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1 vote
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A sequence of continuum hypotheses

The continuum hypothesis asserts that $\aleph_{1}=\beth_{1}$. Both it and its negation can be consistent with ZFC, if ZFC is consistent itself. The generalised continuum hypothesis asserts that $\...
Darmani V's user avatar
  • 290
1 vote
1 answer
83 views

Can cardinality $\kappa$ exist where $\forall n\in\mathbb{N} \beth_n<\kappa$,$\kappa<|\bigcup_{n\in\mathbb{N}}\mathbb{S}_n|$,$|\mathbb{S}_n|=\beth_n$

The Wikipedia article on Beth numbers defines $\beth_\alpha$ such that $\beth_{\alpha} =\begin{cases} |\mathbb{N}| & \text{if } \alpha=0 \\ 2^{\beth_{\alpha-1}} & \text{if } \alpha \text{ is a ...
SarcasticSully's user avatar
1 vote
1 answer
116 views

$\omega$-th or $(\omega + 1)$-th when putting odd numbers after even numbers?

The following clip is taken from Chapter 4 - Cantor: Detour through Infinity (Davis, 2018, p. 56)[2]. When putting odd numbers after even numbers, what should the index for the first odd number ($1$ ...
Yif's user avatar
  • 103
1 vote
0 answers
67 views

How is transifnite recursion applied?

I've been struggling to understand how ordinal addition, multiplication, and exponentiation, along with the Aleph function $\aleph$, are defined using Transfinite Recursion in Jech's Set Theory or ...
Sam's user avatar
  • 5,166
2 votes
1 answer
90 views

What is cardinality of ordinal exponentiation?

Using von Neumann definition of ordinals, is it true that for all cardinal numbers $a$ and $b$ the following equation holds: $$ a^b = |a^{(b)}| $$ where on the left side is the cardinal exponentiation ...
Iskander's user avatar
2 votes
1 answer
166 views

What ways are there to define $\aleph$?

I've seen some posts on this website that consist in providing and comparing different proofs of a theorem (e.g. for Taylor's Theorem or trigonometric identities). Currently I'm reading Holz's ...
Sam's user avatar
  • 5,166
2 votes
1 answer
58 views

Why does regularity of an ordinal $\gamma$ imply the existence of a sequence $(\delta_n)$ such that $\delta_n<\gamma$ for all $n$?

Source: Set Theory by Kenneth Kunen. Lemma III.6.2: Let $\gamma$ be any limit ordinal, and assume that $\kappa:=cf(\gamma)>\omega$. Then the intersection of any family of fewer than $\kappa$ club ...
Dick Grayson's user avatar
  • 1,467
0 votes
1 answer
61 views

Proof of the Reflection Theorem in Kunen?

I'm reading Kunen's Set Theory and the last line of the proof of the Reflection theorem (page 131) is a bit puzzling to me. To those not in possession of Kunen at the moment, the book states verbatim: ...
J.R.'s user avatar
  • 481
0 votes
0 answers
27 views

Being unbounded in a limit ordinal implies order type is also a limit?

Whilst trying to follow a proof from my lecture notes, I stumbled upon the following: $$\gamma \text{ limit, }A\subseteq \gamma, \sup A=\gamma\implies \text{type}(A)\text{ limit}$$ It sounds true, ...
J.R.'s user avatar
  • 481
1 vote
1 answer
63 views

Why do we define cardinality only for well-orderable sets?

I'm revising Kunen's Set Theory and he mentions that when we define the cardinality of a set, we should do it with well-orderable sets. Why is this the case? He points to a section which contains many ...
J.R.'s user avatar
  • 481
0 votes
0 answers
71 views

An infinite linear system of equations with an uncountable number $A$ of equations

I will start with an example to make things clear and avoid confusion : Take all $x>0$ and $$\exp(x) = \sum_{-1<n} a_n x^n$$ Now finding $a_n$ can be described as an infinite linear system of ...
mick's user avatar
  • 16.4k
1 vote
2 answers
62 views

Show that $\{\alpha<\omega_1 : L_\alpha \prec L_{\omega_1}\}$ is closed unbounded in $\omega_1$.

I was doing this exercise and there is a hint to consider the Skolem functions for $L_{\omega_1}$. However, I did not find any general definition of what a Skolem function may be in Kunen (1980), and ...
Derewsnanu's user avatar
8 votes
1 answer
109 views

What does the cardinality alone of a totally ordered set say about the ordinals that can be mapped strictly monotonically to it?

For any cardinal $\kappa$ and any totally ordered set $(S,\le)$ such that $|S| > 2^\kappa$, does $S$ necessarily have at least one subset $T$ such that either $\le$ or its opposite order $\ge$ well-...
Transfinite Pyramid Scheme's user avatar
-3 votes
1 answer
73 views

Ordinal vs. Cardinal $0$ [closed]

From my files ... $1, 2, 3, ...$ are cardinals, they count as in $9$ trucks, $12$ voles, etc. First ($1^{st}$), Second ($2^{nd}$), etc. are ordinals, they're used to order stuff. Now, I've heard of ...
Hudjefa's user avatar
  • 983
4 votes
1 answer
183 views

Jech's proof of canonical well-ordering of $\alpha\times\alpha$.

I'm reading Jech's Set Theory. The canonical well-ordering of $\mathrm{Ord}\times\mathrm{Ord}$ is defined as $$( \alpha ,\beta ) < ( \gamma ,\theta ) :\begin{cases} \max\{\alpha ,\beta \} < \max\...
Zhang Xuan's user avatar

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