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14 votes
8 answers
2k views

Why can't we define arbitrarily large sets yet after defining these axioms? (Tao's Analysis I)

In Tao's Analysis I I am very confused why he says we do not have the rigor to define arbitrarily large sets after defining the below 2 axioms: Axiom 3.4 If $a$ is an object, then there exists a set $...
Princess Mia's user avatar
  • 3,019
1 vote
2 answers
142 views

proving the set of natural numbers is infinite (Tao Ex 2.6.3)

Tao's Analysis I 4th ed has the following exercise 3.6.3: Let $n$ be a natural number, and let $f:\{i \in \mathbb{N}:i \leq i \leq n\} \to \mathbb{N}$ be a function. Show that there exists a natural ...
Penelope's user avatar
  • 3,325
-1 votes
1 answer
90 views

What is the intuitive meaning of natural numbers as constructed in ZF set theory?

My understanding is that in elementary set theory, the natural numbers are defined so that $0 = \emptyset$ and $n+1 = n \cup \{ n \}$. I understand that this gives us some very pleasant properties ...
Kevin's user avatar
  • 483
2 votes
1 answer
33 views

Equivalent characterizations of finite sets

How can we show that the following notions of finiteness for a nonempty set $X$ are equivalent? There exists $n \in \mathbb{N}$ such that there is an injection $X \hookrightarrow \{1, \ldots, n\}$ ...
Smiley1000's user avatar
  • 1,649
2 votes
0 answers
86 views

Is there a name for this set-theoretical definition of natural numbers, or has it been invented?

I'll call it the binary encoding with sets. I think it's nice and trivial, should have been discovered by many genius brains, but i can't find it by searching with efforts. Prior arts are Zermelo's ...
Farter Yang's user avatar
0 votes
1 answer
136 views

Does Cantor’s theorem rely on the Empty Set being in the power set of a set?

As I understand, Cantor’s diagonal set can be empty, that is, there could be a mapping from the the Natural Numbers to the Power Set of the Natural Numbers in which the empty set is not mapped. The ...
PedroCazorla's user avatar
4 votes
0 answers
115 views

Show that $f(a,b,c)=(a+b+c)^3+(a+b)^2+a$ is injective.

For a function $f : \mathbb{N} \times \mathbb{N} \times \mathbb{N} \rightarrow \mathbb{N}$ defined by $f(a,b,c)=(a+b+c)^3+(a+b)^2+a$ I want to show that $f$ is injective. How can I show this? I ...
bel0906's user avatar
  • 41
0 votes
1 answer
163 views

Proving (rigorously) that the number of $m$ element subsets of an $n$ element set is ${n \choose m}$

I am trying to solve the following problem (Amann & Escher Analysis I, Exercise I.6.3): Show that the number of $m$ element subsets of an $n$ element set is ${n \choose m}$. I emphasize that the ...
EE18's user avatar
  • 1,143
0 votes
0 answers
40 views

Induction principle in its set formulation and in its property formulation: which one to use in a well-redacted Induction Step of an induction?

I have read this answer about the well ordering principle and the induction principle. It especially says that "any proper axiomatization of $\mathbb N$ in modern logic does not involve set-...
niobium's user avatar
  • 1,231
0 votes
0 answers
32 views

Partitioning $\mathbb{N}$ into infinitely many infinite pairwise disjoint sets [duplicate]

Find an infinite collection of infinite sets $A_1,A_2,A_3\ldots$ such that $A_i\cap A_j=\emptyset$ for $i≠j$ and $$\bigcup_{i=1}^{\infty}A_i=\mathbb{N}.$$ My Attempt: Let $p_i$ be the $i^{\textrm{th}}...
aqualubix's user avatar
  • 2,145
3 votes
1 answer
103 views

Bijection between $\mathbb{N}$ and the set of finite parts of $\mathbb{N}$

Let $\mathbb{N} = \{0,1,2,3,...\}$ be the set of natural numbers (with $0$) and $\mathbb{F}$ the set of finite parts of $\mathbb{N}$. I want to find a bijection, as simple as possible, between $\...
user700974's user avatar
0 votes
0 answers
30 views

Elementary question regarding various definitions of the integers and naturals

So the question is as follows We need to prove that $\mathbb{\mathbb{Z}}$ is the same set as the following three sets (i) $\{x\in\mathbb{R}\hspace{0.1cm}|\hspace{0.1cm}x\in\mathbb{\mathbb{N}}\hspace{...
Math Monk's user avatar
1 vote
0 answers
106 views

Can every bijection of natural numbers be defined with a closed form formula

I am interested in the existance of closed form formulas for bijections on natural numbers. With the term closed form is lose. Any information on formulas that represent permutations on N are welcomed....
Urh's user avatar
  • 47
2 votes
1 answer
186 views

Is the set of all linear orders on $\mathbb{N}$ linearly orderable?

