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-4 votes
1 answer
66 views

Cannot understand this identity between kronecker and metric tensor [closed]

I'm working on Lorentz generators and I am really not able to understand this relation: $$\omega_{\rho \sigma} \eta^{\rho\mu} \delta^{\alpha}_{\nu} = \frac{1}{2}\omega_{\rho \sigma} \left(\eta^{\rho\...
Heidegger's user avatar
  • 361
0 votes
0 answers
29 views

Unclear passage in Lorentz generators derivation

It's not clear to me a passage, in the extraction of the generators of Lorentz's group acting on the Minkowksi's space points: we have \begin{equation*} \begin{split} x^{' \alpha} & = \Lambda^{\...
Heidegger's user avatar
  • 361
1 vote
1 answer
101 views

Question on the spinor Indices, in non-relativistic quantum mechanics

I've caught by a loop of: Standard texts of Non-Relativistic Quantum Mechanics $\to$ Representation theory of Lie groups and Lie algebras of $SO(3)$ and $SU(2)$ $\to$ Discussions of infinitesimal ...
BasicMathGuy's user avatar
5 votes
3 answers
836 views

Decomposition of product of two antisymmetric Lorentz tensors

Suppose I have a tensor $A_{\mu\nu}$ in the $(3,1)\oplus (1,3)$ representation of the Lorentz group where $(a,b) =(2s_a+1,2s_b+1)$. I was wondering on how to decompose explictly in terms of tensors ...
Fra's user avatar
  • 2,263
0 votes
2 answers
371 views

Riemannian and Weyl tensors as spinor representation

There is the way of converting vector indices to spinor indices, for example, Maxwell stress tensor $F_{[\mu\nu]}$ can be decomposed to $(1,0) \oplus (0,1)$ irreducible representations of $\mathfrak{...
Nikita's user avatar
  • 5,707
4 votes
3 answers
1k views

Showing that 4D rank-2 anti-symmetric tensor always contains a polar and axial vector

In my special relativity course the lecture notes say that in four dimensions a rank-2 anti-symmetric tensor has six independent non-zero elements which can always be written as components of 2 3-...
Alex Gower's user avatar
  • 2,604
1 vote
0 answers
58 views

Irrep of stress energy tensor

We have 4-tensor of second rank. For example energy-momentum tensor $T_{\mu\nu}$, which is symmetric and traceless. Then $T_{\mu\nu}=x_{\mu}x_{\nu}+x_{\nu}x_{\mu}$ where $x_{\mu}$ is 4-vector. Every ...
fika97's user avatar
  • 171
0 votes
1 answer
91 views

Which is correct definition between $J^i\equiv \frac{1}{2}\epsilon^i_{~jk}J^{jk}$ and $J^i\equiv \frac{1}{2}\epsilon^{ijk}J^{jk}$?

The generators of the Lorentz group are denoted by $J^{\mu\nu}$ (suppose they are defined in terms of raised indices, as shown). From this, in my opinion, the angular momentum generators $J^i$'s and $...
Solidification's user avatar
1 vote
2 answers
798 views

Symmetry under Lorentz transformation: precise definition

I am studying QFT but I need to fill some gaps in my comprehension of special relativity (I didn't study it very well and I know I still misunderstand things in S.R). In my book it is written: " A ...
StarBucK's user avatar
  • 1,450
1 vote
0 answers
84 views

Converting field equation from position to momentum space

Question I would like to convert the following equation on position space to an algebraic equation on momentum space. $$\partial^{\alpha\dot{\alpha}}\Phi_{\alpha\alpha_1\cdots\alpha_{A-1}\dot{\alpha}...
NormalsNotFar's user avatar
3 votes
1 answer
869 views

Lorentz Group Generators: Two Methods

Members of the Lorentz group obey $$\eta=\Lambda^{T}\eta\Lambda$$ where $\eta=\textrm{diag}(1,-1,-1,-1)$ is the Minkowski metric. First, in matrix form write $$\Lambda=I+T$$ where $T$ is an ...
klgklm's user avatar
  • 401
4 votes
1 answer
634 views

Srednicki QFT ch34: invariants of the Lorentz group

In chapter 34 of his Quantum Field theory handbook, Srednicki discusses invariants of the Lorentz group and how they appear in the decomposition in irreducible representations of Lorentz tensors. As ...
kuzine's user avatar
  • 141
9 votes
1 answer
526 views

Is the distinction between covariant and contravariant objects purely for the convenience of mathematical manipulation?

Two kinds of indices, covariant and contravariant, are introduced in special relativity. This, as far as I understand, is solely for mathematical luxury, i.e. write expressions in a concise, self-...
SRS's user avatar
  • 26.8k
3 votes
1 answer
1k views

Why is the Mixed Faraday Tensor a matrix in the algebra so(1,3)?

The mixed Faraday tensor $F^\mu{}_\nu$ explicitly in natural units is: $$(F^\mu{}_\nu)=\left(\begin{array}{cccc}0&E_x&E_y&E_z\\E_x&0&B_z&-B_y\\E_y&-B_z&0&B_x\\E_z&...
Selene Routley's user avatar
9 votes
2 answers
478 views

If $v_{a \dot{b}}$ transforms like a four-vector, what does $v_{a}^{\dot{b}}$ describe?

The $( \frac{1}{2}, 0)$ representation of the Lorentz group acts on left-chiral spinors $\chi_a$, the $( 0,\frac{1}{2} )$ representation on right-chiral spinors $\chi^{\dot a}$. The $( \frac{1}{2}, \...
Tim's user avatar
  • 1,872