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11 votes
1 answer
325 views

Can a norm on polynomials be supermultiplicative?

A norm on a real algebra is supermultiplicative when $\lVert f\cdot g\rVert\geq\lVert f\rVert\cdot\lVert g\rVert$ for all $f$ and $g$ in the algebra. Is there a supermultiplicative norm on $\mathbb R[...
mr_e_man's user avatar
  • 5,726
5 votes
2 answers
256 views

Can a norm on polynomials be "almost multiplicative", even for large degrees?

Definition: A norm on a real algebra is called almost multiplicative if there are positive constants $L$ and $U$ such that, for all $f$ and $g$ in the algebra, $$L\lVert f\rVert\cdot\lVert g\rVert\;\...
mr_e_man's user avatar
  • 5,726
1 vote
1 answer
36 views

Wrong defined/boundless $g \rightarrow\sum_{n = 1}^\infty\frac{g(\frac1n)}{2^n}$

Let's consider: $$f\colon (C[0,1], \Vert\cdot \Vert_1) \ni g\rightarrow \sum_{n=1}^\infty\frac{g(\frac1n)}{2^n}$$ I'm trying to check if this object is well defined. where $\Vert f \Vert_1 = \int_0^1|...
Lucian's user avatar
  • 1,787
1 vote
1 answer
133 views

Finding an upper bound on composite $C^{1}$ functions

The conditions for the problem I am currently tackling is as follows: Let $T, M > 0$. Define : $X_{T} := \{ u \in C^{1} ([0,T]) : ||u||_{T} \leq 2M \}$ where $||u||_{T} \ = \ ^{\text{sup}}_{t \in (...
gbnhgbnhg's user avatar
  • 467
1 vote
0 answers
99 views

Norm equivalence constants

Take a polynomial $g\in\mathbb{R}[\mathbf{x}]$, in $n$ variables and having some degree $d$, with $g(\mathbf{x})\geq 0$. We define the $p$-norms of $g$ as $$ \vert \vert g \vert \vert _{p} = \left( \...
SpicyJalapenos's user avatar
2 votes
1 answer
98 views

Show that $\sum_{k=0}^{N} |P(k)| \leq C(N) \int_{0} ^{1} |P(t)| dt $. [closed]

I’m attending a functional analysis course and I am given to solve this problem as an exercise but I’m a little bit disoriented and I don’t know what tools I can use to get it. Show that, for each $...
Maggie94's user avatar
  • 251