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1 vote
0 answers
33 views

Kraus operators

Suppose we have a POVM given by the family of positive, hermitian operators $\{E_i\}_{i\in I} \in \mathcal{H}$. From the Neimark dilation theorem we know that the given POVM can be obtained from ...
ana's user avatar
  • 75
0 votes
1 answer
34 views

Spectrum of a positive definite differential operator

When solving the two body problem in three dimensions in my QM lectures, you end up, essentially, with the Legendre associated equation. In terms of the angular momentum operator: $$L^2Y_l^m(\theta, \...
Lagrangiano's user avatar
2 votes
1 answer
92 views

About the spectrum family of the multiplication operator

Let $<,>$ be the inner product of $L^2(\mathbb{R})$. For a measurable function $F:\mathbb{R}^d\to\mathbb{R}$, we define a multiplication operator $M_F:L^2(\mathbb{R}^d)\to L^2(\mathbb{R}^d)$, ...
neconoco's user avatar
1 vote
1 answer
62 views

Moller Operator and the Determination of Bound States in Quantum Scattering Theory

I am trying to understand the Moller operator in quantum scattering theory. An important result concerning this operator is the following useful property that can be used to determine bound states. ...
Debbie's user avatar
  • 854
1 vote
0 answers
94 views

Using density argument of Schwartz functions in $L^2$ to show an operator is symmetric

The position operator $X$ is defined as multiplication by $x$, i.e. $$(X\psi)(x):=x\psi(x).$$ We take the domain $D(X)\subset L^2(\mathbb R)$ for $X$, which we can take $$D(X):=\{\psi \in L^2(\mathbb ...
nomadicmathematician's user avatar
2 votes
4 answers
121 views

The value of $\langle p^2 \rangle$ for $\psi(x)=e^{-|x|}$, where $\hat{p}:=i\frac{d}{dx}$ is the momentum operator.

Consider the Hilbert space $H$ of square-integrable complex functions on the real line equipped with the inner product $$\langle \phi,\psi\rangle:=\int \phi^*\psi d\mu,$$ where $\mu$ is the Lebesgue ...
Thato Tsabone's user avatar
6 votes
1 answer
177 views

Convergence from spectrum of the Choi matrix?

Suppose I have a linear operation of the form $T(C)=\frac{1}{m}\sum_i^m A_i C A_i$ for a set of $m$ symmetric $d \times d$ matrices $A_i$. I construct Choi matrix below with $e_i$ referring to ...
Yaroslav Bulatov's user avatar
2 votes
1 answer
202 views

Spectrum of a sum of self-adjoint operators

This is a "sequel" to that question where I explain why I need the spectrum of an operator given as the sum of a convolution and a function multiplication. Here, I am considering the ...
Gateau au fromage's user avatar
2 votes
2 answers
266 views

Compactness of subset of trace-class operators on a Hilbert space

Consider an infinite-dimensional, complex and separable Hilbert space $H$ and let $\mathcal I(H)$ denote the space of trace-class operators. The set of density operators is defined by $$\mathcal S(H):...
Jakob's user avatar
  • 428
6 votes
0 answers
311 views

Limit of a particular trace norm.

I have the following problem. Let $\mathbf{\hat{\rho}}(t)$ and $\mathbf{\hat{\sigma}}(t)$ be two trace class positive operators acting on a Hilbert space of infinite dimension for all $t > 0$. More ...
Hldngpk's user avatar
  • 71
0 votes
3 answers
79 views

Whether $[A,B]=0$ if $\langle[A,B]\rangle=0$ for all states in the Hilbert space?

Let $\hat{A}$ and $\hat{B}$ are two self-adjoint operators in quantum mechanics corresponding to two dynamical variables $A$ and $B$. If $$\langle[\hat{A},\hat{B}]\rangle\equiv \langle\psi|[\hat{A},\...
Solidification's user avatar
1 vote
0 answers
53 views

Coefficient conditions for square root of the Laplacian

I am confused about what's going on in the attached picture (from the introduction of Friedrich's Dirac Operators in Geometry). The author claims that for an operator $P$ to satisfy $P = \sqrt{\...
summersfreezing's user avatar
1 vote
0 answers
104 views

Power rule for derivative operator $D^n$

I was playing with commuting the derivative operator $D$ and the scalar multiplication of $x$ applying to a function $f$. If $[\cdot,\cdot]$ denote de commutator, then: $$[D,x]f=D(xf)-xDf=f+xDf-xDf=f$$...
Daniel Muñoz's user avatar
1 vote
0 answers
43 views

If $A\geq 0$ and $0\leq B\leq C$, then $0\leq \sqrt{B}A\sqrt{B}\leq \sqrt{C}A\sqrt{C}$ [duplicate]

