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2 votes
1 answer
92 views

About the spectrum family of the multiplication operator

Let $<,>$ be the inner product of $L^2(\mathbb{R})$. For a measurable function $F:\mathbb{R}^d\to\mathbb{R}$, we define a multiplication operator $M_F:L^2(\mathbb{R}^d)\to L^2(\mathbb{R}^d)$, ...
neconoco's user avatar
2 votes
1 answer
202 views

Spectrum of a sum of self-adjoint operators

This is a "sequel" to that question where I explain why I need the spectrum of an operator given as the sum of a convolution and a function multiplication. Here, I am considering the ...
Gateau au fromage's user avatar
2 votes
1 answer
77 views

If $0\leq A\leq B$ then the corresponding densities satisfy $0\leq\rho_A\leq \rho_B$

Let $A,B$ on $L^2(\mathbb R^d,\mathbb C^d)$ such that $0\leq A\leq B$ AND $A,B$ are trace-class. Then their densities are given by $$\rho_A(x):=\sum_jA\varphi_j(x)\overline{\varphi_j(x)},\qquad \rho_A(...
schrodingerscat's user avatar
1 vote
1 answer
65 views

An inequality for Schatten norms with a compact self-adjoint operator

Let $Q$ be a compact self-adjoint operator on $L^2(\mathbb R,\mathbb C)$. Notice that $(1-\Delta)^{s}$ is a positive (and hence self-adjoint) operator on $H$ for any $s>0$. We denote by $\mathfrak ...
schrodingerscat's user avatar
5 votes
1 answer
191 views

Problem on a rank 1 perturbation of an self-adjoint operator

With my teacher we have been trying to solve for a while a problem that consists of two parts, and each one in three sections. The first part, which has to do with the problems that I was able to ...
Litafie's user avatar
  • 160
2 votes
1 answer
139 views

Convergence of $e^{itH}$ as a sum for $H$ and unbounded operator

Let $H$ be an unbounded operator on a Hilbert space $\mathcal{H}$. We may define the propagator $U(t)=e^{itH}$ via the functional calculus. However, if $H$ were bounded, the series $\sum_{k=0}^\infty \...
user293794's user avatar
  • 3,738
0 votes
0 answers
558 views

Spectrum of momentum operator of quantum physics

I am stuck with the following problem: Given the momentum operator of quantum mechanics $Af = - if'$ where the domain $D(A)$ consists of functions $f \in L^2(\mathbb{R})$ that are absolutely ...
Gunther's user avatar
  • 51
1 vote
1 answer
78 views

Where precisely is topology required to prove the existence of non-zero eigenstates in the proof of the spectral theorem?

My professor today remarked that the proof of the spectral theorem (even for the discrete spectrum case) uses not just algebra but also topology to prove the existence of eigenstates. However, I'm not ...
user avatar
4 votes
1 answer
903 views

Stone's theorem and the spectral theorem

I am struggling to formally derive the expression found in the Stone's theorem for one-parameter unitary groups. I am aware that this can be done by using the spectral theorem. I am mostly interested ...
omsorg's user avatar
  • 43
1 vote
1 answer
520 views

Is the resolution of the identity 'unique'?

I want to know how many ways the identity operator $I$ on a (finite) Hilbert space $\mathcal{H}$ can be written as sum of outer products of states like $|\psi_i\rangle\langle \psi_i|$. For example, $...
Mims's user avatar
  • 21
1 vote
3 answers
3k views

Proving that every diagonalizable operator is normal

This question is insipired by the proof of the Spectral Theorem in Nielsen and Chuang's book (page 72). It says: Theorem: Any normal operator $M$ on a vector space $V$ is diagonal with respect to ...
NNN's user avatar
  • 1,862
1 vote
0 answers
74 views

No embedded point spectra for (discrete) Schrodinger operators with compactly supported potential

Consider the lattice $\mathbb{Z}^d$ and let $H_0$ denote the (negative) Laplacian on $l^2(\mathbb{Z}^d)$ with spectrum $[-2d,2d]$. Suppose that I add a potential $q:\mathbb{Z}^d\rightarrow\mathbb{R}$ ...
Mathmo's user avatar
  • 1,035
4 votes
2 answers
349 views

Why is the magnetic Schrödinger operator positive?

In the book Schrödinger Operators by Cycon et al. they prove that the magnetic Schrödinger operator (as well as the Pauli operator) have essential spectrum $\sigma_{ess} = [0,\infty)$ if $B$ has decay ...
Jakob Elias's user avatar
  • 1,405
0 votes
0 answers
145 views

Simple proof that density operator has only pure point spectrum

Is there any simple proof that self-adjoint, nonnegative and trace one operators have only point spectrum? Namely, we want to show that if a bounded operator $\rho$ on $\mathcal{H}$ is such that $$ \...
NessunDorma's user avatar
  • 1,017
1 vote
0 answers
64 views

Let $\mathcal{H}$ be the Schrödinger operator. Why is $u(x,t)\xrightarrow{t\to\pm\infty} 0\iff\sigma_p(\mathcal{H})=\emptyset$?

Let $\mathcal{H}:=V-\Delta$ be the Schrödinger operator, $V\in C^\infty_0(\mathbb{R})$ and let $u\in L^2(\mathbb{R})$ be a solution of the equation $$\left(\Delta-\frac{\partial^2}{\partial t^2}\...
Jason Born's user avatar
  • 1,038

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