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1 vote
1 answer
129 views

Proving $\sum_{1}^{n} \left\lceil\log_{2}\frac{2n}{2i-1}\right\rceil=2n -1 $

Show that $$\sum_{i=1}^{n} \left\lceil\log_{2}\frac{2n}{2i-1}\right\rceil=2n -1 $$ where $ \lceil\cdot\rceil$ denotes the ceiling function. My method: one way would be observe each part of the ...
ProblemDestroyer's user avatar
2 votes
2 answers
153 views

$\sum_{k=0}^\infty[\frac{n+2^k}{2^{k+1}}] = ?$ (IMO 1968)

For every $ n \in \mathbb{N} $ evaluate the sum $ \displaystyle \sum_{k=0}^\infty \left[ \dfrac{n+2^k}{2^{k+1}} \right]$ ($[x]$ denotes the greatest integer not exceeding $x$) This was IMO 1968, 6th ...
G. Sai Rithvick's user avatar
2 votes
4 answers
62 views

For a fixed $k$ what is the value of $\sum_{l=1}^{5^m-1} \Big\lfloor \dfrac{l}{5^k}\Big \rfloor$

For a fixed $k$ what is the value of $\sum_{l=1}^{5^m-1} \Big\lfloor \dfrac{l}{5^k}\Big \rfloor$ By dividing the numbers between $1$ and $5^m$ as intervals of $5^k$, I was getting the following ...
user avatar
3 votes
2 answers
689 views

How many values of $n$ are there for which $n!$ ends in $1998$ zeros?

How many values of $n$ are there for which $n!$ ends in $1998$ zeros? My Attempt: Number of zeros at end of $n!$ is $$\left\lfloor \frac{n}{5}\right\rfloor+\left\lfloor\frac{n}{5^2}\right\rfloor+\...
Maverick's user avatar
  • 9,569
2 votes
1 answer
447 views

Sum of all divisors of the first $n$ positive integers.

Yesterday I was going through Möbius Function notes, and found that writing $n = p_{1}^{\alpha_1}p_{2}^{\alpha_2}\cdots p_{r}^{\alpha_r}$, the sum of all divisors can be written as. $$ e(n) = \prod_{...
Shagun's user avatar
  • 49
3 votes
2 answers
227 views

Find n in sum that results in a number $aaa$

Lets say that we have the sum $1+2+3+\ldots+n$ where $n$ is a positive natural number and that this sum should equal a three digit number in which all the digits are the same, for example $111, 222,$ ...
Plebbut's user avatar
  • 39
0 votes
1 answer
100 views

Is this a valid definition of the rationals?

$$\mathbb{Q}=\left\{\sum_{n=1}^k f(n)\mid k,n\in\mathbb{N}\land f\text{ is a finite composition of $+$, $-$, $\div$, $\times$}\right\}$$ Reasoning: Any real number can be described by a (sometimes ...
R. Burton's user avatar
  • 5,040
3 votes
2 answers
199 views

Calculate $ \biggr\lfloor \frac{1}{4^{\frac{1}{3}}} + \frac{1}{5^{\frac{1}{3}}} + ... + \frac{1}{1000000^{\frac{1}{3}}} \biggr\rfloor$

Calculate $ \biggr\lfloor \frac{1}{4^{\frac{1}{3}}} + \frac{1}{5^{\frac{1}{3}}} + \frac{1}{6^{\frac{1}{3}}} + ... + \frac{1}{1000000^{\frac{1}{3}}} \biggr\rfloor$ I am just clueless. I just ...
ami_ba's user avatar
  • 2,132
2 votes
2 answers
83 views

Suppose that $1+2+...+n=\overline{aaa}$. Which of the following items CERTAINLY divides $n$? $5,6,7,8,11$

Suppose that $1+2+...+n=\overline{aaa}$. Which of the following items CERTAINLY divides $n$? $5,6,7,8,11$ I converted the given relation into the following: $$n(n+1)=2*3*37*a$$ Now I think ...
Hamid Reza Ebrahimi's user avatar
3 votes
2 answers
102 views

How many integers $n$ for $3<n<100$ are such that $1+2+3+\cdots+(n-1)=k^2$, with $k \in \mathbb{N^*}$?

I know that the sum $1+2+3+\cdots+(n-1)$ equals $\frac{(n-1)\cdot n}{2}$. I wrote the equation in the two following forms: $$(n-1)\cdot \frac{n}{2}=k^2$$ $$(n-1)\cdot n=2k^2$$ And I tried to find ...
Glycerius's user avatar
  • 593
4 votes
1 answer
500 views

Does anyone know how to reduce this sum of sums into something simpler in order to find a special value? [duplicate]

to clarify the difference between this and the supposed duplicate, these two questions talk about completely different functions with completely different purposes I was given this from a friend. ...
user64742's user avatar
  • 2,175
0 votes
2 answers
124 views

Proof of Number Theoretic Function $\sigma$ [closed]

If $N$ is a positive integer then,$$\sum\limits_{n=1}^{N}\sigma(n)=\sum\limits_{n=1}^{N}n\lfloor\dfrac{N}{n}\rfloor$$, where $\lfloor.\rfloor$ denotes greatest integer function and $\sigma(n)$ denotes ...
mathlover's user avatar
  • 1,943
3 votes
4 answers
186 views

Summation or Integral representation ${e^{2}\above 1.5pt \ln(2)}=10.66015459\ldots$

How can I construct a summation or integral representation of $${e^2\above 1.5pt \ln(2)}.$$ Naively I would write $$\Bigg(\sum_{n=0}^{\infty}{2^n \above 1.5pt n!} \Bigg)\Bigg(\sum_{n=1}^\infty {(-1)^{...
Anthony's user avatar
  • 3,758
11 votes
1 answer
306 views

Proving if it is possible to write 1 as the sum of the reciprocals of x odd integers

Let $x$ be an even number. Is it possible to write 1 as the sum of the reciprocals of $x$ odd integers? Write a proof supporting your answer. I tried a lot of these, and I think it is no because I ...
joko34's user avatar
  • 311
14 votes
4 answers
462 views

Show that the numerator of $1+\frac12 +\frac13 +\cdots +\frac1{96}$ is divisible by $97$

Let $\frac{x}{y}=1+\frac12 +\frac13 +\cdots +\frac1{96}$ where $\text{gcd}(x,y)=1$. Show that $97\;|\;x$. I try adding these together, but seems very long boring and don't think it is the right way ...
locke5's user avatar
  • 153

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