Let $H$ be a complex Hilbert space with inner product $\langle\cdot,\cdot\rangle$. We say $A\geq 0$ if $\langle Ax,x\rangle\geq0$ for all $x\in H$. If $A\geq 0$ and $0\leq B\leq C$, then does $0\leq \...
schrodingerscat's user avatar
2 votes
1 answer
77 views

If $0\leq A\leq B$ then the corresponding densities satisfy $0\leq\rho_A\leq \rho_B$

Let $A,B$ on $L^2(\mathbb R^d,\mathbb C^d)$ such that $0\leq A\leq B$ AND $A,B$ are trace-class. Then their densities are given by $$\rho_A(x):=\sum_jA\varphi_j(x)\overline{\varphi_j(x)},\qquad \rho_A(...
schrodingerscat's user avatar
0 votes
1 answer
70 views

If $0\leq A\leq B$ and $C\geq0$ then does $0\leq AC\leq BC$?

Let $H$ be a complex Hilbert space with inner product $\langle\cdot,\cdot\rangle$. We say $A\geq 0$ if $\langle Ax,x\rangle\geq0$ for all $x\in H$. If $0\leq A\leq B$ and $C\geq0$ then does $0\leq AC\...
schrodingerscat's user avatar
1 vote
0 answers
34 views

Meaning of "smooth finite-rank operators $Q$ in $L^2(\mathbb R^d)$"

What does it mean for a finite-rank operator to be "smooth"? How can one finite-rank operator be smoother than another? For me, a finite-rank operator on $L^2(\mathbb R^d)$ has an expression ...
schrodingerscat's user avatar
1 vote
1 answer
84 views

Operator theory: nonnegative operator $Q$ less than an orthogonal projection $P$ satisfies $PQ=QP$

Suppose that we have a Hilbert space $\mathcal{H}$, an orthogonal projection $P$ (i.e. $P=|\Psi\rangle\langle\Psi|$ for some $\Psi\in\mathcal{H}$ with $\|\Psi\|=1$) and another non-negative bounded ...
Ooooscar's user avatar
0 votes
1 answer
40 views

If $A$ is trace-class on $L^2(\mathbb R^2)$ then $\mathbb 1(-\Delta\leq 1)A\mathbb 1(-\Delta\leq 1)$ is finite-rank. [closed]

I am trying to prove that if $A$ is trace-class on $L^2(\mathbb R^2)$ then $\mathbb 1(-\Delta\leq 1)A\mathbb 1(-\Delta\leq 1)$ is a finite-rank operator, where $\mathbb 1(-\Delta\leq 1)$ is defined on ...
schrodingerscat's user avatar
1 vote
1 answer
65 views

An inequality for Schatten norms with a compact self-adjoint operator

Let $Q$ be a compact self-adjoint operator on $L^2(\mathbb R,\mathbb C)$. Notice that $(1-\Delta)^{s}$ is a positive (and hence self-adjoint) operator on $H$ for any $s>0$. We denote by $\mathfrak ...
schrodingerscat's user avatar
3 votes
1 answer
130 views

Commutator bertween shift operator and "position" operator

I was studying the shift operator in quantum mechanics from wikipedia and in the commutator section explains that for a shift operator $\hat T(x)$ and a position operator $\hat x$, the commutator $\...
Daniel Muñoz's user avatar
0 votes
1 answer
59 views

In what sense is $\breve{g}(x-y)/(2\pi)^n$ the integral kernel of $g(-i\nabla)$?

It is said in Trace Ideals and Their Applications by Barry Simon that the integral kernel of the operator $g(-i\nabla)$ on $L^2(\mathbb R^n)$ is given by $\breve{g}(x-y)/(2\pi)^n$. Indeed, for any $\...
schrodingerscat's user avatar
1 vote
1 answer
80 views

Hartree equation in density matrix formalism is equivalent to a system of Hartree equations

I want to prove that: If the density matrix $$\gamma(t):=\sum_{j=1}^N|u_j(t)\rangle\langle u_j(t)|=\sum_{j=1}^N\langle u_j(t),\cdot\rangle u_j$$ solves $$i\partial_t\gamma(t)=[-\Delta+w*\rho,\gamma],$...
schrodingerscat's user avatar
4 votes
1 answer
145 views

Definition of ground state?

In quantum mechanics, a ground state is an eigenstate of the hamiltonian with the minimal eigenvalue and its existence is guaranteed by appropriate theorems. At least that's how it's defined in ...
Kelly's user avatar
  • 305
1 vote
1 answer
42 views

Find self-adjoint of $P=|a \rangle \langle b |$

Let $P$ be an operator s.a. $P=|a \rangle \langle b |$ and $P|f \rangle = \langle b | f \rangle | a \rangle $. Find the self-adjoint and the $P^2$ operator. My attempt: We know to find the self ...
lebong66's user avatar
  • 463
4 votes
1 answer
175 views

Are quantum state (density) operators unique?

