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0 votes
1 answer
154 views

Peskin & Schroeder equation (7.2)

I found this completeness relation of momentum eigenstate $|\lambda_p\rangle$ Here $|\Omega\rangle$ is the vacuum, and $|\lambda_p\rangle$ represents the state with one particle labeled by $\lambda$ ...
FIA's user avatar
  • 1
2 votes
0 answers
77 views

LSZ theorem for trivial scattering

The $1\to1$ scattering amplitude is trivial and is given by (take massless scalars for simplicity) $$ \tag{1} \langle O(\vec{p}) O^\dagger(\vec{p}\,')\rangle = (2 | \vec{p}\,|) (2\pi)^{D-1} \delta^{(...
stringynonsense's user avatar
2 votes
0 answers
81 views

Why Fock representation holds only in a free quantum field theory?

With a quantum system with $N$ degrees of freedom, all the representations are unitarily equivalent to Fock representation. However, if the number of degrees of freedom goes to infinity, there are ...
MBlrd's user avatar
  • 159
-3 votes
1 answer
91 views

Some calculation in Mahan book, p73 [closed]

On page 73 of Mahan, Many-particle physics, 3rd edition, one finds $$ _0\langle|S(-\infty,0) = e^{-iL}_0\langle|S(\infty,-\infty)S(-\infty,0). $$ I'm wondering why this is true, as in the previous ...
user2820579's user avatar
0 votes
1 answer
117 views

Problem with understanding the concept of vacuum state of a quantum field

The vacuum state is the state with the minimum energy, which implies no excitations, which I assume is the same as a state with no particles. Then I am confused about a static electric coulomb field. ...
Pato Galmarini's user avatar
9 votes
4 answers
3k views

If quantum fields are operator valued distributions, why aren't they always smeared?

I don't completely understand the distributional character of a quantum field because I never see them "smeared" in basic textbooks. As I understand it, if $\chi : \mathcal{F} \rightarrow \...
R. M.'s user avatar
  • 615
-1 votes
1 answer
249 views

What does the field operator $φ(x)$ do to the Fock space?

For simplicity: imagine a free, scalar theory, and a 1 particle universe. Spacetime: we have an operator $φ(x)$ defined everywhere on spacetime. Fock space: the space of states in which the particle ...
TrentKent6's user avatar
0 votes
1 answer
114 views

Can we construct the QFT Fock space with only field operators $φ(x)$ acting on the vacuum?

We always hear that The Fock space is constructed with multiple $~a^\dagger_{\vec p}$ acting on the vacuum for different values of ${\vec p}$ (we can use alternatives notations to ${\vec p}$ because ...
TrentKent6's user avatar
-2 votes
1 answer
144 views

Does the QFT Klein-Gordon equation describe the state of the field or the field operator?

In the canonical quantization of QFT we talk about: states representing a field. field operators. The quantum Klein-Gordon equation is expressed in terms of the field φ. Is φ (in the equation) the ...
TrentKent6's user avatar
3 votes
1 answer
153 views

Equivalence of Schrödinger operator formalism and Path Integral Formulations for Scalar Field Theory

I'm exploring the deep connections between different formulations of quantum field theories and have a specific question about the equivalence between the Schrödinger representation and the path ...
Anon21's user avatar
  • 1,548
0 votes
1 answer
64 views

The relation between spin and momentum in particle state

In quantum field theory, it seems that when we consider a massive particle's spin degree of freedom, we usually do in the particle's rest frame. And I know the little group will only change spin DOF ...
Haiqin Tang's user avatar
2 votes
1 answer
284 views

How to derive the Fermion generating function formally from operator formalism?

The generating functionals for fermions is: $$Z[\bar{\eta},\eta]=\int\mathcal{D}[\bar{\psi}(x)]\mathcal{D}[\psi(x)]e^{i\int d^4x [\bar{\psi}(i\not \partial -m+i\varepsilon)\psi+\bar{\eta}\psi+\bar{\...
Bababeluma's user avatar
1 vote
0 answers
73 views

Convergence of series of elements in a quasi-local algebra

I am studying the quasi-local algebra on Bratteli and Robinson Operator Algebras and Quantum Statistical Mechanics, but there is one thing that is not clear to me at the moment. Let's say that the ...
MBlrd's user avatar
  • 159
0 votes
1 answer
106 views

How does Weinberg definition of particle states from standard momentum work?

In his first volume, part 2.5, Weinberg define one particle states $Φ_{p,𝜎}$ ($p$ is the momentum and $𝜎$ another quantum number) in the following way : Choose a Standard momentum $k$ Find a ...
Samael's user avatar
  • 43

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