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Questions tagged [polylogarithm]

For questions about or related to polylogarithm functions.

0 votes
0 answers
37 views

Generalised Polylogarithm Polynomials and Related Integer Sequences

Consider the generalised infinite summation $$S_{n,m}=m^{n+1} \sum_{k=1}^\infty \frac{k^n}{(m+1)^k}=m^{n+1}\,\mathrm{Li}_{(-n)} \left(\frac{1}{m+1}\right)$$ where $m$ and $n$ are positive integers, ...
James Arathoon's user avatar
1 vote
1 answer
112 views

asymptotic behaviour of polylogarithmic function

I would like to understand the asymptotic behaviour as $a \rightarrow 0$ of the function $$ f(a) := \sum\limits_{k=2}^{\infty} e^{ - a^2 k}{k^{-3/2}} $$ More precisely, I would like to obtain an ...
QuantumLogarithm's user avatar
2 votes
0 answers
140 views

The ultimate polylogarithm ladder

As you can see, here I performed a derivation of a quite simple formula, not much differing from the standard integral representation of the Polylogarithm. Seeking to make it fancier, I arrived at ...
Artur Wiadrowski's user avatar
0 votes
3 answers
82 views

Evaluating an integral from 0 to 1 with a parameter, (and a dilogarithm)

So I need to evaluate the following integral (in terms of a): $$\int_{0}^{1} \frac{\ln{|1-\frac{y}{a}|}}{y} dy$$ Till now I have tried u-sub ($u = \ln{|1-\frac{y}{a}|}$, $u=\frac{y}{a}$) and ...
Kraken's user avatar
  • 27
11 votes
1 answer
254 views

A cool integral: $\int^{\ln{\phi}}_{0}\ln\left(e^{x}-e^{-x}\right)dx=-\frac{\pi^2}{20}$

I was looking at the equation $\ln{e^{x}-e^{-x}}$ and found that the zero was at $x=\ln{\phi}$ where $\phi$ is the golden ratio. I thought that was pretty cool so I attempted to find the integral. I ...
Dylan Levine's user avatar
  • 1,688
3 votes
0 answers
121 views

Show that $\mathfrak{Re}(\textrm{Li}_2(e^{ix}))=\frac{x^2}{4}-\frac{\pi x}{2}+\frac{\pi^2}{6}$ (polylogarithm)

I am working with the polylogarithm function and want to find closed expressions for $\textrm{Li}_2(e^{ix})$. If I plot the function $\mathfrak{Re}(\textrm{Li}_2(e^{ix}))$ I get $y=\dfrac{x^2}{4}-\...
garondal's user avatar
  • 889
11 votes
0 answers
255 views

Solve the integral $\int_0^1 \frac{\ln^2(x+1)-\ln\left(\frac{2x}{x^2+1}\right)\ln x+\ln^2\left(\frac{x}{x+1}\right)}{x^2+1} dx$

I tried to solve this integral and got it, I showed firstly $$\int_0^1 \frac{\ln^2(x+1)+\ln^2\left(\frac{x}{x+1}\right)}{x^2+1} dx=2\Im\left[\text{Li}_3(1+i) \right] $$ and for other integral $$\int_0^...
Faoler's user avatar
  • 1,637
4 votes
0 answers
112 views

Calculate an integral involving polylog functions

Im my recent answer https://math.stackexchange.com/a/4777055/198592 I found numerically that the following integral has a very simple result $$i = \int_0^1 \frac{\text{Li}_2\left(\frac{i\; t}{\sqrt{1-...
Dr. Wolfgang Hintze's user avatar
8 votes
3 answers
1k views

Prove $\int_{0}^{1}\frac1k K(k)\ln\left[\frac{\left(1+k \right)^3}{1-k} \right]\text{d}k=\frac{\pi^3}{4}$

Is it possible to show $$ \int_{0}^{1}\frac{K(k)\ln\left[\tfrac{\left ( 1+k \right)^3}{1-k} \right] }{k} \text{d}k=\frac{\pi^3}{4}\;\;? $$ where $K(k)$ is the complete elliptic integral of the first ...
Setness Ramesory's user avatar
4 votes
0 answers
83 views

Closed form of dilogarithm fucntion involving many arctangents

I am trying to find closed form for this expression: $$ - 2{\text{L}}{{\text{i}}_2}\left( {\frac{1}{3}} \right) - {\text{L}}{{\text{i}}_2}\left( {\frac{1}{6}\left( {1 + i\sqrt 2 } \right)} \right) - {\...
OnTheWay's user avatar
  • 2,702
1 vote
0 answers
69 views

