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0 votes
1 answer
54 views

Why is $\sum_{m=0}^{\lfloor xs\rfloor} 2 \binom{s}{m} p^m (1-p)^{s-m} \leq 2\exp{\left(-\frac{2(\lfloor xs\rfloor - sp)^2}{s}\right)}$

I am trying to understand few of the mathematical steps I have encountered in a paper, there are two of them (a) $\sum_{m=0}^{\lfloor xs\rfloor} 2 \binom{s}{m} p^m (1-p)^{s-m} \leq 2\exp{\left(-\frac{...
coolname11's user avatar
0 votes
0 answers
45 views

Inequality with Products and Sums

I need help to find a proof for the following inquality. Assuming that $ 0 \leq c_i \leq 1 $ and $ 0 \leq d_i \leq 1 $, show that $$ \prod_{i=1}^N (c_i + d_i - c_i d_i) \geq \prod_{i=1}^N c_i + \prod_{...
Duns's user avatar
  • 778
0 votes
0 answers
98 views

If $\sum_{i=1}^n x_i \ge a$, then what can we know about $\sum_{i=1}^n \frac{1}{x_i}$?

Suppose that $$\sum_{i=1}^n x_i \ge a$$ where $a>0$ and $x_i\in (0, b]$ for all $i$. Are there any bounding inequalities we can determine for $$\sum_{i=1}^n \frac{1}{x_i}?$$ I understand that $\...
BSplitter's user avatar
  • 1,615
0 votes
2 answers
93 views

Can someone give me a hint to this question concerning $\sum_{i=1}^n |x-i|$?

Find the smallest positive integer $n$ for which $|x − 1| + |x − 2| + |x − 3| + · · · + |x − n| \geq 2022$ for all real numbers $x$. I don't think I can combine any of these terms, right? So I started ...
bnkgfh's user avatar
  • 13
3 votes
3 answers
168 views

find a closed form formula for $\sum_{k=1}^n \frac{1}{x_{2k}^2 - x_{2k-1}^2}$

Let $\{x\} = x-\lfloor x\rfloor$ be the fractional part of $x$. Order the (real) solutions to $\sqrt{\lfloor x\rfloor \lfloor x^3\rfloor} + \sqrt{\{x\}\{x^3\}} = x^2$ with $x\ge 1$ from smallest to ...
user33096's user avatar
  • 2,031
7 votes
1 answer
184 views

Show that $|x_{k+1}-x_k| \leq 1$ (for $0<k<n$) implies $\sum_{k=1}^n |x_k| - \left|\sum_{k=1}^n x_k\right|\leq\lceil(n^2-1)/4\rceil$.

Let $n\ge 1$ be a positive integer and let $x_1,\cdots, x_n$ be real numbers so that $|x_{k+1}-x_k|\leq 1$ for $k=1,2,\cdots, n-1$. Show $$\sum_{k=1}^n |x_k| - \left|\sum_{k=1}^n x_k\right|\leq \left\...
user3379's user avatar
  • 1,837
1 vote
1 answer
64 views

If $a_sk^s+a_{s-1}k^{s-1}+...+a_0$ is the basis representation of $n$ with respect to the basis $k$. Then, $0<n\leq k^{s+1}-1$.

If $a_sk^s+a_{s-1}k^{s-1}+...+a_0$ is the basis representation of $n$ with respect to the basis $k$. Then, $$0<n\leq k^{s+1}-1$$. My attempt:- By basis represantation, we know that $0\leq a_j<k,...
Unknown x's user avatar
  • 849
1 vote
1 answer
95 views

Prove that $\frac{1}{kn} + \frac{1}{kn + 1} + \dotsb + \frac{1}{kn + n - 1} > n \left(\sqrt[n]{\frac{k+1}{k}} - 1 \right)$

Let $k,n \in \mathbb{Z}^+$ with $n > 1$. Prove that $$\frac{1}{kn} + \frac{1}{kn + 1} + \dotsb + \frac{1}{kn + n - 1} > n \left(\sqrt[n]{\frac{k+1}{k}} - 1 \right)$$ I roughly observe that AM-...
Krosin's user avatar
  • 374
15 votes
2 answers
608 views

The inequality $\,2+\sqrt{\frac p2}\leq\sum\limits_\text{cyc}\sqrt{\frac{a^2+pbc}{b^2+c^2}}\,$ where $0\leq p\leq 2$ is: Probably true! Provably true?