For context, the following question is related to my question on Physics SE. Now for the question. Consider the following requirements on an operator $\rho$ on a Hilbert space (or on a rigged Hilbert ...
EE18's user avatar
  • 1,143
1 vote
1 answer
69 views

For projection matrices, which vector of the outer product should be complex conjugated?

I have a conjugation wrong somewhere in my definitions, and I can't work out where it is. I want to define the standard matrix for a projection operator. If you can provide correct and standard ...
Mikkel Rev's user avatar
  • 1,849
2 votes
1 answer
321 views

On the usage of derivative in operator theory

In quantum mechanics, we work with linear operators on Hilbert spaces $\mathscr{H}$. Suppose I have two bounded ones, defined on the same space $A, B: \mathscr{H}\to\mathscr{H}$. It seems to me there ...
ric.san's user avatar
  • 141
0 votes
1 answer
437 views

Show that the adjoint of two operators is the sum of the adjoints

Problem Show that for any two operators $\hat{A}$ and $\hat{B}$, the adjoint $(\hat{A} + \hat{B})^\dagger = \hat{A}^\dagger + \hat{B}^\dagger$. Do so using the integral form of the definition of ...
10GeV's user avatar
  • 1,381
0 votes
1 answer
55 views

Positive linear operator inequality

I'm stuck proving the following inequality. Let $H$ autohermitian operator such that $$\langle u|H|u\rangle\geq0\qquad\forall |u\rangle$$ Proof that $$|\langle u|H|v\rangle|^2\leq\langle u|H|u\rangle\...
math3341's user avatar
0 votes
0 answers
63 views

What is the most general Self-Adjoint operator acting on $L^{2}(\mathbb{R})$?

What is the most general Self-Adjoint operator acting on $L^{2}\mathbb{R}$? My hypothesis is that the aswer to my question will be that the most general Self-Adjoint operator $A$ acting on $L^{2}(\...
Hldngpk's user avatar
  • 71
1 vote
0 answers
105 views

On the structure of the set of Self-Adjoint operators acting on $L^{2}(\mathbb{R})$.

Let us consider the $Hilbert$ Space $L^{2}(\mathbb{R})$ and let $SA(L^{2}(\mathbb{R})$ be the space of all self adjoint operators acting on $L^{2}$. I have worked with operators such as $X$, $P$, $X^{...
Hldngpk's user avatar
  • 71
2 votes
1 answer
370 views

If $\hat{A}$ commutes with $\hat{r}^2$, does $\hat{A}$ commute with $\hat{r}$?

Let $\hat{x}, \hat{y}, \hat{z}$ be the position operators in 3D space and $\hat{r}^2=\hat{x}^2+\hat{y}^2+\hat{z}^2$ as usual. If one operator $\hat{A}$, commutes with $\hat{r}^2$, i.e. $$\Big[\hat{A}, ...
Gaussian97's user avatar
0 votes
0 answers
27 views

Question regarding conjugate operators and the harmonic operator.

Let us consider the operator $\hat{n}=\hat{a}^\dagger\hat{a}$ as the number operator of the harmonic oscillator. Let $|n\rangle$ be the eigenstates. Then we can say : $$\hat{n}|n\rangle=n|n\rangle$$ I'...
Nakshatra Gangopadhay's user avatar
1 vote
1 answer
145 views

Given $[A,B]=0$ then $[A,f(B)]=0$

Given $A$ and $B$ two operators that commute ($[A,B]=0$) then $A$ commutes with an arbitrary function of $B$ I recently saw this property of the commutators on a quantum mechanics course. We didn't ...
Mikel Solaguren's user avatar
1 vote
1 answer
67 views

Equivalence between two definitions of hermitian adjoint

Given the two definitions of hermitian adjoint: $(1): <\Psi|A|\Phi>=(<\Psi|A^+|\Phi>)^*$ $(2): <\Psi|A\Phi>=<A^+\Psi|\Phi>$ I want to show that they are equivalent However I ...
Mikel Solaguren's user avatar
1 vote
0 answers
62 views

Integral over operators equal -When are operators equal?

This is a physics motivated question from quantum mechanics. When I have two operators $\hat{A}$ and $\hat{B}$ acting on the Hilbertspace $\mathbb{C}-L^2(\mathbb{R})$ with $$\int\psi^*(x)\hat{A}\psi(x)...
Silas's user avatar
  • 320
1 vote
1 answer
42 views

What can I infer from this scalar product identity?