In studying the issue of linear orders and well ordering in the context of ZF Set Theory (without the Axiom of Choice), I have recently been thinking about the following question: Is the set of all ...
FD_bfa's user avatar
  • 4,331
1 vote
1 answer
76 views

how many linear orderings on $\omega$ the are and how can we identify when 2 of them are in fact isomorphic.

how many linear orderings on $\omega$ the are and how can we identify when 2 of them are in fact isomorphic. I think that by instability argument there are $2^{\aleph_0}$ of them, but I do not know ...
user122424's user avatar
  • 3,978
0 votes
1 answer
125 views

What is the cardinality of non-singleton subsets of $\mathbb{N}$?

I am studying a course on ZF Set Theory (without the Axiom of Choice) and am currently looking at the cardinalities of infinite sets. One question that I came across is the following: Determine the ...
FD_bfa's user avatar
  • 4,331
3 votes
1 answer
490 views

Is this exercise from Tao's Analysis 1 erroneous?

On page 68 of the fourth edition of Tao's Analysis 1, is Exercise $3.5.12$, the first part of which I believe is erroneous. The exercise is stated as follows: (Note: $n++$ refers to the successor of $...
Gaurav Chandan's user avatar
0 votes
2 answers
120 views

Constructing the power set of natural numbers

Consider the set of Natural numbers, $\mathbb{N}$, and a particular natural number, $n$. Consider $A_n$ to be the set of all subsets of $\mathbb{N}$ whose size is $\leq n$. Now as we take $n$ to ...
Kushal Shah's user avatar
1 vote
1 answer
75 views

How do you prove that there exists a highest element of any finite, nonempty subset of Natural Numbers? Is the following algorithmic proof valid?

Since the given set, $C \subset \mathbb{N}$ is non empty, hence by well ordering principle there exists $\alpha \in C$ which is the lowest element in C. Also, since the set $C$ is finite, $\quad \...
Pragnya Jha's user avatar
1 vote
1 answer
25 views

Function that generates 2 indexes for nested subsets

I'm doing a problem and looking for some way to create a specific bijection between $\mathbb{N}$ and my set $W$. $W$ is a set that contains infinite subsets $Y_n$. Each of these subsets contains every ...
DeepQuantum's user avatar
0 votes
0 answers
24 views

How to count a number of elements in a set with subsequent natural numbers and why substracting the lowest number from the highest is wrong??

I just started learning math from 0 and looking for explanation I have a set {18,...,32} and the task is to find its cardinality. I was thinking that substracting the lowest (18) from the highest (32) ...
Mikhail Gaponov's user avatar
4 votes
1 answer
115 views

Can One Discuss Induction without Sets?

The standard presentation of mathematical induction involves subsets having a certain property. Here is a typical formulation from Gallian's Contemporary Abstract Algebra, Ninth edition: It seems to ...
Gary's user avatar
  • 515
0 votes
2 answers
78 views

Is this an adequate proof that any non-empty subset of N has a minimal element?

I am trying to improve my own standards for proof writing, but I cannot attend school, so I do not have the luxury of being able to speak to professors or peers to verify my attempts. In the proof ...
davidyoungog's user avatar
1 vote
1 answer
57 views

How do I define the proper subset $\bigcup\limits_{i=1}^\infty[n^2,n^2+1]$ of a set $\bigcup\limits_{i=1}^\infty[n,n+1]$

I have to determine if the set $T=\bigcup\limits_{i=1}^\infty[n^2,n^2+1]$ is bounded and find the supremum and infimum if they exist. Clearly, $T=\{[1,2], [4,5], [9,10]...\}$ it is clearly bounded ...
Daniel Jago's user avatar
0 votes
1 answer
56 views

Describing $\mathbb{N}$ with multiples of $4\mathbb{N}$

Suppose we index subsets of the natural numbers in the following way. $$\begin{matrix} X_2 = 4 \mathbb{N} &Y_2 = 8\mathbb{N} \\ X_3 = 16\mathbb{N} & Y_3 = 32\mathbb{N} \\ X_4 = 64\mathbb{N} &...
Grigor Hakobyan's user avatar
1 vote
1 answer
171 views

Unboundedness of infinite subsets of natural numbers

$\newcommand{\N}{\mathbb{N}}$ I am trying to show that every infinite subset of $\N$ is unbounded, that is, $$ \forall A \subseteq \N: (|A| = |\N| \Rightarrow \forall m \in \N:\exists n \in A:m < n)...
Hermis14's user avatar
  • 2,617
2 votes
3 answers
134 views

How to show that this set is finite?