Let $p$ be a positive parameter in the range from $0$ to $2$. Can one prove that $$2 +\sqrt{\frac p2} \;\leqslant\;\sqrt{\frac{a^2 + pbc}{b^2+c^2}} \,+\,\sqrt{\frac{b^2 +pca}{c^2+a^2}}\,+\,\sqrt{\...
Hanno's user avatar
  • 6,528
6 votes
3 answers
208 views

Algebraic inequality $\sum \frac{x^3}{(x+y)(x+z)(x+t)}\geq \frac{1}{2}$

The inequality is $$\frac{x^3}{(x+y)(x+z)(x+t)}+\frac{y^3}{(y+x)(y+z)(y+t)}+\frac{z^3}{(z+x)(z+y)(z+t)}+\frac{t^3}{(t+x)(t+y)(t+z)}\geq \frac{1}{2},$$ for $x,y,z,t>0$. It originates from a 3-D ...
JohnnyC's user avatar
  • 1,250
6 votes
5 answers
333 views

Bounds on $S = \frac{1}{1001} + \frac{1}{1002}+ \frac{1}{1003}+\dots+\frac{1}{3001}$

$S = \frac{1}{1001} + \frac{1}{1002}+ \frac{1}{1003}+ \dots+\frac{1}{3001}$. Prove that $\dfrac{29}{27}<S<\dfrac{7}{6}$. My Attempt: $S<\dfrac{500}{1000} + \dfrac{500}{1500}+ \dfrac{...
user avatar
4 votes
1 answer
98 views

Prove the inequality $\sum_{cyc}\frac{a^3}{b\sqrt{a^3+8}}\ge 1$

Let $a,b,c>0$ and such $a+b+c=3$,show that $$\sum_{cyc}\dfrac{a^3}{b\sqrt{a^3+8}}\ge 1\tag{1}$$ I tried using Holder's inequality to solve it: $$\sum_{cyc}\dfrac{a^3}{b\sqrt{a^3+8}}\sum b\sum \...
math110's user avatar
  • 93.6k
4 votes
2 answers
124 views

If $a, b, c, d\in\mathbb R^+, $ then prove that $\displaystyle\frac{a-b}{b+c}+\frac{b-c}{c+d}+\frac{c-d}{d+a}+\frac{d-a}{a+b}\ge 0.$

My approach: We have: $\displaystyle\frac{a-b}{b+c}+\frac{b-c}{c+d}+\frac{c-d}{d+a}+\frac{d-a}{a+b}$ $\displaystyle=\frac{a+c}{b+c}-1+\frac{b+d}{c+d}-1+\frac{c+a}{d+a}-1+\frac{d+b}{a+b}-1$ $\...
Dhrubajyoti Bhattacharjee's user avatar
5 votes
4 answers
110 views

Prove that for every $n \in \mathbb{N}$ $\sum\limits_{k=2}^{n}{\frac{1}{k^2}}<1$ [duplicate]

$$\sum\limits_{k=2}^{n}{\frac{1}{k^2}}<1$$ First step would be proving that the statement is true for n=2 On the LHS for $n=2$ we would have $\frac{1}{4}$ therefore the statement is true for $n=...
Vicente Martinez's user avatar
5 votes
2 answers
364 views

How to find range $a_{75}$ of the term of the series $a_n=a_{n-1}+ {1 \over {a_{n-1}}} $ [duplicate]

If $a_1=1$ and for n>1$$a_n=a_{n-1}+ {1 \over {a_{n-1}}} $$ $a_{75}$ lies between (a) (12,15) (b) (11,12) (c) (15,18) Now , in this question, I rewrote, $a_n-a_{n-1} = {1 \over {a_{n-1}}}$, to ...
Mr.HiggsBoson's user avatar
3 votes
3 answers
172 views

Proving $a^2 + b^2 + c^2 \geqslant ab + bc + ca$

Let $a, b, c \in \mathbb{R}$. Show that $a^2 + b^2 + c^2 \geqslant ab + bc + ca$. My reasoning went as follows and I would like to know if it's correct. $a^2 + b^2 + c^2 \geqslant ab + bc + ca$ $\...
user avatar
5 votes
2 answers
520 views

Prove that $\sum_{i=1}^n\frac{x_i}{\sqrt[nr]{x_i^{nr}+(n^{nr}-1)\prod_{j=1}^nx^r_j}} \ge 1$ for all $x_i>0$ and $r \geq \frac{1}{n}$.

Prove that, for all $x_1,x_2,\ldots,x_n>0$ and $r \geq \frac{1}{n}$, it holds that $$\sum_{i=1}^n\frac{x_i}{\sqrt[nr]{x_i^{nr}+(n^{nr}-1)\prod \limits_{j=1}^nx^r_j}} \ge 1.$$ This is a slightly ...
Hulkster's user avatar
  • 2,040
2 votes
4 answers
139 views

How do we prove this inequality?

Suppose $a,b,c > 0$. Prove that $$\frac{a^2}{b^2} +\frac{b^2}{c^2} + \frac{c^2}{a^2} \geq \frac ab + \frac bc + \frac ca.$$ I've tried multiplying everything by the denominator and then I tried to ...
Jesus's user avatar
  • 1,798
2 votes
2 answers
72 views

Interesting Inequality With Exponents And Base > 1

I had trouble proving the following inequality: $\beta > 1$ $(\alpha_{1}\beta^{2\alpha_{1}} + \ldots + \alpha_{n}\beta^{2\alpha_{n}})(\beta^{\alpha_{1}} + \ldots + \beta^{\alpha_{n}}) \geq (\...
Rehaan Ahmad's user avatar
0 votes
4 answers
51 views

Prove using squared number property

$$ If \sum_{i=1}^{10} x_i=10 $$ Prove that $$ \sum_{i=1}^{10} x_i^2\ge 10 $$
Mahmudul Hasan's user avatar
1 vote
3 answers
40 views

How do we know that $\sum\limits_{k=1}^n\left(\frac{a}{b}\right)^{k-1}< n $?

