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2 votes
3 answers
112 views

How do vacuum bubbles "dress" terms in the $S$-matrix numerator?

I am self-studying QFT using the book "A modern introduction to quantum field theory" by Maggiore. On page 124-125 he's doing the calculation in the interaction picture for a process with ...
Andrea's user avatar
  • 613
0 votes
1 answer
124 views

The definition of the path integral

I still have big conceptual questions about the path integral. According to (24.6) of the book "QFT for the gifted amateur" from Lancaster & Blundell the path integral is equal to $$Z =\...
Frederic Thomas's user avatar
1 vote
0 answers
147 views

LSZ reduction formula relation

LSZ formula gives a relation between the scattering amplitudes and correlators as $$\langle f |i \rangle = (-i)^{m+n}\int \Pi_{i=1}^m d^4x_, e^{ik_i'x_i (\Box_{x_i} -m^2)}\Pi_{j=1}^n d^4x_, e^{ik_j ...
Monopole's user avatar
  • 3,464
2 votes
0 answers
219 views

Classical action as $S$-matrix generating functional at the tree-level

I have seen repeated statements that the $S$-matrix generating functional at the tree-level is the same as the action calculated on the classical solutions of the equation of motion corresponding to ...
DGeometry's user avatar
1 vote
1 answer
339 views

$S$-matrix elements in path integral approach

How to calculate $S$-matrix elements of quantum electrodynamics using path integral formalism?
talari suresh's user avatar
10 votes
4 answers
615 views

Why can we shift the field $\phi$, so that $\langle \Omega | \phi(x) | \Omega \rangle = 0$?

Problem Introduction In different derivations of the LSZ reduction formula the author makes a shift of the field $\phi(x)$ $$ \phi'(x) = \phi(x) - \langle \Omega | \phi(x) | \Omega \rangle, $$ and ...
Gabor's user avatar
  • 199
3 votes
2 answers
313 views

Which vacuum do I use for the path-integral?

In Weinberg, vol. 1, Section 9.2, Weinberg defines the in and out vacua as states with no particles (9.2.4): $$a_{\rm in}|{\rm VAC,in}\rangle=0$$ $$a_{\rm out}|{\rm VAC,out}\rangle=0$$ He does this ...
Eric David Kramer's user avatar
3 votes
0 answers
292 views

Can interacting quantum field theory describe more than just scattering?

From my understanding we do not yet know how to make much out of interacting QFT other than scattering amplitude at asymptotic infinity. (Correct me if I misunderstand.) But path integral, in ...
Mike Mcmaster's user avatar
6 votes
1 answer
674 views

Why the vacuum-to-vacuum amplitude?

I am reading "QFT in a Nutshell" by Zee, and the beginning of the book progresses like this: Section I.2: Show how $\langle q_F|e^{-iHt}|q_I\rangle=\int Dq\ e^{iS}$. p. 12: Says that we ...
Alex1994's user avatar
3 votes
1 answer
614 views

Clarification of Path Integral formulation

I am reading from Schwarz book on QFT the Path Integral chapter and I am confused about something. I attached a SS of that part. So we have $$\langle\Phi_{j+1}|e^{-i\delta H(t_j)}|\Phi_{j}\rangle=N \...
Alex Marshall's user avatar
17 votes
2 answers
441 views

Quantum symmetries: $S$ or $Z$?

Let $I$ be the action of some QFT (gauge-fixed and including all the necessary counter-terms); $S$ the associated scattering-matrix; and $Z$ the partition function (in the form of, say, a path ...
AccidentalFourierTransform's user avatar
8 votes
2 answers
488 views

In Feynman functional integrals why do we integrate the action over all time?

Say the definition of a propagator in quantum field theory is: $$G_F(x,y)=\int \phi(x)\phi(y) e^{i S[\phi] } D\phi$$ where $S$ is the action. Why do we integrate the Lagrangian density from $t=-\...
user avatar
2 votes
0 answers
877 views

Foundation of path Integral formulation of QFT, derivation and meaning of LSZ formulas

I'm currently studying path integral in quantum field theory. I am comfortable with path integrals, and also path integral formulation of QM, but I was asking if there is a self consistent coherent ...
13 votes
2 answers
3k views

Physical meaning of partition function in QFT

When we have the generating functional $Z$ for a scalar field \begin{equation} Z(J,J^{\dagger}) = \int{D\phi^{\dagger}D\phi \; \exp\left[{\int L+\phi^{\dagger}J(x)+J^{\dagger}(x)}\phi\right]}, \end{...
Orca's user avatar
  • 1,336
4 votes
0 answers
992 views

Polology in Functional Integration

Completeness of Hilbert space (on-shell states) is a very powerful concept in canonical quantization, for example, to study the nonperturbative characteristics of the S-matrix, like polology (pole and ...
user109798's user avatar

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