Suppose I have shown for a single vector $\lvert 0 \rangle$ that $$\langle 0 \rvert U^\dagger \phi U \lvert 0 \rangle=\langle 0 \rvert \phi \lvert 0 \rangle$$ where $\phi$ is a certain operator and $U$...
Ghorbalchov's user avatar
5 votes
1 answer
191 views

Problem on a rank 1 perturbation of an self-adjoint operator

With my teacher we have been trying to solve for a while a problem that consists of two parts, and each one in three sections. The first part, which has to do with the problems that I was able to ...
Litafie's user avatar
  • 160
1 vote
1 answer
74 views

Action of an operator-valued function of the momentum operator $\hat{p}$ and its unboundedness

I am currently dealing with an operator-valued function $f(\hat{T})$ of the following kind: $$f(\hat{T}) =\sqrt{1 + b\hat{T}^2} $$ where $b$ $\in \mathbb{R}$ and $\hat{T}$ is a linear operator acting ...
RH_ss's user avatar
  • 31
1 vote
1 answer
94 views

What is the meaning of the operator projection in quantum mechanic

Let's have a vector $B_1$ which lies in the $xz$ plane forming an angle $\theta$ with $z$ axis. Let $S_\theta$ be the projection of the operator S along $B_1$. Question 1: How can i write $S_\theta$ ...
Salmon's user avatar
  • 315
0 votes
1 answer
33 views

On derivatives of tensor products in QM

Does the derivation follow a sort of Leibniz's Rule for a tensor product? $ \displaystyle \frac {\partial} {\partial t} \left ( A_t \otimes B_t \right) \overset ? = \frac {\partial A_t} {\...
ric.san's user avatar
  • 141
4 votes
2 answers
99 views

Can I conclude these weak derivatives are strong?

I'm trying to show the momentum operator $P : \mathcal D(P)\ \dot{=}\ C^\infty_0(\Bbb R)\to L^2(\Bbb R)$ with $P=-i\hbar\partial_x$ is essentially self-adjoint, which is equivalent to saying that it ...
giobrach's user avatar
  • 7,532
0 votes
1 answer
192 views

proof of the product: x times m derivative of delta function.

The question is in one dimension and is : Prove that $$x\delta^{(m)}=-m\delta^{(m-1)},\ m \in \mathbb{N},$$ where $\delta^{(m)}$ is the $m$-derivative of $\delta.$ As I know, I got through this way: $...
João Pedro's user avatar
2 votes
1 answer
82 views

Scaled Dirac Delta function: $ \delta (xe^r - y) $

I was reading on squeezed Gaussian states and stumbled upon this paper: Equivalence Classes of Minimum-Uncertainty Packets. II. It is mentioned after Eq. $\left(2\right)$ that $$ \left\langle x\left\...
Lefteris's user avatar
2 votes
1 answer
105 views

Consequences of Deficiency indices theorem (Von Neumann theory)

Let $T: \operatorname{dom}(T) \rightarrow \scr H$ be a symmetric operator. $T$ admits self-adjoint extensions $\iff$ $d_+ = d_-$, where $d_\pm = \dim \ker(T^\dagger \pm i \mathbb{I})$ If $d_+ = d_-$,...
ric.san's user avatar
  • 141
0 votes
1 answer
91 views

Translation on X operator

I need to show that given $[x, p_x]=i\hbar$ then the following is true: $$ e^{iap_x/\hbar}f(x)e^{-iap_x/\hbar}=f(x+a) $$ for a general function $f(x)$. I've tried using Taylor Series for both ...
Gustavo Schranck Habermann's user avatar
0 votes
2 answers
58 views

Operator norm of X

I've been trying to prove that the operator norm of $\hat{X}\phi(x) = x\phi(x)$ with $\phi(x) \in L^2[0,1]$ is given by: $$ ||\hat{X}|| = \sup_{||\phi(x)||=1} ||\hat{X}\phi(x)||=1 $$ However i havent ...
Gustavo Schranck Habermann's user avatar
1 vote
1 answer
204 views

Hermiticity of operator on square integrable functions

I'm trying to solve this problem for my Quantum Mechanics class but its my first time dealing with infinite dimensional spaces so I'm a little lost here. I need to show that the operator defined by $$ ...
Gustavo Schranck Habermann's user avatar
1 vote
2 answers
49 views

Algebra involving operator of x and p

For operators x and p in QM with $p= {h\over i}{d \over dx} $, how can I find the combination of operator such as $$(xp-px)^2 $$ or $$(x+p)(x-p) $$ Can I just expand them by using normal algebra such ...
Nobu Nobu's user avatar

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