I'm trying to convince myself that $$b^n - a^n < (b-a)nb^{n-1}$$ when $0 < a < b$ and $n>1$. I will be persuaded once I can show that $$\sum\limits_{k=1}^nb^{n-k}a^{k-1}=b^{n-1}\sum\...
actinidia's user avatar
  • 3,425
2 votes
0 answers
38 views

Upper bound on $\frac{v_{1}}{1-c_{1}x}+\cdots+\frac{v_{n}}{1-c_{n}x}$

Let $v_{1},\ldots,v_{n}$ and $c_{1},\ldots,c_{n}$ be real numbers such that $v_{i}=2\alpha_{i}^{2}$ and $c_{i}=2\alpha_{i}$ for some $\alpha\ge 0$. My question is the following: Can I get, for $x\ge 0$...
nemo's user avatar
  • 638
0 votes
1 answer
53 views

Need help showing that $0.1\ge \sum_{n=n_r}^{\infty}P(n; \mu=0.85) \implies 0.9 \le \sum_{n=0}^{n_r-1}P(n; \mu=0.85)$

I have the following 'homework style' question which I will quote word for word: A test is done to check for a predicted atomic spectral line by counting the number of photons emitted from a ...
BLAZE's user avatar
  • 8,528
2 votes
1 answer
160 views

How to prove that $ \Bigg(\sum^{n}\limits_{k=1}\sqrt{\frac{k-\sqrt{k^{2}-1}}{\sqrt{k(k+1)}}}\Bigg)^{2} \le n\sqrt{\frac{n}{n+1}}$ for $n\ge1$

I need to prove Prove the inequality $$ \Bigg(\sum^{n}_{k=1}\sqrt{\frac{k-\sqrt{k^{2}-1}}{\sqrt{k(k+1)}}}\Bigg)^{2} \le n\sqrt{\frac{n}{n+1}}, $$ where $n$ is a positive integer. Equivalently $$\...
Guy Fsone's user avatar
  • 24.2k
1 vote
1 answer
40 views

simple sum inequality

I have an inequality for sums that I can't proof, although I know it is true. Let $h_{ij} = h_{ji}$ a real $n\times n$ matrix, and $h_{ijk} = - h_{ikj}$ a real $n\times n\times n$ tensor with $$\sum_{...
cesare borgia's user avatar
0 votes
1 answer
52 views

Smallest Sum of products, under cyclic permutations

Let $a_i$ be real positive numbers, $i=0, \dots, N-1$, with $N$ even. Define sums $S_k = \sum_{i=0}^{N-1} a_i a_{i+k}$, for $k=0, \dots, N-1$, where the indices are understood to be cyclic, i.e. $...
Andreas's user avatar
  • 15.8k
0 votes
2 answers
92 views

Find the maximize of $\sum_{cyc}\frac{1}{x^2+y^2+1}$

Let $x>0$, $y>0$ and $z>0$ such that $xy+yz+xz=3$. Find a maximize of $$P=\frac{1}{x^2+y^2+1}+\frac{1}{y^2+z^2+1}+\frac{1}{z^2+x^2+1}$$ We need to prove $P\le 1$ with $x=y=z=1$ We have: $$\...
Word Shallow's user avatar
  • 1,898
2 votes
6 answers
1k views

Showing that $S=\frac{1}{100} + \frac{1}{101} + \dots + \frac{1}{1000} \gt 1$

If $$S=\frac{1}{100} + \frac{1}{101} + \dots + \frac{1}{1000}$$ then $$S\gt 1,$$ but how? I understood that there are $451$ pair of terms. So clubbed two terms together. $\frac{1}{100}+\frac{1}{...
EmilySekuz's user avatar
3 votes
2 answers
196 views

Inequality $\frac{1}{a+b}+\frac{1}{a+2b}+...+\frac{1}{a+nb}<\frac{n}{\sqrt{a\left( a+nb \right)}}$

Let $a,b\in \mathbb{R+}$ and $n\in \mathbb{N}$. Prove that: $$\frac{1}{a+b}+\frac{1}{a+2b}+...+\frac{1}{a+nb}<\frac{n}{\sqrt{a\left( a+nb \right)}}$$ I have a solution using induction, but ...
whitexlotus's user avatar
3 votes
1 answer
106 views

Inequality $\frac{x_1^2}{x_1^2+x_2x_3}+\frac{x_2^2}{x_2^2+x_3x_4}+\cdots+\frac{x_{n-1}^2}{x_{n-1}^2+x_nx_1}+\frac{x_n^2}{x_n^2+x_1x_2}\le n-1$

Show that for all $n\ge 2$ $$\frac{x_1^2}{x_1^2+x_2x_3}+\frac{x_2^2}{x_2^2+x_3x_4}+\cdots+\frac{x_{n-1}^2}{x_{n-1}^2+x_nx_1}+\frac{x_n^2}{x_n^2+x_1x_2}\le n-1$$ where $x_i$ are real positive ...
whitexlotus's user avatar

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