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2 votes
0 answers
52 views

How to define double factorial for non positive integers?

I studied double factorial which known for natural number $$ n!!=n(n-2)!! , 1!!=0!!=1$$ So we have for $n\in N$ $$ (2n)!!=2^n n! , (2n+1)!!=\frac{(2n+1)!}{2^n n!}$$ but I found on Math-World formula ...
Faoler's user avatar
  • 1,637
5 votes
1 answer
231 views

Closed form for $\Gamma(a-x)$ where $a \in (0,1]$.

Now asked on MO here. I wonder if there is a closed form for $ \Gamma(a-x)$. And by closed form here I mean a finite combinations of elementary functions, powers of $\Gamma(a)$ and powers of $\Gamma(...
pie's user avatar
  • 6,620
3 votes
0 answers
53 views

Find $\prod_{k=1}^n \frac{\Gamma (a_k/m)}{\Gamma (b_k/m)}$ algorithmically

It sometimes happens that $$\prod_{k=1}^n \frac{\Gamma (a_k/m)}{\Gamma (b_k/m)}$$ is algebraic for positive integers $m,n,a_k,b_k$. For example, $$\frac{\Gamma\left(\frac{1}{24}\right)\Gamma\left(\...
Nomas2's user avatar
  • 667
4 votes
0 answers
96 views

Evaluate $\sum_{n=0}^{\infty} \frac{(a)_n (b)_n}{(2b)_n} \frac{\psi^{(0)}\left (n+ \frac{a}2+1 \right ) }{\Gamma\left (n+ \frac{a}2+1 \right ) }$

Define $$S(a,b)=\sum_{n=0}^{\infty} \frac{(a)_n (b)_n}{(2b)_n} \frac{\psi^{(0)}\left (n+ \frac{a}2+1 \right ) }{\Gamma\left (n+ \frac{a}2+1 \right ) },$$ where $\psi^{(0)}(x)=\frac{\Gamma^\prime(x)}{\...
Setness Ramesory's user avatar
48 votes
1 answer
1k views

How to evaluate double limit of multifactorial $\lim\limits_{k\to\infty}\lim\limits_{n\to 0} \sqrt[n]{n\underbrace{!!!!\cdots!}_{k\,\text{times}}}$

Define the multifactorial function $$n!^{(k)}=n(n-k)(n-2k)\cdots$$ where the product extends to the least positive integer of $n$ modulo $k$. In this answer, I derived one of several analytic ...
TheSimpliFire's user avatar
  • 27.1k
2 votes
1 answer
76 views

How to compute: $I_x =\int_0^1 t^x e^{-\frac{1}{1-t^2}} dt~~~x>0$?

$$I_x =\int_0^1 t^x e^{-\frac{1}{1-t^2}} dt~~~x>0$$ I first tried to see if I could solve the integer case. $$I_n =\int_0^1 t^ne^{-\frac{1}{1-t^2}} dt $$ I have tried to find a possible ...
Guy Fsone's user avatar
  • 24.2k