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8 votes
1 answer
1k views

Topological degree of polynomial maps.

The $\mathbb{Z}_2$ topological degree of a (non-constant) polynomial in one variable, clearly, coincides with its degree as a polynomial, $\mod 2$. Consider further a polynomial self-mapping $F$ on ...
Pietro Majer's user avatar
  • 58.1k
9 votes
3 answers
696 views

references / general idea of kervaire invariant problem

There's a workshop at MSRI in a couple months on the Kervaire invariant problem that I'd really like to attend. I saw Hopkins speak about it a while back without understanding much of the talk, but I'...
Aaron Mazel-Gee's user avatar
17 votes
5 answers
3k views

Homologically trivial submanifolds

Unuseful prequel Let $M$ be a (compact, oriented, differentiable) manifold. Before knowing anything about homology theory a naif but clever mathematician may want to measure the holes in $M$ by the ...
Andrea Ferretti's user avatar
17 votes
2 answers
2k views

Is a conceptual explanation possible for why the space of 1-forms on a manifold captures all its geometry?

Let $M$-be a differentiable manifold. Then, suppose to capture the underlying geometry we apply the singular homology theory. In the singular co-chain, there is geometry in every dimension. We look at ...
Akela's user avatar
  • 3,669
24 votes
1 answer
5k views

Do "surjective" degree zero maps exist?

Is there a map $f\colon X \to Y$ of closed, connected, smooth and orientable $n$-dimensional manifolds such that the degree of $f$ is 0 but $f$ is not homotopic to a non-surjective map? Added: The ...
Thomas Kragh's user avatar
  • 2,560
13 votes
3 answers
3k views

Contractible manifold with boundary - is it a disc?

I'm sure this is standard but I don't know where to look. Let $M$ be a contractible compact smooth $n$-manifold with boundary. Does it have to be homeomorphic to $D^n$? What about diffeomorphic? [...
Sergei Ivanov's user avatar
20 votes
1 answer
2k views

Every Manifold Cobordant to a Simply Connected Manifold

I am wondering if it is true that every compact, connected, oriented manifold is cobordant to a simply connected manifold. I believe that some sort of surgery will do the trick. Roughly speaking, I ...
Justin Curry's user avatar
  • 2,694
39 votes
4 answers
7k views

Two kinds of orientability/orientation for a differentiable manifold

Let $M$ be a differentiable manifold of dimension $n$. First I give two definitions of Orientability. The first definition should coincide with what is given in most differential topology text books, ...
Anweshi's user avatar
  • 7,382

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