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2 votes
0 answers
63 views

Hilbert Space in Categorical Gauged TQFT

I am trying to understand how gauge theory interacts with the categorical formulation of TQFT. I will formulate my doubts in two different questions. I have understood gauging a TQFT in different ...
Badillo's user avatar
  • 53
2 votes
1 answer
90 views

Peskin and Schroeder's discussion of the BRST operator

On page 519 of Peskin and Schroeder, the authors have the following discussion on the nilpotent BRST operator $Q$ that commutes with the Hamiltonian $H$. Many eigenstates of $H$ must be annihilated ...
Simplyorange's user avatar
0 votes
0 answers
67 views

Unitarity gauge

Weinberg in Chapter 21, section 21.1, QFT 2, says that, in unitarity gauge $\tilde{\phi}_n(x) = \gamma^{-1}_{nm}(x)\phi_m(x)$, we do not have degrees of freedom with negative probability, like time-...
physicsbootcamp's user avatar
4 votes
1 answer
365 views

Intuition for Hilbert space of a quantized gauge theory

In the standard explanation, the physical Hilbert space of a quantized gauge theory (such as QCD) is given by the cohomology of the BRST charge acting on some larger, unphysical Hilbert space. More ...
nodumbquestions's user avatar
4 votes
1 answer
207 views

Is unphysical states still unphysical in an interaction theory?

Maggiore A modern introduction to quantum field theory Section 4 : In free quantum electromagnetic field theory... since only the two degree of freedom transverse wave, the energy, and the momentum, ...
ShoutOutAndCalculate's user avatar
5 votes
0 answers
106 views

How do you write a resolution of unity (the identity) in gauge theories?

In, say, a quantum field theory of a single scalar field $\phi$, it is common to write the identity as ${\bf 1}=\int{\cal D}\phi\, |\phi\rangle\langle \phi|$, a useful thing to do in various path ...
user26866's user avatar
  • 3,492
5 votes
4 answers
504 views

Gauge ghosts & unphysical states in gauge theory

I have a general question about a statement from Wikipedia about ghost states as occuring in gauge theory: "In the terminology of quantum field theory, a ghost, ghost field, or gauge ghost is an ...
user267839's user avatar
  • 1,395
4 votes
1 answer
310 views

BRST symmetry, gauge invariance and longitudinal gauge bosons

While quantizing a non-Abelian gauge theory covariantly, we first demand that the BRST charge acting on the physical states of the Hilbert space must be zero. However such physical states still have ...
Sounak Sinha's user avatar
3 votes
1 answer
390 views

Negative norm for bosons and fermions

How comes negative norm is such a big thing for fermions that Dirac equation was chosen over KG, while the same kind of problem for photons is just ok? In fact, many books in QED do not even mention ...
MsTais's user avatar
  • 1,184
3 votes
1 answer
129 views

Question on BRST closed vectors which are also co-closed

I'm studying the BRST quantization formalism from this reference. I have a question though, about page 44. The author introduces a co-BRST operator on the extended Hilbert space (which also include ...
Kamil's user avatar
  • 701
6 votes
0 answers
260 views

Is the vacuum degenerate in the Abelian Higgs model?

Consider the theory with Lagrangian $$ \mathcal{L} = -\frac{1}{4}F_{\mu \nu} F^{\mu \nu} + (D_\mu \phi)^* (D^\mu \phi) - U(\phi) \,, $$ where $U(\phi)$ breaks the $U(1)$ symmetry of the system. If we ...
gj255's user avatar
  • 6,425
2 votes
1 answer
150 views

How is the state $|a_0 a_i\rangle$ physical?

For a state $|\psi\rangle$ to be physical we require that: $$\langle\psi|a_0^\dagger a_0|\psi\rangle = \langle\psi|a_i^\dagger a_i|\psi\rangle$$ It is always said that physical state must contain ...
gertian's user avatar
  • 1,323
0 votes
1 answer
687 views

Negative norm states

If we have negative norm states such that $[a,a^\dagger]=-1$ how do we treat the normalization of two particle states ? Suppose: $|aa\rangle = N a^\dagger a^\dagger |0\rangle$, after some work we ...
gertian's user avatar
  • 1,323
2 votes
0 answers
201 views

Weaker Gupta-Bleuler conditon $<\psi|(\partial_\mu A^\mu)^2|\psi> = 0$

Some context In the Gupta Bleuler quantization procedure for gauge fields we introduce the gauge fixing term: $$S_{GB} = \int dV-\frac{1}{2}(\partial_\mu A^\mu)^2$$ to the Lagrangian. After ...
gertian's user avatar
  • 1,323
3 votes
1 answer
524 views

$U(1)$ Faddeev-Popov formalism

What is the correct series expansion for the $U(1)$ Faddeev-Popov ghosts? I know that the $U(1)$ ghosts are only a phase such that they can be neglected in most cases but it turns out that this is ...
gertian's user avatar
  • 1,323

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