Let $m \in \mathbb{N}$ For $\alpha = (\alpha_{1},...,\alpha_{m}) \in \mathbb{N}_{0}^{m}$, let $|\alpha|:= \alpha_{1}+...+\alpha_{m}$ Is the set $\{\alpha \in \mathbb{N}_{0}^{m}: |\alpha|\leq k\}$ ...
123123's user avatar
  • 296
0 votes
1 answer
41 views

Family set of subsets of $\Bbb N$

Let $g:\Bbb N\times\Bbb N \to\Bbb N$ biyective s.t. $g(n, m) = 2^{n-1}(2m-1)$. Show that there exists a famaily set $\{C_n : n \in\Bbb N\}$ of subsets of $\Bbb N$, infinites, disjoints pairwise and ...
PanChan's user avatar
1 vote
1 answer
1k views

The set of Fibonacci numbers formalized in set-theoretic notation: did I do it correctly?

The set of Fibonacci numbers $= \displaystyle \{x_i \in \Bbb N_0 : x_i = x_{i-1} + x_{i-2} \ \forall \ i \in \Bbb N_2 : x_0 + x_1 =1, >\}$. Is this correct notation? The $>$ at the end is ...
user110391's user avatar
  • 1,129
0 votes
2 answers
306 views

How to prove that there are $n$ natural numbers that are less or equal than $n$ and what properties are allowed to use in induction.

Let $n \in \mathbf{N}$. I wondered how to prove that there are exactly $n$ natural numbers that are smaller or equal than $n$. This seems somewhat circular which confuses me. I guess the way to do ...
MaxH's user avatar
  • 389
1 vote
1 answer
55 views

Finiteness, finite sets and representing its elements.

A set $S$ is called finite if there exists a bijection from $S$ to $\{1,...,n\}$ for one $n \in \mathbf{N}$. It is then common to write its elements as $s_1,...,s_n$. I now wonder, why this is ...
MaxH's user avatar
  • 389
0 votes
3 answers
258 views

Can the natural numbers contain an element that is not representable by a number?

I read the following document: https://www.math.wustl.edu/~freiwald/310peanof.pdf . In this document, the author wants to formalize that natural numbers, that are informally thought of as a collection ...
MaxH's user avatar
  • 389
0 votes
2 answers
100 views

Directly proof $S$ is countable, where $S$ is set of function from $\{0, 1\}$ to $\mathbb{N}$

Suppose $S=\{f_1,f_2,f_3,f_4,f_5,........\}$ where $f_i$ is a function $f:\{0, 1\}\to\mathbb{N}.$ I have to prove $S$ is countable.Then need to prove direct one-to-one correspondence between $S$ and $\...
user avatar
2 votes
1 answer
106 views

Why Cantor diagonalization theorem is failed to prove $S$ is countable, Where $S$ is set of finite subset of $\mathbb{N}$?

I have an given set $S$ where $S=$ set of finite subsets of $\mathbb{N}.$ We need to prove $S$ is countably infinite. My approach: I need to prove there is one-to-one correspondence between $S$ and ${\...
user avatar
-1 votes
1 answer
173 views

Why bijection between $\mathbb{N^2}$ and $\mathbb{N}$ is not possible directly?

To understand bijection between $\mathbb{N^2}$ and $\mathbb{N}$ I found this pdf on internet. But have couple of confusion. N.B: Here we take $0 \in \mathbb{N}.$ Confusion:1 Why directly proof of ...
S. M.'s user avatar
  • 1
0 votes
0 answers
209 views

Are odd natural numbers an inductive set?

