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1 vote
0 answers
75 views

Scalar particle Compton scattering using relativistic Lagrangian formulation of electromagnetism

We know that parallel to scalar QED, a common formalism that describes a massive particle coupled to electromagnetism is through a relativistic worldline formalism, which writes $$\mathcal{S}=\int\ ds\...
khaki's user avatar
  • 76
0 votes
0 answers
60 views

How diagrams with loop and several propagators contribute to $S$-matrix element?

I studied Feynman rules with Schwartz textbook and what caught my eye was diagrams such as second and third on this picture (diagrams to the second order of $g$ for $\mathcal{L} = \frac{g}{3!}\phi^3$ ...
Михаил Полещук's user avatar
3 votes
0 answers
152 views

Finding the interaction vertices

Given a Lagrange density $$\mathcal{L} = \frac{1}{2}\partial_\mu \phi \partial^\mu \phi - \frac{m^2}{2}\phi^2 - \frac{\lambda_3}{3!}\phi^3 - \frac{\lambda_4}{4!}\phi^4$$ where $\phi$ is a scalar field,...
Geigercounter's user avatar
2 votes
1 answer
96 views

More general propagator of a real scalar field

I have some Lagrangian containing a real scalar field $\phi$ with mass $m$. Let $A \in \mathbb{R}$ be some constant. The Lagrangian takes the form: \begin{equation} \mathcal{L} = -\frac{A}{2} (\...
Mathphys meister's user avatar
3 votes
2 answers
466 views

What is the equivalence theorem in quantum field theory?

Let $L(\phi)$ be a Lagrangian and $\phi$ a quantum field. The equivalence theorem says that the $S$ matrix remains invariant under field redefinition. Let us take for example the Lagrangian $$L=\...
amilton moreira's user avatar
0 votes
0 answers
180 views

Proof of Weinberg effective field theorem?

In the book Effective field theory at page 6 there is this Weinberg's theorem To any given order in perturbation theory, and for a given set of asymptotic states, the most general possible ...
amilton moreira's user avatar
2 votes
0 answers
219 views

Classical action as $S$-matrix generating functional at the tree-level

I have seen repeated statements that the $S$-matrix generating functional at the tree-level is the same as the action calculated on the classical solutions of the equation of motion corresponding to ...
DGeometry's user avatar
1 vote
0 answers
159 views

Connected part of $S$-matrix generating functional

I am currently studying an article by A.Jevicki et. al. (https://doi.org/10.1103/PhysRevD.37.1485) and I am a little confused. They say that the generating functional of the $S$-matrix is related to ...
DGeometry's user avatar
2 votes
1 answer
360 views

S-matrix expansion for the $\phi^4$ theory and the interaction picture

My question is about the perturbative expansion of the S-matrix using Dyson's expansion. Let the Lagrangian density of the $\phi^4$ theory be \begin{equation} \mathcal{L} = \frac{1}{2}\left[\partial_\...
dsfkgjn's user avatar
  • 107
10 votes
4 answers
615 views

Why can we shift the field $\phi$, so that $\langle \Omega | \phi(x) | \Omega \rangle = 0$?

Problem Introduction In different derivations of the LSZ reduction formula the author makes a shift of the field $\phi(x)$ $$ \phi'(x) = \phi(x) - \langle \Omega | \phi(x) | \Omega \rangle, $$ and ...
Gabor's user avatar
  • 199
3 votes
0 answers
723 views

S-matrix for $\phi^3$ theory

In the book Quantum Field Theory for the gifted amateur by Tom Lancaster & Stephen J Blunden, in the chapter about expanding the S matrix they give an example using the $\phi^4$ Langrangian, $$ \...
Tom Csiz's user avatar