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0 votes
2 answers
151 views

Dimension of a vector space of all tensors of rank $(k,l)$ in 4D

Dual vector space is the set of all linear functionals defined on a given vector space. The vector space and dual vector space is isomorphic and hence have the same dimension. A rank $(k,l)$ tensor is ...
Grace's user avatar
  • 310
3 votes
2 answers
397 views

Why is it difficult to define conserved quantities in general relativity as in special relativity?

How exactly are conserved quantities, i.e. mass, energy and momenta of a system computed in special relativity and why doesn't it work in general relativity? I know that the curvature of the spacetime ...
aceituna's user avatar
  • 113
4 votes
1 answer
454 views

Notation of Mixed Tensors: Risk of Confusing Index Positions?

The convention for notating indices of a tensor is to write a contravariant index superscript and a covariant index subscript. If one has a pure contravariant or a pure covariant tensor of $2$nd order,...
thorr's user avatar
  • 43
3 votes
4 answers
2k views

4-Vector Definition

In most places I've looked, I see that 4-vectors are defined as 4-element vectors that transform like the 4-position under lorentz transformation. This is typically accompanied by generally, $$\...
Captain Morgan's user avatar
0 votes
0 answers
103 views

Contracted product of matrices with Lorentz indices

Let $\mathbf{A}_\mu$ and $\mathbf{B}_\mu$ be two matrix-valued spacetime vectors, i.e. $(A_\mu)_{ab}$ and $(B_\mu)_{ab}$ and let $\mathbf{C}$ be a matrix in the same space (external to spacetime), i.e....
user avatar
-1 votes
2 answers
1k views

Off-diagonal terms in metric for 4D space-time [closed]

Consider a delta between two events in 4D space-time written as a 4-vector, $x^\mu=(dt, dR)$. The time $dt$ is a scalar difference in time. The 3-vector $dR$ points some direction in space. One ...
sweetser's user avatar
4 votes
1 answer
310 views

Proper time along path in Minkowski Space

Consider the path $x^\mu(u)$ in Minkowski space; such that: $$t = \frac{a}{c} \sinh(u) , \quad x = a \cosh(u) ,\quad y = 0 ,\quad z = 0 $$ where $a$ is a positive constant and $u$ is a parameter ...
Sarah Jayne's user avatar
5 votes
4 answers
3k views

How to prove the raising/lowering indices operation?

I've read this related question, though it didn't satisfy me; I hope this complements it. I know that if I contract a covariant tensor ${A_{\alpha\beta}}$ with a vector ${B^\beta}$, I get some other ...
user avatar