Skip to main content

Questions tagged [cardinals]

This tag is for questions about cardinals and related topics such as cardinal arithmetics, regular cardinals and cofinality. Do not confuse with [large-cardinals] which is a technical concept about strong axioms of infinity.

1 vote
0 answers
54 views

Injective monotonic mapping from rationals $\mathbb Q^2$ to $\mathbb R$

Exercise: $f: \mathbb Q^2\to\mathbb R$. Where $\mathbb Q$ is the set of rational numbers. $f$ is strictly increasing in both arguments. Can $f$ be one-to-one? This question is related to many ...
High GPA's user avatar
  • 3,824
1 vote
0 answers
44 views

Can a countable union of subgroups of uncountable index in G be equal to G? [closed]

Let G be a group and $\{H_i\}_{i<\omega}$ be a countable family of subgroups of $G$, each of them of uncountable index. Can $G=\bigcup_{i<\omega} H_i$?
Moreno Invitti's user avatar
2 votes
4 answers
231 views

Is the cardinality of $\varnothing$ undefined?

It is intuitive that the cardinality of the empty set is $0$. However we are asked to demonstrate this using given definitions/axioms in Tao Analysis I 4th ed ex 3.6.2. My question arises as I think ...
Penelope's user avatar
  • 3,325
0 votes
0 answers
43 views

How does measure theory deal with higher cardinalities?

The second part of the definition of a sigma-algebra is that countable unions of measurable sets are measurable. The second property of a measure is that the measure of countable unions of measurable ...
TheOwl's user avatar
  • 11
0 votes
0 answers
56 views

On the Singular Cardinal Hypothesis

I'm trying to find the proof of this result. If for each $\lambda\geq2^\omega$, $\lambda^\omega\le\lambda^+$, then the SCH holds. I'm not sure where to look. So if you have any info about this, please ...
Selena's user avatar
  • 103
0 votes
1 answer
66 views

Why is $\{0,1\}^{\Bbb N}$ uncountable? [duplicate]

In the book Measure and Integral : An introduction to real analysis, in chapter 8 Lp spaces, theorem 8.18, the authors give a counterexample to show that $l^\infty$ is not separable: Question: why is ...
G.t.g.h's user avatar
  • 161
0 votes
0 answers
29 views

Cardinal sum of powers

I'm trying to solve this exercise. Can anybody please help me: If $\kappa$ ist an infinite cardinal number with $cf(\kappa) = \kappa$ and for all $\mu < \kappa$ the inequality $2^{\mu} \leq \kappa$ ...
Johannes's user avatar
0 votes
0 answers
34 views

For all cardinals $\kappa, \lambda$ with $\lambda \geq cf(\kappa)$ the inequality $\kappa^{\lambda} > \kappa$ holds [duplicate]

I genuinely have no idea why the proposition in the title holds or how to show it. I am kind of new to cardinals and ordinals and very confused. If someone could explain, I would really appreciate ...
metamathics's user avatar
1 vote
0 answers
92 views

Cardinal power towers

I am not an expert on large cardinals. I could not find any reference (and terminology) for the following question: We start with $$\lambda:=\aleph_0 \text{ [tet] } \omega = \aleph_0 ^ {\aleph_0 ^ {\...
Cem Aksak's user avatar
0 votes
0 answers
25 views

Would well-founded Scott cardinals work in ZCA + Ranks?

Does original Zermelo's set theory + Regularity + Ranks, prove that every set is of equal size to some element of a Scott cardinal? The original Zermelo does include an axiom of Choice, and it admits ...
Zuhair's user avatar
  • 4,631
1 vote
1 answer
119 views

The cardinality of specific set $A\subset \mathbb{N}^{\mathbb{N}}$

Let $A$ be a set of total functions from the naturals to the naturals  such that for every $f\in A$ there is a finite set $B_f\subset \mathbb{N}$ , such that for every $x\notin B_f$ , $f(x+1)=f(x)+1$. ...
Daniel's user avatar
  • 83
4 votes
1 answer
82 views

Induction does not preserve ordering between cardinality of sets?

Consider building a binary tree and consider it as a collection of points and edges. Here is one with five levels, numbered level $1$ at the top with $1$ node to level $5$ at the bottom with $16$ ...
jdods's user avatar
  • 6,360
3 votes
1 answer
107 views

A family of $\kappa^{<\omega}$ such that for every member in $\kappa$ is contained by all but finitely many elements of the family

Suppose that $\kappa$ is an uncountable cardinal. Let $\kappa^{<\omega}$ denote the family of all finite subsets of $\kappa$. Does there exist a family $S\subset\kappa^{<\omega}$ such that for ...
Jianing Song's user avatar
  • 1,923
0 votes
0 answers
55 views

How should I should prove $\mathbb{R}\sim\{0,1\}^{ \mathbb{N}}$ [duplicate]

I've seen some argument about the binary representation, but I think it is not accurate because under some extreme cases, the rounding or bit constraint would results distinct reals also have the same ...
LJNG's user avatar
  • 1,364
2 votes
1 answer
308 views

Dependence of the equation $a+1=a$ for infinite cardinals $a$ on the axiom of choice

let $A$ be a set such that for all $n \in $ N $ A ≉ N_n$ where $N_n = \{ 0 ,1 ,2 ...... n-1\} $ and $a$ be the Cardinality of $A$ meaning ($|A| = a$) is it possible to prove that $a+1=a$ without ...
theorem 28's user avatar

15 30 50 per page