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11 votes
1 answer
325 views

Can a norm on polynomials be supermultiplicative?

A norm on a real algebra is supermultiplicative when $\lVert f\cdot g\rVert\geq\lVert f\rVert\cdot\lVert g\rVert$ for all $f$ and $g$ in the algebra. Is there a supermultiplicative norm on $\mathbb R[...
mr_e_man's user avatar
  • 5,726
6 votes
1 answer
6k views

Matrix Norm Bounds

A natural consideration of matrix norms is to compare them, and one of the many standard results on the induced 1, 2, and $\infty$-norms indicate that $$\frac{1}{\sqrt{n}}\|A\|_\infty\leq \|A\|_2\leq \...
Dustin Tran's user avatar
  • 1,793
5 votes
2 answers
256 views

Can a norm on polynomials be "almost multiplicative", even for large degrees?

Definition: A norm on a real algebra is called almost multiplicative if there are positive constants $L$ and $U$ such that, for all $f$ and $g$ in the algebra, $$L\lVert f\rVert\cdot\lVert g\rVert\;\...
mr_e_man's user avatar
  • 5,726
5 votes
0 answers
84 views

Gettings bounds for seminorms from bound of absolute value

On a compact domain $\Omega \subseteq \mathbb{R}^d$, we have a function $u(x) \in C^{\infty}(\Omega)$ with an approximation $u_h(x)$ with the following properties: $$ |u(x) - u_h (x)| \leq C h^{m+1} |...
Quang Thinh Ha's user avatar
4 votes
1 answer
59 views

After applying a sequence of involutory real matrices to a vector, is the norm of this vector bounded from below?

For $n,N \in \mathbb{N}$, let $A_1, \ldots, A_n$ be a finite sequence of involutory $(N \times N)$-matrices over $\mathbb{R}$, i.e. $A = A^{-1}$. We know, that the eigenvalues of any involutory matrix ...
Michael Kohlhaas's user avatar
4 votes
0 answers
379 views

Need to improve upper bound for $\| (uv^T + B)^{-1} \|$ (Sherman-Morrison formula)

I have a matrix $A \in \mathbb{C}^{n \times n}$ in the form $A = uv^T + B$, where $u,v \in \mathbb{C}^n$ and $B \in \mathbb{C}^{n \times n}$. I know $A$ is invertible and want to find an upper bound ...
Integral's user avatar
  • 6,574
3 votes
3 answers
363 views

Why $\|(A + cI)^{-1}x\|\leq \frac{\|x\|}{\lambda_{\min}(A)}$

Given $A\succ 0$ (positive-definite) and $c>0$, I am trying to show $$\|(A + cI)^{-1}x\|\leq \frac{\|x\|}{\lambda_{\min}(A)} \tag{1}$$ using information like this but without success so far. Could ...
Thoth's user avatar
  • 865
3 votes
2 answers
400 views

How to find upper and lower bound

Let $\Sigma \in S_{++}^n$ be a symmteric positive definte matrix with all diagonal entries one. Let $U \in R^{n \times k_1}$, $W \in R^{n \times k_2}$, $\Lambda \in R^{k_1 \times k_1}$ and $T \in R^{...
newbie's user avatar
  • 81
3 votes
0 answers
244 views

Upper bound the maximum column sum of a particular stochastic matrix

Let $(x_i)_{i=1}^N$ be a set of vectors in $\mathbb{R}^D$. Define the matrix $W \in \mathbb{R}^{N \times N}$ as: $W_{ij} = \frac{\exp(-||x_i-x_j||^2)}{\sum_k \exp(-||x_i-x_k||^2)}$ i.e. row $i$ of $...
hyunjik11's user avatar
2 votes
2 answers
673 views

If the expectation of the norm of random variable is bounded, does that imply that the expectation of the squared norm is bounded?

Let $\mathbf{x}$ be a random vector. If $\mathbb{E}[\|\mathbf{x}\|]$ is upper bounded, does that imply that $\mathbb{E}[\|\mathbf{x}\|^2]$ is also upper bounded? The Jensen's inequality goes the ...
Jorge del Val's user avatar
2 votes
1 answer
51 views

alternative asymptotic bounds

I have an $n$ by 1 vector of weights $w$, and an $n$ by $k$ matrix, $\Gamma$. I have that $w'w$ is $\mathcal{O}(1)$, $\frac{\Gamma'\Gamma}{n}=\mathcal{O}(1)$ and $\frac{\Gamma\Gamma'}{n}=\mathcal{O}(1)...
yungmist's user avatar
2 votes
1 answer
98 views

Show that $\sum_{k=0}^{N} |P(k)| \leq C(N) \int_{0} ^{1} |P(t)| dt $. [closed]

I’m attending a functional analysis course and I am given to solve this problem as an exercise but I’m a little bit disoriented and I don’t know what tools I can use to get it. Show that, for each $...
Maggie94's user avatar
  • 251
2 votes
0 answers
83 views

Upper bound in bayesian regression setting

Let $y_i = x_i^\top \beta + \epsilon_i$, $i=1,\ldots,n$; where $\epsilon_i$ are i.i.d. following a distribution with mean zero and unit variance, i.e., $\epsilon_i \sim P_{\epsilon_i}(0,1)$, $i=1,\...
newbie's user avatar
  • 81
2 votes
1 answer
227 views

Show that $\|A\|_{\infty} \leq \sqrt n \|A\|_2$

Question: Let $A \in \Bbb R^{m\times n}$. Show that $$\|A\|_{\infty} \leq \sqrt n \|A\|_2$$ Attempt: First, I tried invoking the SVD (Singular Value Decomposition) of $A$: $$\|A\|_\infty = \|UDV\|...
glowstonetrees's user avatar
1 vote
2 answers
3k views

Bound on l1 norm given bound on l2 norm

While doing self-study exercices, I found the following bound without explanation and was not able to see why it is always the case. I found some examples, it seems legitimate but I am unable to ...
Alf's user avatar
  • 91

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