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5 votes
0 answers
127 views

Division of fibration by $\Sigma_{n}$ gives Serre fibration

This is related to a question posted on StackExchange: https://math.stackexchange.com/questions/4776877/left-divisor-of-a-fibration-by-compact-lie-group-is-a-fibration. The question there had received ...
TopologyStudent's user avatar
10 votes
2 answers
614 views

Homotopy properties of Lie groups

Let $G$ be a real connected Lie group. I am interested in its special homotopy properties, which distinguish it from other smooth manifolds For example $G$ is homotopy equivalent to a smooth compact ...
Arshak Aivazian's user avatar
1 vote
0 answers
136 views

Automorphism group of indefinite orthogonal Lie group $G=O(p,q)$ vs that of a double covering group $\tilde{G}$

Previously I mentioned in Automorphism group of a Lie group $G$ vs that of a double covering group $\tilde{G}$: same or not? that the automorphism group of a Lie group 饾惡 may be the same as that of ...
wonderich's user avatar
  • 10.4k
0 votes
0 answers
88 views

Automorphism group of a Lie group $G$ vs that of a double covering group $\tilde{G}$: same or not? [duplicate]

Previously there are some counterexamples given in Automorphism group of a Lie group $G$ vs that of a covering group $\tilde G$: same or not? such that the automorphism group of a Lie group 饾惡 is not ...
wonderich's user avatar
  • 10.4k
4 votes
1 answer
292 views

Atiyah-Bott-Shapiro generalization to $U(n) \to ({Spin(2n) \times U(1)})/{\mathbf{Z}/4}$ for $n=2k+1$

Atiyah, Bott, and Shapiro paper on Clifford Modules around page 10 shows two facts. 1 - There is a lift $U(n) \to Spin^c(2n)$ from $U(n) \to SO(2n)\times U(1)$. Also an embedding (injective group ...
袦邪褉懈薪邪 Marina S's user avatar
0 votes
1 answer
247 views

$SU(k)/SO(k)$ as a manifold, for each positive integer $k$ [closed]

The quotient space $SU(k)/SO(k)$ is also a homogeneous space constructed out of the Lie groups (special unitary $SU(k)$ and special orthogonal $SO(k)$). Because the $SO(k)$ may not be a normal ...
袦邪褉懈薪邪 Marina S's user avatar
8 votes
1 answer
218 views

Isomorphisms of Pin groups

My goal is to identify the $Pin$ group $$ 1 \to Spin(n) \to Pin^{\pm}(n) \to \mathbb{Z}_2 \to 1 $$ such that $Pin^{\pm}(n)$ are isomorphisms to other more familiar groups. My trick is that to look at ...
wonderich's user avatar
  • 10.4k
2 votes
0 answers
95 views

Compact $G$-ENR's and Euler characteristic computed with Alexander-Spanier cohomology with compact support

Let $(Z,A)$ a compact ENR pair, then $$\chi(Z)=\chi_c(Z-A)+\chi(A)$$ where $\chi_c$ is the Euler characteristic taken in Alexander-Spanier cohomology with compact support (ENR means euclidean ...
Victor TC's user avatar
  • 795
7 votes
1 answer
482 views

Classification of fibrations $\Bbb S^k\longrightarrow\Bbb S^d\longrightarrow B$

Does there exist a complete classification of all fiber bundles $\Bbb S^k\longrightarrow\Bbb S^d\longrightarrow B$, that is, fibrations of $\smash{\Bbb S^d}$ with each fiber homeomorphic to $\smash{\...
M. Winter's user avatar
  • 12.8k
3 votes
1 answer
331 views

Homotopy type of $SO(4)/SO(2)$

A classical result states that the quotient $SO(4)/SO(3)$ is homotopy equivalent to $S^3$. In fact, this can be stated in more general terms since $SO(n+1)/SO(n)$ has the homotopy type of $S^n$. What ...
X1921's user avatar
  • 325
10 votes
1 answer
720 views

What's the sufficient or necessary conditions for a manifold to have Lie group structure?

For example, given a Lie group, its fundamental group must be Abelian. So $\Sigma_g$ ($g>1$) can't have Lie group structure. We also know for $S^n$ only $n=0,1,3$ can have Lie group structures. ...
fff123123's user avatar
  • 249
2 votes
0 answers
69 views

Connected topological/Lie group $H$ and $Q$, inflate $Q$-cocycle to coboundary in $H$

I am interested in finding mathematical examples and criteria of inflating $Q$-cocycle to coboundary in $H$, under the requirement: (1) Both $H$ and $Q$ are connected topological groups or Lie groups (...
annie marie c艙ur's user avatar
18 votes
2 answers
1k views

Exotic smooth structures on Lie groups?

If a topological group $G$ is also a topological manifold, it is well-known (Hilbert's 5th Probelm) that there is a unique analytic structure making it a Lie group. However, for a compact Lie group $...
Piojo's user avatar
  • 773
2 votes
1 answer
244 views

How to extend an equivariant map from a compact Lie group

Let $G$ be a compact Lie group and let $H$ be a closed subgroup of it. Let $g$ be a torsion element of $G$ and $C_G(g)$ the centralizer of it. Let $Y$ be a $C_G(g)-$space. I'm working on the space $$...
Megan's user avatar
  • 1,030
7 votes
2 answers
711 views

Euler class of S^1-orbibundle

Given a topological space $M$ with a locally free $S^1$ action on it, assume the slice representation holds,(this is often the case, e.g. M is a smooth manifold) then this will make $M$ a principal $S^...
Shisen Luo's user avatar