Chemical Basis of Morphogenesis (A. Turing, 1952)

In reading The Chemical Basis of Morphogenesis by A. Turing, I am unable to follow a small section of his working. On page $47$, Turing states that \begin{align*} x_r&=\sum_{s=0}^{N-1} \exp\left(\...
M B's user avatar
  • 617
3 votes
0 answers
30 views

for what value of $y$ does $\sum_{k= 0}^n a_0 x^k = \sum_{k=0}^n y^k$

for what value of $y$ does $$\sum_{k= 0}^n a_0 x^k = \sum_{k=0}^n y^k$$ This was just an idea I was playing around with. I tried solving $$\frac{a_0(x^{n+1}-1)}{x-1} = \frac{y^{n+1}-1}{y-1} $$ This ...
infinitylord's user avatar
  • 4,844
3 votes
0 answers
287 views

$f(8) \geq 1$ and $f(n)\geq 2f(\lceil \frac n2-n^{2/3} \rceil)$. Can we deduce $\exists C>0: f(cn) \geq n$?

Let $f : \Bbb N \to \Bbb N$ be a nondecreasing function that satisfies $f(8) \geq 1$ and $f(n)\geq 2f(\lceil \frac n2-n^{2/3} \rceil)$. Can we deduce that there exists some positive constant $c$ such ...
Pachirisu's user avatar
  • 929
3 votes
0 answers
68 views

How many tests to validate an identity?

Discrete formulas such as the Faulhaber summations can be verified by evaluating them for a finite number of values. For example $$\sum_{k=1}^nk=\frac{n(n+1)}2$$ is validated by evaluating for $n=0,1,...
user avatar
3 votes
0 answers
283 views

Pull constant out of a summation of fractions

General problem $$ \sum_{i=1}^n \frac{a_i + x}{b_i + x} = 0 $$ Is it possible for solve for $x$? Some context I've hit a road block in my derivation... At this point, I need to pull the model ...
DavidS's user avatar
  • 31
3 votes
2 answers
176 views

Evaluate $S=\left|\sum_{n=1}^{\infty} \frac{\sin n}{i^n \cdot n}\right|$

Evaluate $$ S=\left|\sum_{n=1}^{\infty} \dfrac{\sin n}{i^n \cdot n}\right|$$ where $i=\sqrt{-1}$ For this question, I did the following, Let $$ \begin{align*} S &= \sum_{n=1}^{\infty} \...
user avatar
2 votes
0 answers
60 views

How to simplify $e^{-\sum_{i=-k}^k(k-|i|)x_i}$?

Consider the expression given by $$ \large e^{-\Large\sum_{i=-k}^k(k-|i|)x_i} $$ Is there a way of simplifying this expression? For example, provided $\{x_i\}$ is bounded and "smooth" enough ...
sam wolfe's user avatar
  • 3,435
2 votes
0 answers
39 views

Simplifying $\sum_{k=1}^{\log_{2}{n}}\log_{3}{\frac{n}{2^k}}$ in two ways gives different results

I want to calculate the result of $$\sum\limits_{k=1}^{\log_{2}{n}}\log_{3}{\frac{n}{2^k}}$$ I used two below approaches. Both approaches are based on $\log A + \log B = \log (A \times B)$ and $\sum\...
hasanghaforian's user avatar
2 votes
0 answers
78 views

value of $\frac{\sum_{k=0}^r{n\choose k}{n-2k\choose r-k}}{\sum_{k=r}^n {n\choose k}{2k\choose 2r} {(\frac{3}{4})}^{(n-k)}({\frac{1}{2}})^{2k-2r}}$ .