Polylogarithm further generalized

Here I proposed a generalized formula for the polylogarithm. However, because of a slight mistake towards the end, visible prior to the edit, I was unaware that it yields just a result of an integral ...
Artur Wiadrowski's user avatar
5 votes
1 answer
193 views

Evaluating $\int_{0}^{1}\mathrm{d}x\,\frac{\operatorname{arsinh}{(ax)}\operatorname{arsinh}{(bx)}}{x}$ in terms of polylogarithms

Define the function $\mathcal{I}:\mathbb{R}^{2}\rightarrow\mathbb{R}$ by the definite integral $$\mathcal{I}{\left(a,b\right)}:=\int_{0}^{1}\mathrm{d}x\,\frac{\operatorname{arsinh}{\left(ax\right)}\...
David H's user avatar
  • 30.7k
2 votes
0 answers
85 views

Complex polylogarithm/Clausen function/Fourier series

Sorry for the confusing title but I'm having a problem and I can phrase the question in multiple different ways. I was calculating with WolframAlpha $$\int \text{atanh}(\cos(x))\mathrm{d}x= i \text{Li}...
Math Attack's user avatar
2 votes
1 answer
75 views

Converting polylogarithms to Dirichlet L functions

When trying to simplify polylogarithms evaluated at some root of unity, namely $\text{Li}_s(\omega)$ for $\omega=e^{2\pi i ~r/n}$, it is reasonable to convert it to Hurwitz zeta functions or Dirichlet ...
Po1ynomial's user avatar
  • 1,695
1 vote
1 answer
60 views

Imaginary part of the dilogarithm of an imaginary number

I am wondering if I can simplify $${\rm Im} \left[ {\rm Li}_2(i x)\right] \ , $$ in terms of more elementary functions, when $x$ is real (in particular, I am interested in $0<x<1$). I checked ...
Rudyard's user avatar
  • 305
2 votes
0 answers
68 views

Evaluating $\int\frac{\log(x+a)}{x}\,dx$ in terms of dilogarithms

As per the title, I evaluated $$\int\frac{\log(x+a)}{x}\,dx$$ And wanted to make sure my solution is correct, and if not, where I went wrong in my process. Here is my work. $$\int\frac{\log(x+a)}{x}\,...
Person's user avatar
  • 1,123
1 vote
1 answer
201 views

Verification of the generalized polylogarithm formula

Here I posted a generalized formula for the polylogarithm I had discovered. However, for $x=\frac{1}{2}$, $z=\frac{1}{2}$, $p=1$ wolfram alpha yields a result different than what the double integral ...
Artur Wiadrowski's user avatar
6 votes
2 answers
326 views

How to show $\int_0^1\frac{\operatorname{Li}_2\left(\frac{1+x^2}{2}\right)}{1+x^2}dx=\ln(2)G$

I am trying to prove that $$\int_0^1\frac{\operatorname{Li}_2\left(\frac{1+x^2}{2}\right)}{1+x^2}dx=\ln(2)G,$$ where $G$ is the Catalan constant and $\operatorname{Li}_2(x)$ is the dilogarithm ...
Ali Shadhar's user avatar
  • 25.8k
1 vote
0 answers
86 views

Efficient calculation for Lerch Transcendent Expression

I've encountered: $$\Phi(z, s, \alpha) = \sum_{k=0}^\infty \frac { z^k} {(k+\alpha)^s}.$$ When trying to compute: $$\frac{1}{x}\sum_{p=0}^m \frac{2}{(2p-1)\ x^{2p-1}}\ s.t. x\in\mathbb{N} =\ ???$$ ...
user3108815's user avatar
3 votes
0 answers
142 views

Prove that $-\int_{0}^{1}\frac{{\rm Li}_2(-x(1-x))}{x}\ dx=\frac{2}{5}\zeta(3)$

Prove that $$-\int_{0}^{1}\frac{{\rm Li}_2(-x(1-x))}{x}\ dx=\frac{2}{5}\zeta(3)$$ where ${\rm Li}_2(x)$ is the Poly Logarithm function and $\zeta(s)$ is the Riemann zeta function Let $$I=-\int_{0}^{1}...
Max's user avatar
  • 910
1 vote
0 answers
72 views

