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1 vote
0 answers
90 views

In the path integral formulation of QFT, how do we get quantized particles out of a field?

Every QFT textbook starts by basically postulating that we have discrete states connected by creation and annihilation operators. In Quantum Mechanics, we started from a differential equation and ...
A. Kriegman's user avatar
  • 1,262
3 votes
1 answer
153 views

Equivalence of Schrödinger operator formalism and Path Integral Formulations for Scalar Field Theory

I'm exploring the deep connections between different formulations of quantum field theories and have a specific question about the equivalence between the Schrödinger representation and the path ...
Anon21's user avatar
  • 1,548
2 votes
1 answer
284 views

How to derive the Fermion generating function formally from operator formalism?

The generating functionals for fermions is: $$Z[\bar{\eta},\eta]=\int\mathcal{D}[\bar{\psi}(x)]\mathcal{D}[\psi(x)]e^{i\int d^4x [\bar{\psi}(i\not \partial -m+i\varepsilon)\psi+\bar{\eta}\psi+\bar{\...
Bababeluma's user avatar
8 votes
2 answers
575 views

Why is the limiting operator in the CFT state-operator correspondence well-defined, and why is conformal symmetry necessary?

Consider a Euclidean CFT in radial quantisation, and let $S$ be the unit sphere centred on the origin. The state-operator correspondence says that any state $\Psi_S$ living on $S$ can be prepared by a ...
nodumbquestions's user avatar
8 votes
4 answers
2k views

How to connect the usage of the path integral in QFT to the usage in Quantum Mechanics?

In Quantum Mechanics, path integrals are used to calculate the matrix element: $$ \langle x_1, t_1|x_2, t_2\rangle_J=\int e^{i(S[x(t)]+\int\!J x(t))/\hbar} d[x(t) ].\tag{1}$$ If we naively try to ...
Ryder Rude's user avatar
  • 6,355
1 vote
1 answer
102 views

Handling the $\nabla \phi$ term in the Hamiltonian in a path integral

Let the scalar Hamiltonian be of the form $H = \int d^3x \left [\hat{\pi}^2 + (\nabla \hat{\phi})^2 + m^2\hat{\phi}^2 \right ]$. We wish to evaluate the quantity $\langle \phi_f | \exp(-iHt) | \phi_i \...
Angela's user avatar
  • 1,023
1 vote
1 answer
83 views

Clarification regarding the terminology of Microstates

I would like to understand how microstates are defined or used in physics. Are microstates suppose to only mean eigenvalues of a given observable (or a generator of symmetry)? The reason for my ...
Dr. user44690's user avatar
2 votes
2 answers
367 views

Partition function for bosons with path integral

In this book the partition function for bosons is defined in eq. 2.17 as: $$Z=\mathrm{Tr}[e^{-\beta (H-\mu_i N_i)}]=\sum_a\int d\phi_a\langle\phi_a|e^{-\beta(H-\mu_i N_i)}|\phi_a\rangle$$ The ...
user avatar
7 votes
3 answers
1k views

Euler-Lagrangian equation of motion of quantum fields in QFT

A canonical way of doing quantum field theory is by starting with some Lagrangian, for example, that of free scalar field $$L=\frac{1}{2}\partial_{\mu}\phi \partial^{\mu}\phi-\frac{1}{2}m\phi^2$$ Then ...
Tan Tixuan's user avatar
6 votes
2 answers
1k views

Expectation values in path integral formalism

In quantum field theory, it is often assumed that the expectation value $\langle A\rangle$ of an operator $A$ can be written in the path integral formalism in the following way: $$ \langle A\rangle = \...
HelloGoodbye's user avatar
0 votes
1 answer
98 views

Functional representation of operators in second quantization

In path integral formalism, the operator $\hat{a}$ and $\hat{a}^\dagger$ represented by numbers $\alpha$ and $\bar{\alpha}$ according to $\hat{a}$|$\alpha$⟩=$\alpha$|$\alpha$⟩ and <$\alpha$|$\hat{a}...
Solidstate's user avatar
4 votes
1 answer
486 views

Preparing States using path integral in QFT

I had some confusion about the idea of cutting the path integral to define states in quantum field theory. There are two versions which I have seen: We do the path integral with an unspecified '...
Tushar Gopalka's user avatar
2 votes
2 answers
484 views

Path integral identity

I am reading the Background Field Methods in the EPFL Lectures on GR as an EFT. The authors use this identity on Page 23, Equation (174): $$ \mathcal{N}^{-1}\int\mathcal{D}\phi\,\mathcal{D}\phi^*\exp\{...
Nihar Karve's user avatar
  • 8,492
3 votes
1 answer
449 views

Vacuum energy of a free scalar field from path integral

My question has been asked two other times: Spinor vacuum energy (misleading title) and Vacuum Energy Calculation using Path Integral. I am not completely satisfied with the answers and it looks like ...
hodop smith's user avatar
7 votes
1 answer
206 views

Choice of folliation in path integral

Assume we have a scalar field theory for a field $\phi$. Can we think of the Hilbert space as being spanned by states of the form $|\varphi\rangle$ for configurations $\varphi\in C^\infty(\mathbb{R}^3)...
Ivan Burbano's user avatar
  • 3,915

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