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187 votes
2 answers
31k views

Why do we not have spin greater than 2?

It is commonly asserted that no consistent, interacting quantum field theory can be constructed with fields that have spin greater than 2 (possibly with some allusion to renormalization). I've also ...
James's user avatar
  • 2,861
38 votes
4 answers
5k views

Scattering, Perturbation and asymptotic states in LSZ reduction formula

I was following Schwarz's book on quantum field theory. There he defines the asymptotic momentum eigenstates $|i\rangle\equiv |k_1 k_2\rangle$ and $|f\rangle\equiv |k_3 k_4\rangle$ in the S-matrix ...
SRS's user avatar
  • 26.8k
26 votes
1 answer
531 views

Is the converse of Weinberg's statement on the cluster decomposition principle true?

In Weinberg's "The Quantum Theory of Fields, Vol. 1", Section 4.4, page 182, the author says: We now ask, what sort of Hamiltonian will yield an $S$-matrix that satisfies the cluster ...
Gold's user avatar
  • 36.4k
22 votes
2 answers
6k views

What is the physical interpretation of the S-matrix in QFT?

A few closely related questions regarding the physical interpretation of the S-matrix in QFT: I am interested in both heuristic and mathematically precise answers. Given a quantum field theory when ...
newbie's user avatar
  • 221
21 votes
2 answers
4k views

Quantum Field Theory in position space instead of momentum space?

What are the reasons why we usually treat Quantum Field Theory in momentum space instead of position space? Are the computations (e.g. of Feynman diagrams) generally easier and are there other ...
Thomas's user avatar
  • 1,783
21 votes
1 answer
5k views

Unitary quantum field theory

What do physicists mean when they refer to a quantum field theory being unitary? Does this mean that all the symmetry groups of the theory act via unitary representations? I would appreciate if one ...
Yaniel Cabrera's user avatar
20 votes
2 answers
4k views

Equivalence Theorem of the S-Matrix

as far as I know the equivalence theorem states, that the S-matrix is invariant under reparametrization of the field, so to say if I have an action $S(\phi)$ the canonical change of variable $\phi \to ...
gaugi's user avatar
  • 355
19 votes
1 answer
5k views

Green's function in path integral approach (QFT)

After having studied canonical quantization and feeling (relatively) comfortable with it, I have now been studying the path integral approach. But I don't feel entirely comfortable with. I have the ...
Hunter's user avatar
  • 5,228
17 votes
2 answers
1k views

What physical processes other than scattering are accounted for by QFT? How do they fit into the general formalism?

For background, I'm primarily a mathematics student, studying geometric Langlands and related areas. I've recently been trying to catch up on the vast amount of physics knowledge I'm lacking, but I've ...
NewToPhysics's user avatar
17 votes
2 answers
441 views

Quantum symmetries: $S$ or $Z$?

Let $I$ be the action of some QFT (gauge-fixed and including all the necessary counter-terms); $S$ the associated scattering-matrix; and $Z$ the partition function (in the form of, say, a path ...
AccidentalFourierTransform's user avatar
17 votes
2 answers
685 views

Is there an analogue of the LSZ reduction formula in quantum mechanics?

In quantum field theory the LSZ reduction formula gives us a method of calculating S-matrix elements. In order to understand better scattering in QFT, I will study scattering in non-relativistic ...
Slayer147's user avatar
  • 1,045
16 votes
3 answers
11k views

What actually means to compute things at tree level?

In his QFT book, Matthew Schwartz first talks about tree level as follows: We will begin by going through carefully some of the predictions that the theory gets right without infinities. These are ...
Gold's user avatar
  • 36.4k
16 votes
1 answer
4k views

When we define the S-matrix, what are "in" and "out" states?

I have seen the scattering matrix defined using initial ("in") and final ("out") eigenstates of the free hamiltonian, with $$\left| \vec{p}_1 \cdots \vec{p}_n \; \text{out} \right\rangle = S^{-1} \...
A. Zerkof's user avatar
  • 163
16 votes
2 answers
2k views

CFT and the Coleman-Mandula Theorem

The Coleman-Mandula theorem states that under certain seemingly-mild assumptions on the properties of the S-matrix (roughly: one particle states are left invariant and the amplitudes are analytic in ...
Morrissey87's user avatar
15 votes
1 answer
2k views

Does de Sitter space admit an asymptotic S-matrix?

From the Penrose diagram of de Sitter space, we see it has a future and past conformal boundary, and they are both spacelike. So, does de Sitter space admit an asymptotic S-matrix? Sure, in the usual ...
inflation's user avatar
  • 245

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