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16 votes
0 answers
404 views

Is the oriented bordism ring generated by homogeneous spaces?

I am trying to find a Riemannian geometrically well-understood set of generators of the oriented bordism ring, including the torsion parts. By a set of generators, I mean that the set generates the ...
Zhenhua Liu's user avatar
2 votes
0 answers
132 views

Question about spin map

I'm confused with the following definition of a spin map. A spin map is a map $f: N\to M$ between differentiable manifolds such that their second Stiefel-Whitney classes are related $\omega_2(N)=f^*\...
Radeha Longa's user avatar
-1 votes
1 answer
752 views

Essential simple closed curves in a torus [closed]

Definition: By a closed curve in a surface $S$ we will mean a continuous map $S^1 \to S$. We will usually identify a closed curve with its image in $S$. A closed curve is called essential if it is not ...
T566y65tt's user avatar
  • 119
0 votes
1 answer
154 views

Why does $X_0\times S^1\simeq X-X_0$? [closed]

Let $X$ be an $n$-dimensional connected smooth manifold, and let $X_0$ be an embedded $(n-2)$-dimensional compact submanifold of $X$ with the trivial normal bundle. How do we get inclusion? $$X_0\...
Radeha Longa's user avatar
15 votes
6 answers
2k views

Any shortcuts to understanding the properties of the Riemannian manifolds which are used in the books on algebraic topology

I'm now attending a reading seminar on the algebraic topology. The seminar treats the book of Bott & Tu (Differential Forms in Algebraic Topology) and Milnor (Characteristic Classes). In those ...
gualterio's user avatar
  • 1,073
16 votes
1 answer
1k views

Is there an area-preserving diffeomorphism of the disk which is nowhere conformal?

This question is a cross-post. Let $D \subseteq \mathbb{R}^2$ be the closed unit disk. Does there exist a smooth area-preserving diffeomorphism $f:D \to D$ that does not have conformal points? I ...
Asaf Shachar's user avatar
  • 6,641
2 votes
0 answers
143 views

When are automorphisms of the cohomology ring realized by isometries?

Let $(M,g)$ be a closed smooth Riemannian manifold, and denote by $G$ a closed subgroup of its isometry group. By considering the maps $g^*$ induced by elements $g\in G$ in the (de Rham) cohomology $H^...
Renato G. Bettiol's user avatar
2 votes
0 answers
132 views

Do we have estimate like $\int_\gamma \alpha \le |\alpha| \cdot |\gamma|$? [closed]

Let $(X,g)$ be a compact smooth Riemannian manifold. It is known that $H^1(X, \mathbb R)\cong \mathrm{Hom} (\pi_1(X), \mathbb R)$, namely there is a natural pairing $$ H^1(X) \times \pi_1(X) \to \...
Hang's user avatar
  • 2,739
16 votes
2 answers
586 views

What is the weakest negative curvature condition ensuring a manifold is a $K(G,1)$?

The only statement I'm sure of is that any hyperbolic or Euclidean manifold is a $K(G,1)$ (i.e. its higher homotopy groups vanish), since its universal cover must be $\mathbb H^n$ or $\mathbb E^n$. ...
Tim Campion's user avatar
  • 62.6k