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1 vote
1 answer
144 views

Physical intuition for the Minkowski space?

As the title suggests, I am looking for physical intuition to better understand the Minkowski metric. My original motivation is trying to understand the necessity for distinguishing between co-variant ...
user10709800's user avatar
0 votes
1 answer
71 views

On covariant form of Lorentz equation

The non-relativistic version of Lorentz equation has the form $$m\frac{d\vec{v}}{dt}=q(\vec{E}+\vec{v}\times\vec{B}) $$ Where $\vec{v}, \vec{E}, \vec{B}$ refers to the velocity of charged particle, ...
paul230_x's user avatar
  • 1,752
0 votes
1 answer
69 views

Doubt about product of four-vectors and Minkowski metric [closed]

Given the Minkowski metric $\eta_{\mu\nu}$ And $\eta^{\mu\nu}\eta_{\mu\nu}$=4 I can write $\eta^{\mu\nu}\eta_{\mu\nu}k^{\mu}k^{\nu}$=$4k^{\mu}k^{\nu}$ But $\eta^{\mu\nu}\eta_{\mu\nu}k^{\mu}k^{\nu}$=$\...
rafa's user avatar
  • 13
2 votes
1 answer
110 views

Four-vector and Notation significance [closed]

As the title suggest, this has to do, on the most part, with four vector notation. I have a series of questions, the majority, related to this topic: 1- If we assume a lorentz boost in the x direction ...
imbAF's user avatar
  • 1,398
2 votes
1 answer
116 views

Contravariant Components (Susskind's book)

In his book about SR & classical field theory, Susskind generalizes from the differential of $X'$ (function differential) to any 4-vector. I got stuck there trying to figure out why it is ...
Steve Jolt's user avatar
2 votes
1 answer
171 views

Why not define tensors under Galilean or Poincare transformations?

I have seen vectors (and tensors, in general) defined under rotations, $$V^i=R^i_{~j}V^j$$ and under Lorentz transformations, $$V^{\prime\mu}=\Lambda^\mu_{~~\nu}V^\nu$$ where $R,\Lambda$ are the ...
Solidification's user avatar
1 vote
1 answer
219 views

How to contract spinor indices?

In normal vector representation, vectors can be contracted as follows: $$v^\mu v_\mu$$ with one covariant and one contravariant index. But in spinor representation, there are 4 possible type of ...
Habouz's user avatar
  • 1,324
0 votes
1 answer
486 views

Show that the contraction of a covector and a vector is Lorentz invariant

I just got Sean Carroll's Spacetime and Geometry: An Introduction to General Relativity a couple of weeks ago, and I have resolved to go through the entire book. In the first chapter, he prompts the ...
Chidi 's user avatar
  • 187
2 votes
2 answers
639 views

Trying to understand electric and magnetic fields as 4-vectors

I was trying to show that the field transformation equations do hold when considering electric and magnetic fields as 4-vectors. To start off, I obtained the temporal and spatial components of $E^{\...
user avatar
4 votes
3 answers
1k views

Showing that 4D rank-2 anti-symmetric tensor always contains a polar and axial vector

In my special relativity course the lecture notes say that in four dimensions a rank-2 anti-symmetric tensor has six independent non-zero elements which can always be written as components of 2 3-...
Alex Gower's user avatar
  • 2,604
5 votes
4 answers
3k views

Is the Four-gradient of a Scalar Field a Four-Vector?

Consider a scalar field $\phi$ as a function of spacetime coordinates $x^\mu$. The four-gradient of $\phi$ is given by \begin{equation} \frac{\partial \phi}{\partial x^\mu} = \left( \frac{\partial \...
Генивалдо's user avatar
0 votes
0 answers
211 views

What are covectors in special relativity?

In special relativity the purpose of vectors makes fairly intuitive sense, they represent a point in spacetime: $$x^{\mu}=\begin{pmatrix}x^0 \\ x^1 \\ x^2 \\ x^3\end{pmatrix}$$ and we can define the ...
Charlie's user avatar
  • 6,963
1 vote
3 answers
240 views

In electromagnetism, how do we know that either $F^{\mu\nu}$ or $A^\mu$ is a tensor?

In special relativity the partial derivative $\partial_\mu$ is a tensor. Now if some function $A^\mu$ was a tensor, then also the quantitiy $F^{\mu\nu}=\partial^\mu A^\nu - \partial^\nu A^\mu$ would ...
Diger's user avatar
  • 391
3 votes
3 answers
3k views

How to prove a 4D vector is a 4-Vector?

This is a fairly open ended question. Given a set of 4 Components, that is, a 4D Vector, what is the process for determining rather or not it is a "4-Vector" as defined in special relativity? I want ...
Mason Hargrave's user avatar
0 votes
2 answers
1k views

How does 4-vector notation work?

In particle physics we are going over 4-vector notation. However, my background on this is a little shaky, and I'm having difficulty differentiating the notation and visualizing what it actually means....
matryoshka's user avatar

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