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2 votes
0 answers
52 views

How to define double factorial for non positive integers?

I studied double factorial which known for natural number $$ n!!=n(n-2)!! , 1!!=0!!=1$$ So we have for $n\in N$ $$ (2n)!!=2^n n! , (2n+1)!!=\frac{(2n+1)!}{2^n n!}$$ but I found on Math-World formula ...
Faoler's user avatar
  • 1,637
5 votes
1 answer
231 views

Closed form for $\Gamma(a-x)$ where $a \in (0,1]$.

Now asked on MO here. I wonder if there is a closed form for $ \Gamma(a-x)$. And by closed form here I mean a finite combinations of elementary functions, powers of $\Gamma(a)$ and powers of $\Gamma(...
pie's user avatar
  • 6,620
0 votes
0 answers
74 views

Is it possible to find a closed form for $i!$? [duplicate]

I am curious is there a closed form for $i!$? I tried to search for any closed form for this but I didn't find any. $$z! := \lim_{n \to \infty } n^z \prod_{k=1}^n \frac {k}{z+k}$$ $$i! =\lim_{n \to \...
Mathematics enjoyer's user avatar
1 vote
0 answers
43 views

Computing $\frac{d^{n-1}}{dz^{n-1}}\frac{z}{\ln\left(z!\right)}^{n}$

I am trying to compute $$\frac{d^{n-1}}{dz^{n-1}}\left(\frac{z}{\ln\left(z!\right)}\right)^{n}$$ The problem arises when dealing with inversion formulae. My question is, can this expression be ...
user2549157's user avatar
1 vote
1 answer
123 views

Proof about the power series of reciprocal multifactorials $m_x(k)=\sum_{n=0}^\infty \frac{x^n}{n\underbrace{!\cdots!}_{\text{k times}}}$

The proof I've attempted mimics very closely the answer on this question. How to prove the formula for the Reciprocal Multifactorial constant? Pre-requisite definitions: A multifactorial of order $k \...
Bhoris Dhanjal's user avatar
48 votes
1 answer
1k views

How to evaluate double limit of multifactorial $\lim\limits_{k\to\infty}\lim\limits_{n\to 0} \sqrt[n]{n\underbrace{!!!!\cdots!}_{k\,\text{times}}}$

Define the multifactorial function $$n!^{(k)}=n(n-k)(n-2k)\cdots$$ where the product extends to the least positive integer of $n$ modulo $k$. In this answer, I derived one of several analytic ...
TheSimpliFire's user avatar
  • 27.1k
1 vote
1 answer
45 views

Expressing the coefficients of $(1-x)^{1/4}$ using factorials

From the fact that $1\times3\times5\times\ldots\times(2n-1)=\frac{(2n)!}{2^nn!}$, we can show that $$ (1-x)^{1/2}=\sum_{n=0}^\infty \frac{(2n-2)!}{(n-1)!n!2^{2n+1}}x^n. $$ However, can I do the same ...
Ma Joad's user avatar
  • 7,534
2 votes
3 answers
130 views

Does this function have a closed form?

$$k_a(x)=\sum^\infty_{n=0}{\frac{n^2}{(n+x)!}}$$ $$k_b(x)=\sum^\infty_{n=0}{\frac{(n+x)^2}{n!}}$$ I noticed these functions closely relate to $e$. By looking at them I was able to determain a closed ...
Graviton's user avatar
  • 4,472
2 votes
1 answer
232 views

Approximation of the factorial function

I'm using the term factorial function as $\gamma(x+1)$ on the sense that I'm taking all real number in count. I have seen many approximations of the factorial function for positive values, for ...
Sam's user avatar
  • 5,166
2 votes
2 answers
163 views

Equations involving factorial/Gamma function

Are there any known methods to formally solve equations like: 1)$x^3!+(2x^2)!-x!+3=0$ 2)$x!=e^x$ ($0$ is trivial but there must be another one) 3)$(2x!)^2+x!-1=0$ 4)$x!!+x!=7$ I don't need ...
AlienRem's user avatar
  • 4,099
4 votes
1 answer
182 views

Product identity for $n^n$

I came across the rather nice identity \begin{align} &&\frac{(-n)^{n-1} \Gamma (n+1)}{(1-n)_{n-1}}&&\tag{1}&\\ \\ &=&\prod _{k=1}^{n-1} \frac{(k+1) n^2}{n^2-k n}&&\...
martin's user avatar
  • 9,018