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0 votes
0 answers
98 views

If $\sum_{i=1}^n x_i \ge a$, then what can we know about $\sum_{i=1}^n \frac{1}{x_i}$?

Suppose that $$\sum_{i=1}^n x_i \ge a$$ where $a>0$ and $x_i\in (0, b]$ for all $i$. Are there any bounding inequalities we can determine for $$\sum_{i=1}^n \frac{1}{x_i}?$$ I understand that $\...
BSplitter's user avatar
  • 1,615
1 vote
1 answer
140 views

Other ways to show $y_n = \prod_{k=1}^n \left(1+{1\over x_k}\right)$ is bounded, where $x_n$ is another sequence with given properties.

Problem statement: Let $n\in \mathbb N$ and $\{x_n\}$ be a sequence of natural numbers such that $S_n$ defined by: $$ S_n = {1\over x_1} + {1\over x_2} + {1\over x_2} + \dots + {1\over x_n} $$ ...
roman's user avatar
  • 5,411
1 vote
1 answer
96 views

Proof verification of $\sum_{k=1}^n kq^{n-k}$ is unbounded for $n \in \mathbb N$ and $q\in\{\mathbb R\setminus0\}$

As opposed to the sum in this question I want to prove the following: Given $n\in \mathbb N$, $q\in \{\mathbb R \setminus0\}$ and: $$ x_n = \sum_{k=1}^n kq^{n-k} $$ Show that $x_n$ is an ...
roman's user avatar
  • 5,411
2 votes
0 answers
38 views

Upper bound on $\frac{v_{1}}{1-c_{1}x}+\cdots+\frac{v_{n}}{1-c_{n}x}$

Let $v_{1},\ldots,v_{n}$ and $c_{1},\ldots,c_{n}$ be real numbers such that $v_{i}=2\alpha_{i}^{2}$ and $c_{i}=2\alpha_{i}$ for some $\alpha\ge 0$. My question is the following: Can I get, for $x\ge 0$...
nemo's user avatar
  • 638
6 votes
1 answer
1k views

Upper bound of the sum $\sum_{i=2}^{N}{\frac{1}{\log(i)}}$

One of the questions in Sierpinski's book on number theory lead to finding a tight upper bound for the following sum: $$\sum_{i=2}^N {\frac{1}{\log(i)}}$$ The trivial upper bound like $\frac{N-1}{\...
Five's user avatar
  • 217
4 votes
1 answer
426 views

Find an asymptotically tight bound for $\sum_{k=1}^nk^r\log^s(k)$

I have an exam coming up that I'm studying for and I'm somewhat stumped by a couple problems. I need to derive an asymptotically tight bound for the following summation: Assume $r$ and $s$ are ...
canton's user avatar
  • 129