Evaluate $\sum\limits_{n=0}^\infty\operatorname W(e^{e^{an}})x^n$ with Lambert W function

$\def\W{\operatorname W} \def\Li{\operatorname{Li}} $ Interested by $\sum_\limits{n=1}^\infty\frac{\W(n^2)}{n^2}$, here is an example where Lagrange reversion applies to a Lambert W sum: $$\W(x)=\ln(...
Тyma Gaidash's user avatar
5 votes
1 answer
288 views

Closed forms of the integral $ \int_0^1 \frac{\mathrm{Li}_n(x)}{(1+x)^n} d x $

(This is related to this question). How would one find the closed forms the integral $$ \int_0^1 \frac{\mathrm{Li}_n(x)}{(1+x)^n} d x? $$ I tried using Nielsen Generalized Polylogarithm as mentioned ...
Anomaly's user avatar
  • 107
0 votes
1 answer
431 views

What's a better time complexity, $O(\log^2(n))$, or $O(n)$?

(By $O(\log^2(n))$, I mean $O((\log n)^2)$ rather than $O(\log(\log(n)) )$ I know $O(\log(n))$ is better than $O(\log^2(n))$ which itself is better than $O(\log^3(n))$ etc. But how do these compare to ...
Henry Deutsch's user avatar
0 votes
1 answer
34 views

Proving $2^{\log^{1-\varepsilon}n}\in \omega(\operatorname{polylog}(n))$

Let $\varepsilon \in (0,1)$. I wish to show that $2^{\log^{1-\varepsilon}(n)}\in \omega(\operatorname{polylog}(n))$. I attempted to turn this into a function and use L'Hospital's rule but that got me ...
Michal Dvořák's user avatar
1 vote
1 answer
122 views

Show that $\int_0^1 \frac{Li_{1 - 2m}(1 - 1/x)}{x} dx = 0$.

I would like to show that,for $m \geq 2$, $$I_m := \int_0^1 \frac{\operatorname{Li}_{1 - 2m}(1 - 1/x)}{x} dx = 0$$ where $\operatorname{Li}_{1 - 2m}$ is the $1-2m$ polylogarithm (https://en.wikipedia....
jvc's user avatar
  • 2,073
4 votes
0 answers
81 views

How to derive this polylogarithm identity (involving Bernoulli polynomials)?

How can one derive the following identity, found here, relating the polylogarithm functions to Bernoulli polynomials? $$\operatorname{Li}_n(z)+(-1)^n\operatorname{Li}_n(1/z)=-\frac{(2\pi i)^n}{n!}B_n\!...
WillG's user avatar
  • 6,672
2 votes
1 answer
258 views

Generalized formula for the polylogarithm

Some time ago, I discovered the formula for repeated application of $z\frac{d}{dz}$ here. Recently, I thought about taking the function to which this would be applied to be the integral representation ...
Artur Wiadrowski's user avatar
5 votes
3 answers
258 views

How to find the exact value of $\sum_{n=1}^{\infty} \frac{\sin \left(\frac{n \pi}{4}\right)}{n^2 \cdot 2^{\frac{n}{2}}} $?

Once I met the identity $$ \boxed{S_0=\sum_{n=1}^{\infty} \frac{\sin \left(\frac{n \pi}{4}\right)}{2^{\frac{n}{2}}}=1}, $$ I first tried to prove it by $e^{xi}=\cos x+i\sin x$. $$ \begin{aligned} \...
Lai's user avatar
  • 22.3k
2 votes
1 answer
98 views

Function upper-bounding polylogarithm function when $0 < z < 1$

The polylogarithm function (aka Jonquière's function) is defined as $Li_s(z) = \sum_{k=1}^{\infty} z^k k^{-s}$. Is there a closed-form upper bound for this function when $s \leq -1$ and is real, and $...
Daniel-耶稣活着's user avatar
6 votes
1 answer
285 views

Calculate $\int _0^1\frac{\arcsin ^2\left(x\right)\ln \left(x\right)\ln \left(1-x\right)}{x}\:\mathrm{d}x$

this integral got posted on a mathematics group by a friend $$I=\int _0^1\frac{\arcsin ^2\left(x\right)\ln \left(x\right)\ln \left(1-x\right)}{x}\:\mathrm{d}x$$ I tried seeing what I'd get from ...
logandetner's user avatar

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