The question requires us to find the value of $\frac{\sum_{k=0}^r{n\choose k}{n-2k\choose r-k}}{\sum_{k=r}^n {n\choose k}{2k\choose 2r} {\left(\frac{3}{4}\right)}^{(n-k)}\left({\frac{1}{2}}\right)^{...
SOUMILI NAG's user avatar
2 votes
0 answers
60 views

Finding a formula for a sum that involves binomial coefficients

Is there a formula for this sum: $$ \sum_{j=0}^k {n \choose j} {n \choose k-j} (-2)^j \left(-\frac13 \right)^{k-j} ?$$ It reminds me to Vandermonde's identity; but as you can see there is a slight ...
rowcol's user avatar
  • 897
2 votes
0 answers
143 views

I've come up with two ways to evaluate $\sum_{1 \le j<k\le n} \frac{k}{k-j}$ but only one of them works

I've come up with two ways to solve this double sum but only one of them works: $$ \sum_{1 \le j<k\le n} \frac{k}{k-j}$$ My first approach is to change $k-j$ into a single $k$. So we have the ...
MathematicsBeginner's user avatar
2 votes
2 answers
82 views

Using trigonometric power formulas to derive an identity for $\cos^3(x)$

I am practicing with manipulating sigma notation and binomial coefficients right now. I am using the formula given here to derive the identity for $\cos^3(x)$ The identity for $\cos^3(x)$ is $$\cos^3(...
James Warthington's user avatar
2 votes
0 answers
137 views

Can this summation be done without calculator?

Is it possible to perform the summation , $$\sum_{i=1}^{\infty} \frac{1}{i^i}$$ without the use of calculator? It does converge to a finite value = 1.29129... Wolfram Alpha link to this Describe the ...
Saket Gurjar's user avatar
  • 1,663
2 votes
0 answers
115 views

Double Summation Multiplication

There is some simplification, similar to Lagrange's identity, for the multiplication of double summation ? Double Summation: $\left( \sum\limits_{\substack{m=1}}^N \sum\limits_{\substack{n=1}}^N a_{...
Bruno Felipe's user avatar
2 votes
0 answers
38 views

Upper bound on $\frac{v_{1}}{1-c_{1}x}+\cdots+\frac{v_{n}}{1-c_{n}x}$

Let $v_{1},\ldots,v_{n}$ and $c_{1},\ldots,c_{n}$ be real numbers such that $v_{i}=2\alpha_{i}^{2}$ and $c_{i}=2\alpha_{i}$ for some $\alpha\ge 0$. My question is the following: Can I get, for $x\ge 0$...
nemo's user avatar
  • 638
2 votes
0 answers
256 views

Foil in a Summation

I have the following summation, where I find the following result $ \sum_{i}^n {(a+b_i)(c+d_i)} $ $ \sum_{i}^n {(ac+ad_i + bc_i + b_id_i)} $ However others have told me that I am missing a "N" ...
bsmith144's user avatar
2 votes
2 answers
70 views

Question on changing the index of summation

$$b(a+b)^m = \sum_{j=0}^m \binom{m}{j}a^{m-j}b^{j+1}= \sum_{k=1}^m \binom{m}{k-1}a^{m+1-k}b^{k}+b^{m+1}$$ I believe $j = k-1$ though the book does say that. This is related to proving the binomial ...
user372344's user avatar
2 votes
0 answers
150 views

Evaluate this product $n \times \frac{n-1}{2} \times \dots \times \frac{n-(2^k-1)}{2^k}$

For $k = \lfloor \log_{2}(n+1) \rfloor - 1$ evaluate $n \times \frac{n-1}{2} \times\frac{n-3}{4} \times \frac{n-7}{8} \times \dots \times \frac{n-(2^{k}-1)}{2^k}$ So the product goes up to $k$ and I ...
Lewis's user avatar
  • 69
2 votes
0 answers
105 views

How does one change the top number in a summation?

Sorry I do not know the correct term (I am guessing "upper limit"). Here is what I mean. $$\sum\limits_{i=1}^{\color{red}{17}}\frac{2i}{i+3}$$ The $17$ is what I am talking about as "the top number". ...
Anonymous Computer's user avatar
2 votes
0 answers
48 views

Are there efficient ways of computing sums that involve trigonometric functions and q-logarithms (Tsallis q-logarithms)?

