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Questions tagged [noncommutative-algebra]

For questions about rings which are not necessarily commutative and modules over such rings.

0 votes
0 answers
10 views

How to use BCH formula to compute mutiplication of group element?

i cant get the right answer. Given the commute rule of (for example, the caculation below will be in static group): we have: generator H, P, K, J, and commutation rule $[H,P]=0$, $[H,K]=0$, $[P,P]=0$...
showin's user avatar
  • 1
1 vote
0 answers
24 views

Finiteness of results in Connes-Kreimer approach

Remark: Although this is technically a physics-related post, the content heavily relies on pure mathematics, so I deemed it more appropriate here. When reading the papers by Connes and Kreimer (e.g. [...
NDewolf's user avatar
  • 1,713
2 votes
1 answer
36 views

Nonunital non commutative ring with 3 ideals...

It is well known that if a (unital commutative) ring A has only three ideals ({0}, J, A), then the quotient A/J is a field. But, what can we conclude about A/J if A is not commutative nor unital but ...
Felipe's user avatar
  • 73
1 vote
0 answers
39 views

Polynomial of a ring is nilpotent if all of its coefficients are nilpotent? [duplicate]

Let $R$ be a ring (not necessarily commutative) and $R[x]$ its polynomial ring. Suppose $f(x)\in R[x]$ is such that $f(x)=a_0+a_1x+\cdot\cdot\cdot + a_nx^n$. My question is if $a_i$ is nilpotent for ...
Chaudhary's user avatar
  • 533
2 votes
1 answer
61 views

Finite dimensional Irreps (of algebras) with same traces must be equivalent ('page 136' in Bourbaki)

I look for the reference (or proof) of the following fact which is from appendix (B $27$) of Dixmier's book on $C^*$-algebras. Claim: Let $A$ be an algebra (not necessarily commutative) over a field $...
Charles Ryder's user avatar
-1 votes
0 answers
21 views

Tensor over matrices [duplicate]

Suppose $A$ and $B$ be two ring. Show that $M_n(A) \otimes_{\mathbb{Z}} M_m(B) \simeq M_{nm}(A \otimes_{\mathbb{Z}} B)$. Actually if define $\psi : M_n(A) \times M_m(B) \rightarrow M_{nm}(A \otimes B)$...
Arian Heydari's user avatar
1 vote
0 answers
47 views

Conceptual definition of the Auslander-Reiten translate

In homological algebra, we learn to differentiate between The conceptual definition. A computation, which is done by choosing efficient resolutions. The only definition I've seen of the Auslander-...
user135743's user avatar
0 votes
0 answers
46 views

Noncommutative analogue of ring of integers in number field

I'm studying Igor V. Nikolaev's paper "Untying knots in 4D and Wedderburn’s theorem". In the paper, he works with hyper-algebraic fields $\mathbb{K}$, i.e., fields with noncommutative ...
Ama's user avatar
  • 81
0 votes
1 answer
12 views

Are primitive ideals left maximal in a non-commutative ring?

Let $\mathcal{R}$ ring and $I \subset \mathcal{R} $. $I$ is called a primitive ideal of $\mathcal{R}$ if it is a left ideal and $\exists \, M$ simple left $\mathcal{R}- $module such that $Ann(M)=I$. ...
kostis's user avatar
  • 3
1 vote
0 answers
87 views

Why do Kontsevich and Rosenberg use algebra epimorphisms rather than surjections?

In the article Noncommutative spaces Kontsevich and Rosenberg make the following definition: 2.6. The Q-category of infinitesimal algebra epimorphisms. Let $A$ be the category $Alg_k$ of associative ...
Nick Mertes's user avatar
1 vote
0 answers
34 views

Ideal generated by central element is central in a prime ring?

A ring $R$ is said to be prime if $xRy=0 \implies x=0$ or $y=0.$ Let $R$ be a prime ring and $x \in Z(R)$. Then the ideal generated by $x$ is central i. e. $\langle x \rangle \subseteq Z(R).$ I ...
MANI's user avatar
  • 1,954
0 votes
0 answers
31 views

Wedderburn Artin's theorem for algebras over a field

I learned about the Wedderburn Artin's theorem for simple left artinian ring, says that if $R$ is simple left Artinian ring then $R\cong\mathrm{M}_n(\Delta)$, for some division ring $\Delta$. I want ...
wwwwww's user avatar
  • 81
1 vote
1 answer
40 views

If $R$ is Armendariz ring then its prime radical $P(R)$ is Armendariz or not?

First let us write about the definitions of some terms. Armendariz ring : A ring $R$ is said to be Armendariz if whenever $f(x),g(x)\in R[x]$ satisfy $f(x)g(x)=0$ then $a_ib_j=0$ for all $i,j$. Here $...
Muhammad Shanu's user avatar
1 vote
0 answers
53 views

On central simple algebras and the Wedderburn Artin's theorem

I learned about the Wedderburn Artin's theorem, says that if $R$ is simple left Artinian ring then $R\cong\mathrm{M}_n(\Delta)$, for some division ring $\Delta$. Now, I was studying the Brauer group. ...
wwwwww's user avatar
  • 81
0 votes
0 answers
38 views

About $(\frac{a,1-a}{k})\cong\mathrm{M}_2(k).$

$k$ is a field. A quaternion algebra over $k$ is a $4$-dimensional $k$-algebra with a basis $1,i,j,ij$ with the following multiplicative relations: $i^2\in k^\times, j\in k^\times, ij=-ji$ and every $...
wwwwww's user avatar
  • 81

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