The definition of inductive set my textbook gave is: A set $T$ that is a subset of the integers is an inductive set provided that for each integer $k$, if $k$ is an element in the set $T$, then $k+1$ ...
Throw Away's user avatar
0 votes
0 answers
103 views

Why is the principle of induction for natural numbers not "self-evident"? [duplicate]

The principle of induction can be stated, in first-order logic, as follows. Let $S\subseteq\mathbb N$, and suppose that $0\in S$. $\forall n:n\in S\to n+1\in S$. Then, $S=\mathbb N$. Now, suppose ...
Joe's user avatar
  • 20.7k
-1 votes
1 answer
135 views

$X$ is infinite thus we have an injection from $\mathbb{N}$ to X [duplicate]

Hey guys I'm trying to prove the following: $X=\emptyset \lor$ There is a surjection $g: \mathbb{N} \rightarrow X \implies X$ is finite $\lor$ there is a Bijection from $\mathbb{N}$ to X I did case ...
Iwan5050's user avatar
  • 385
2 votes
0 answers
128 views

Statement of Well-ordering principle

The statement of well ordering principle appears in different mode - on subsets of natural numbers, or well-ordering of every (non-empty) set. For the question below, I am considering it w.r.t. non-...
Maths Rahul's user avatar
  • 3,047
1 vote
0 answers
515 views

Adding a Fixed Value to Each Element in a Set (How to Denote)

To denote a set such as, for example, the set of every natural number that is 3 greater than a multiple of 5, would $5\mathbb{N}+3$ be generally understood as $\{8,13,18,23,28,33,\dots\}$? If not, how ...
Mathgodpi's user avatar
3 votes
3 answers
187 views

Infinite natural numbers?

Only using the successor function $\nu$ and the other axioms, how do we guarantee that the "next" generated number is different from all the "previous" numbers (I am using ...
Roger Crook's user avatar
3 votes
1 answer
364 views

Showing that the natural numbers are totally ordered with respect to set membership

Working with the usual set theoretic construction of the natural numbers, denoted $\omega$ for now. I am trying to show that $\omega$ is totally ordered with respect to set membership, that is, $n<...
C Squared's user avatar
  • 3,612
0 votes
1 answer
85 views

In ZFC, do we use the set $\mathbb{N}$ in the definition of $\mathbb{N}$ recursively?

In ZFC set theory, we define the set of the natural numbers as follows: By the axiom of infinity, an inductive set exists. Let I be an inductive set. Then, $\mathbb{N}$ is defined as $\{ x\in I |\...
boyler's user avatar
  • 375
0 votes
0 answers
118 views

A Doubt about Well Ordering Principle and Principle of Mathematical Induction

I have had this lingering doubt in my mind for a very long time: One of the standard constructions of N starts by assuming the 5 Peano Axioms, proving that every non-zero is a successor and s(n) is ...
Tara Nanda's user avatar
0 votes
1 answer
33 views

Defining $A \in \mathcal{P}(\Bbb N \times\Bbb N)$ such that it is not any member of a countable subset $M \subseteq \mathcal{P}(\Bbb N \times \Bbb N)$

$ \newcommand{\N}{\mathbb{N}} \newcommand{\P}{\mathcal{P}(\N \times \N)} \newcommand{\set}[1]{\left\{ #1 \right\}} \newcommand{\i}{^{(i)}} \newcommand{\x}{^{[x]}} \newcommand{\y}{^{[y]}} \newcommand{\...
PrincessEev's user avatar
  • 45.9k
0 votes
2 answers
105 views

Is there a specific symbol for $\mathbb{N}\cup\lbrace 0\rbrace$? [duplicate]

It is well known that natural numbers start in 1. However, sometimes people work with a "widened set" of natural numeres plus zero, $\mathbb{N}\cup\lbrace 0\rbrace$. That is, all non-...
FGSUZ's user avatar
  • 164
1 vote
2 answers
96 views

Is this the right way to view infinity in real analysis?

So, I've lately been having confusion on how to understand infinity, but I think I have progress in my intuition. So, I'd appreciate if someone would let me know if I'm on the right track, and which ...
Caleb Briggs's user avatar
  • 1,093
0 votes
1 answer
79 views

Set of all finite subsets of $\mathbb{N}$ not equal to the to set of subsets of $\mathbb{N}$

I can kind of grasp why this is the case as if we take the union of all finite subsets of cardinality $i$ as $i$ runs through every natural number, we are listing finitely many elements each time. ...
Governor's user avatar
  • 459
0 votes
2 answers
231 views

Is the set of all natural numbers acctually a proper class?

I have been searching about the difference between a set and a class. The main definitions I found can be resumed in “all sets are classes, but not all classes are sets. If a class is not a set, then ...
user avatar
4 votes
2 answers
176 views

Is my proof that the Sharkovsky Ordering is a total ordering, correct?

The Sharkovsky ordering is an ordering of the natural numbers $\mathbb{N}$, where $3$ $\prec$ $5 $ $\prec$ $7 $ $\prec$ $9$ $\prec$ ... $2*3$ $\prec$ $2*5$ $\prec$ $...
Linchen's user avatar
  • 85

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