I am interested in computing the following sum: \begin{equation} \sum\limits_{l=1}^k l^{\beta_1} \cos\left(\omega \log_q(\frac{l}{t_c})\right) \end{equation} Here $0 < \omega$, $0 < k < ...
Przemo's user avatar
  • 11.5k
2 votes
0 answers
730 views

Analytical solution for a variable inside of a summation

I am trying to figure out how to solve the following expression for $x$ and I'm surprised that I don't know what to do. $$\frac{2n}{x} = \sum_{i=1}^{n} \frac{1}{x-y_{i}}$$ We have that $n$ and $x$ ...
Samuel Reid's user avatar
  • 5,102
1 vote
0 answers
137 views

Simple algebra in rearring terms

I have a very simple mathematical question, and it is just about algebra which seems very tedious. First, let me state my problem from the beginning: Let $i$ be an index representing countries ($i = {...
Maximilian's user avatar
1 vote
0 answers
103 views

Restructuring Jacobi-Anger Expansion

In Jacobi-Anger expansion, $$e^{\iota z \sin(\theta)}$$ can be written as: $$e^{\iota z \sin(\theta)} = \sum_{n=-\infty}^{\infty} J_n(z)e^{\iota n \theta}$$ where $J_n(z)$ is the Bessel function of ...
SiPh's user avatar
  • 31
1 vote
0 answers
92 views

Example of a specific polynomial

I need four non-trivial polynomials $P(x)$, $Q(y)$, $R(z)$ and $S(w)$ such that $$P(x)Q(y)R(z)S(w)=\sum_{i}a_i b_i c_i d_i x^i y^i z^i w^i+ \sum_{j\neq k\neq l\neq m}e_j f_k g_l h_m x^j y^k z^l w^m $$ ...
Max's user avatar
  • 918
1 vote
0 answers
47 views

Multiple Sigma Notation and Expected Value

I've been struggling with expected value calculations that involve multiple or nested sigma notations. For instance, the solution to a problem I was working on is: $X=\Sigma_{i=1}^{10}X_i\implies E[X]...
user601846's user avatar
1 vote
0 answers
39 views

Is this a valid proof method (and how to complete it) of the exchange of order of indexed summations?

I want to prove that $$ \sum_{1 \leqq i \leqq a} \sum_{1 \leqq j \leqq b} f(i, j) = \sum_{1 \leqq j \leqq b}\sum_{1 \leqq i \leqq a} f(i, j) $$ Which is a very simple statement, but also a bit vexing ...
peritremic's user avatar
1 vote
0 answers
139 views

Solving a geometric-harmonic series

Find the value of $\displaystyle \frac21- \frac{2^3}{3^2}+ \frac{2^5}{5^2}- \frac{2^7}{7^2}+ \cdots$ till infinite terms. found this problem while integrating $\arctan\left(x\right)/x$ from $0$ to $2$ ...
Ashman Wadhawan's user avatar
1 vote
0 answers
86 views

Limit of a sum and two ways yielding two answers

$$\lim_ {n\to \infty} \sum_{r=0}^n \frac{1}{(2r+1)(2r+3)(2r+2)}$$ Now, what I did here was to first break up the general term of the sum using partial fractions, yielding $$ \frac{1}{(2r+1)(2r+2)(2r+3)...
Anuj Jha's user avatar
1 vote
0 answers
40 views

Relating $\sum_{k=1}^N a_k^2 e^{\frac{2\pi i}{N}k}$ to $(\;\sum_{k=1}^N a_k e^{\frac{2\pi i}{N}k}\;)^2$

Consider the following expression $$ \sum_{k=1}^N a_k^2 e^{\frac{2\pi i}{N}k}\tag{1} $$ where $i$ is the imaginary number. How may I relate it to the following expression $$ \left(\sum_{k=1}^N a_k e^{\...
sam wolfe's user avatar
  • 3,435
1 vote
0 answers
48 views

seperating two variables in a function with summation

I'm building a data analysis program that perform on big chunks of data, the issue I'm having is the speed of some operations; to be exact I have a function that takes two variables in this form : $$f(...
Taha Khabouss's user avatar
1 vote
0 answers
46 views

can anyone simplify this equation? $\sum_{n=2}^{\infty} \sum_{j=1}^{n}\left[\frac{n !}{j !(n-j) !}(-A)^{n-j}(-B)^{j}\right]$

Can anyone help me simplify the following equation? Any ideas appreicate. Thanks a lot! $\sum_{n=2}^{\infty} \sum_{j=1}^{n}\left[\frac{n !}{j !(n-j) !}(-A)^{n-j}(-B)^{j}\right]$ with two variables A ...
Jerry's user avatar
  • 31
1 vote
1 answer
194 views

