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25 questions with no upvoted or accepted answers
7 votes
0 answers
194 views

The closed-form of $1-5\left(\frac{1}{2}\right)^k+9\left(\frac{1\cdot3}{2\cdot4}\right)^k-13\left(\frac{1\cdot3\cdot5}{2\cdot4\cdot6}\right)^k+\dots$?

(A related MSE question by P. Singh.) First define, $$F_k = 1-5\left(\frac{1}{2}\right)^k+9\left(\frac{1\cdot 3}{2\cdot 4}\right)^k-13\left(\frac{1\cdot 3\cdot 5}{2\cdot 4\cdot 6}\right)^k+17\left(\...
Tito Piezas III's user avatar
4 votes
0 answers
96 views

Evaluate $\sum_{n=0}^{\infty} \frac{(a)_n (b)_n}{(2b)_n} \frac{\psi^{(0)}\left (n+ \frac{a}2+1 \right ) }{\Gamma\left (n+ \frac{a}2+1 \right ) }$

Define $$S(a,b)=\sum_{n=0}^{\infty} \frac{(a)_n (b)_n}{(2b)_n} \frac{\psi^{(0)}\left (n+ \frac{a}2+1 \right ) }{\Gamma\left (n+ \frac{a}2+1 \right ) },$$ where $\psi^{(0)}(x)=\frac{\Gamma^\prime(x)}{\...
Setness Ramesory's user avatar
4 votes
0 answers
281 views

Non-recursive closed-form of the coefficients of Taylor series of the reciprocal gamma function

The reciprocal gamma function has the following Taylor series. $$\frac{1}{\Gamma(z)}=\sum_{k=1}^{\infty}a_kz^k,$$ where the $a_k$ coefficient are given by the followint recursion. $a_1=1$, $a_2=\...
user153012's user avatar
  • 12.4k
3 votes
0 answers
53 views

Find $\prod_{k=1}^n \frac{\Gamma (a_k/m)}{\Gamma (b_k/m)}$ algorithmically

It sometimes happens that $$\prod_{k=1}^n \frac{\Gamma (a_k/m)}{\Gamma (b_k/m)}$$ is algebraic for positive integers $m,n,a_k,b_k$. For example, $$\frac{\Gamma\left(\frac{1}{24}\right)\Gamma\left(\...
Nomas2's user avatar
  • 667
3 votes
0 answers
173 views

Question on a closed-form expression related to the harmonic number $H_n$

In this question the notation $\tilde{f}(x)$ refers to an analytic representation of the summatory function $$f(x)=\sum\limits_{n=1}^x a(n)\tag{1}$$ that converges to $$\underset{\epsilon\to 0}{\text{...
Steven Clark's user avatar
  • 7,631
3 votes
0 answers
84 views

Closed form for infinite series $\sum_{n=1}^\infty \prod_{j=1}^n \left[1-(\tfrac{j}{n}u+v)^2\right]^{-1} x^n$

I've been struggling to find a closed form for the following series that depends on $u$ and $v$ as parameters: $$ f(u,v,x) = \sum_{n=1}^\infty c_n x^n $$ with $$ c_n = \frac{1}{\prod_{j=1}^n \left[...
wcw's user avatar
  • 207
3 votes
0 answers
134 views

Is there a known transformation between $_2F_1\big(\tfrac12,\tfrac12;1;z\big)$ and $_2F_1\big(\tfrac12,\tfrac12;1;z^2\big)$?

In this post, the OP seeks a closed-form for, $$A=\,_2F_1\big(\tfrac12,\tfrac12;1;\tfrac19\big)=1.02966\dots$$ Using the transformation, $$\,_2F_1\big(\tfrac12,\tfrac12;1;z\big) = \tfrac2{1+\sqrt{1-z}}...
Tito Piezas III's user avatar
3 votes
0 answers
160 views

Two complementary continued fractions that are algebraic numbers

Define the two similar continued fractions, $$x=\cfrac{1}{km\color{blue}+\cfrac{(m-1)(m+1)} {3km\color{blue}+\cfrac{(2m-1)(2m+1)}{5km\color{blue}+\cfrac{(3m-1)(3m+1)}{7km\color{blue}+\ddots}}}}\tag1$$...
Tito Piezas III's user avatar
3 votes
0 answers
124 views

Closed form of specific series

I'm working on a problem that involves the integrals of various Bessel functions that Mathematica can't symbolically handle. I've managed to grind out the transformations and integrals by hand, and ...
logosintegralis's user avatar
2 votes
0 answers
52 views

How to define double factorial for non positive integers?

I studied double factorial which known for natural number $$ n!!=n(n-2)!! , 1!!=0!!=1$$ So we have for $n\in N$ $$ (2n)!!=2^n n! , (2n+1)!!=\frac{(2n+1)!}{2^n n!}$$ but I found on Math-World formula ...
Faoler's user avatar
  • 1,637
2 votes
0 answers
238 views

Showing $\int_{0}^{1}\frac{E(\tfrac{x}{\sqrt{x^2+8}})}{\sqrt{8-7x^2-x^4}}dx=\frac{1}{3}K(\frac{1}{\sqrt{2}})E(\frac{1}{\sqrt{2}})$

Context $\begin{align} K(k)=\int_{0}^{\pi/2}\frac{dt}{\sqrt{1-k^2\sin^2t}}\tag{1} \end{align}$ and $\begin{align} E(k)=\int_{0}^{\pi/2}\sqrt{1-k^2\sin^2t}dt\tag{2} \end{align}$ the complete elliptic ...
User's user avatar
  • 323
2 votes
0 answers
238 views

Closed form expression for a sum

I want to calculate a sum of the form $$\sum_{k=0}^m \frac{\Gamma[m+1+\alpha-k]^2}{\Gamma[m+1-k]^2}\frac{\Gamma[x+k]}{\Gamma[x]k!}$$ where $m>0$ and belongs to integers and $\alpha$ takes half ...
user50183's user avatar
1 vote
0 answers
52 views

Does the rest of this family of continued fractions have closed forms?

The pattern for the continued fractions below is quite straightforward. $F_1$ has numerators with all the integers but, $F_2\; \text{is missing}\; 2m+1 = 3,5,7,\dots\\ F_3\; \text{is missing}\; 3m+1 = ...
Tito Piezas III's user avatar
1 vote
0 answers
43 views

Computing $\frac{d^{n-1}}{dz^{n-1}}\frac{z}{\ln\left(z!\right)}^{n}$

I am trying to compute $$\frac{d^{n-1}}{dz^{n-1}}\left(\frac{z}{\ln\left(z!\right)}\right)^{n}$$ The problem arises when dealing with inversion formulae. My question is, can this expression be ...
user2549157's user avatar
1 vote
0 answers
95 views

Is there a closed form for the binomial expression $\binom{-1/m}{k} $?

I'm interested in binomial coefficients of the form $$\binom{-1/m}{k} ,$$ where $m$ is a positive integer. For $m=2$, it holds that \begin{align} \binom{-1/2}{k} &= (-4)^{-k} \binom{2k}{k} \qquad ...
Max Muller's user avatar
  • 7,148

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