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0 votes
1 answer
72 views

Transforming the field strength tensor - Why do we need to use $\Lambda^T$, instead of a row times row multiplication?

The transformation law is \begin{align} F'^{\mu\nu} = {\Lambda^{\mu}}_{\alpha} {\Lambda^{\nu}}_{\beta} F^{\alpha \beta} = {\Lambda^{\mu}}_{\alpha} F^{\alpha \beta} {\Lambda^{\nu}}_{\beta} \end{align} ...
Quantumwhisp's user avatar
  • 6,763
0 votes
1 answer
65 views

Fraction with components of Lorentz transformation

I want to show how partial derivative transforms under a Lorentz transformation. Since the partial derivative has a fixed definition with respect to the $x$-coordinate it stays unchanged: $\partial_\...
Silas's user avatar
  • 425
2 votes
1 answer
171 views

Why not define tensors under Galilean or Poincare transformations?

I have seen vectors (and tensors, in general) defined under rotations, $$V^i=R^i_{~j}V^j$$ and under Lorentz transformations, $$V^{\prime\mu}=\Lambda^\mu_{~~\nu}V^\nu$$ where $R,\Lambda$ are the ...
Solidification's user avatar
0 votes
2 answers
53 views

Are these two "notations" the same? [closed]

Say we have a tensor $T^{\sigma\tau}$ and I want to now how it transforms, the transformation coefficients in terms of Lorentz transformation matrices would be: $$T^{\mu'\nu '} = L^{\mu '}{}_{\sigma}L^...
Madlad's user avatar
  • 11
0 votes
1 answer
80 views

About the Lorentz transformation in Spacetime and Geometry

In Spacetime and Geometry by Sean Carroll, page 18, he said "We will therefore introduce a somewhat subtle notation, by using the same symbol for both matrices, just with primed and unprimed ...
Lagrange629's user avatar
0 votes
0 answers
50 views

How is tensor analysis useful to Relativity? [duplicate]

How does the knowledge of tensor analysis and Differential Geometry help us understand the equations of General and Special Relativity?
Achyuth SS's user avatar
3 votes
1 answer
109 views

Proof that a Lorentz-invariant scalar function can only depend on scalar products

If we have a Lorentz-invariant scalar function $f$ of a single four-vector $x^{\mu}$ we can show that $f$ can only depend on $x^2$ (see Argument of a scalar function to be invariant under Lorentz ...
jkb1603's user avatar
  • 1,129
1 vote
3 answers
187 views

Confused about tensor notations of how vector and covectors act on each other

I'm learning/playing around with tensors and somehow got this contradiction, suppose $\{v_i\}$ and $\{w_i\}$ are basis for a vector space $V$ and $\{ v^i \}$ and $\{w^i\}$ are basis for the dual space ...
Tony.Y's user avatar
  • 33
1 vote
1 answer
173 views

Is there only one convention to define the electromagnetic field tensor?

I know that the electromagnetic field tensor depends on which metric is used. For example wikipedia uses the $(+---)$ sign convention, but in the Griffiths we have the $(-+++)$ sign convention. That's ...
Nicolas Schmid's user avatar
1 vote
0 answers
66 views

Doubt on transformation laws of tensors and spinors using standard tensor calculus and group theory

1) Introduction From standard tensor calculus, here restricted to Minkowski spacetime, we learned that: A scalar field is a object that transforms as: $$\phi'(x^{\mu'}) = \phi(x^{\mu})\tag{1}$$ A ...
M.N.Raia's user avatar
  • 3,085
2 votes
2 answers
265 views

Determinant of the inverse of a Lorentz transformation

In many text book (Ashok Das Quantum Field Theory) $$(\Lambda^T)_\nu{}^\mu=\Lambda^\mu{}_\nu$$ that gives $\Lambda^T$ = $\Lambda^{-1}$, where $\Lambda$ is Lorentz Transformation matrix. However, this ...
Vivek's user avatar
  • 45
1 vote
1 answer
219 views

How to contract spinor indices?

In normal vector representation, vectors can be contracted as follows: $$v^\mu v_\mu$$ with one covariant and one contravariant index. But in spinor representation, there are 4 possible type of ...
Habouz's user avatar
  • 1,324
6 votes
1 answer
527 views

Tensor manipulations in Landau & Lifschitz "Classical theory of fields"

Landau & Lifshitz "Classical theory of fields" section 6 p. 19 define: $$ df^{ik} = dx^i dx'^k - dx^k dx'^i $$ and $$ df^{*ik}=\frac{1}{2} \; \epsilon^{iklm}df_{lm} \tag{6.11} $$ and ...
Jordi Pinyol's user avatar
1 vote
1 answer
151 views

Is four-vector product always Lorentz invariant?

Let's say we have two four-vectors $a^{\mu}$ and $b^{\nu}$.Is it always true that any combination of those 4-vectors (1-rank tensors) multiplied together will yield an invariant quantity (0-rank ...
Rainbow's user avatar
  • 41
-1 votes
2 answers
61 views

Confusion about raising and lowering indices

Is it possible to take the following expression: $$U^\mu U^v\partial_\mu\partial_v$$ Where $U$ is the four-velocity, and simplify it the following way?: $$U^\mu U^v \eta_{\mu v}\partial^v\partial_v =c^...
Tachyon's user avatar
  • 633

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