Trigonometric Identities Using De Moivre's Theorem

I am familiar with solving trigonometric identities using De Moivre's Theorem, where only $\sin(x)$ and $\cos(x)$ terms are involved. But could not use it to solve identities involving other ratios. ...
Abhinandan Saha's user avatar
1 vote
1 answer
45 views

Sum and product problem

How can I find the result of: $\sum\limits_{i=1}^{n}\prod\limits_{j=1}^{2} ij$ I know that $\prod\limits_{j=1}^{2} ij = 2i^2$, so I should simply do the summation as $\sum\limits_{i=1}^n2i^2$?
Maria Giulia Martins's user avatar
1 vote
0 answers
56 views

Prove that if $4k+1$ is a prime number than for every $n \in \mathbb{N}$ $\sum\limits_{j=1}^{2k}{j^{4n+2}}$ is a multiple of $4k+1$

Prove that if $4k+1$ is a prime number than for every $n \in \mathbb{N}$ $\sum\limits_{j=1}^{2k}{j^{4n+2}}$ is a multiple of $4k+1$ First I tried proving for n=1 $\sum\limits_{j=1}^{2k}{j^{6}}=(4k+1)...
Vicente Martinez's user avatar
1 vote
0 answers
28 views

How to express this function for arbitrary N?

I am working on solving an equation system, that involves a parameter $N=2,3,\cdots,\infty$. Because I found it rather hard to solve it with an arbitrary $N$, I solved it in smaller numbers. One can ...
MrR's user avatar
  • 11
1 vote
0 answers
75 views

When is $a(n)$ prime?

Question: When is $a(n)\in P$ compared to all possible values of $n$? where $P$ denotes the set of primes. What is the density of the primes in the sequence? Consider the sum of the prime counting ...
zeta space's user avatar
1 vote
0 answers
57 views

Closed form of basic looking geometric-like sum

In my research I have come across the need to sum simple looking geometric series-like sums. Neither Maple, nor Mathematica, nor Wolfram Alpha and not even OEIS (On-line Encyclopedia of Integer ...
user415396's user avatar
1 vote
0 answers
48 views

Transforming a long sum of products for efficient computation (based on spanning trees in a complete graph)

Let's say there is a set of $n$ real coefficients: $a_1,...,a_n$. My task is to calculate the value of a rather simple sum of k products: ...
maciek's user avatar
  • 239
1 vote
0 answers
46 views

Trying to find a function that converts a binary sequence to a number

Suppose I have the sequence $\langle x_1, ..., x_n \rangle \in \mathbb{N}^n$ that gets encoded to the binary string $$ \begin{matrix} \underbrace{11...1} & 0 & \underbrace{11...1} & 0 &...
Tristan Batchler's user avatar
1 vote
1 answer
56 views

Given variable $m$, how do I find zeros of a polynomial in terms of $m$?

This is a summation question about a finite series with sum $m$. I'm trying to write a computer program that takes in a given integer $m$ (which represents the sum of a series) and outputs the number ...
Michael's user avatar
  • 11
1 vote
1 answer
116 views

Upper bound of a sum of series

How can I find a tight upper bound for the following expression: $\sum\limits_{i=1}^{k} a_i \sum\limits_{j = 1}^{i} \frac{1}{b_j} = a_1 \frac{1}{b_1} + a_2 (\frac{1}{b_1} + \frac{1}{b_2}) + \dots + ...
jayesh's user avatar
  • 41
1 vote
0 answers
35 views

Help with simplification of this expression.

So i have derived this expression and would like to simplify it (i.e find an expression purely in terms of J and v). $$ J\bigg[1+\sum_{n=1}^{J-1}\prod_{k=1}^{n}\frac{k(1-v)(J-k)}{(k+1)(J-k-1 + vk)}\...
vilacelestin's user avatar
1 vote
0 answers
160 views

How to isolate and solve for k in a Sigma notation probability mass function equation?

"isolate and solve for k:" $$P(X = k) = \sum_{k=0}^n {{{K \choose k} {{N-K} \choose {n-k}}}\over {N \choose n}}$$ If the above equation is a function of P, how would the equation be stated as a ...
Tyson's user avatar
  • 11

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